是否有一种方法显示所有枚举作为他们的字符串值在swagger而不是他们的int值?
我希望能够提交POST动作,并根据它们的字符串值放置枚举,而不必每次都查看enum。
我尝试了DescribeAllEnumsAsStrings,但服务器然后接收字符串而不是enum值,这不是我们要寻找的。
有人解决了吗?
编辑:
public class Letter
{
[Required]
public string Content {get; set;}
[Required]
[EnumDataType(typeof(Priority))]
public Priority Priority {get; set;}
}
public class LettersController : ApiController
{
[HttpPost]
public IHttpActionResult SendLetter(Letter letter)
{
// Validation not passing when using DescribeEnumsAsStrings
if (!ModelState.IsValid)
return BadRequest("Not valid")
..
}
// In the documentation for this request I want to see the string values of the enum before submitting: Low, Medium, High. Instead of 0, 1, 2
[HttpGet]
public IHttpActionResult GetByPriority (Priority priority)
{
}
}
public enum Priority
{
Low,
Medium,
High
}
要在swagger中以字符串形式显示枚举,请在ConfigureServices中添加以下行来配置JsonStringEnumConverter:
services.AddControllers().AddJsonOptions(options =>
options.JsonSerializerOptions.Converters.Add(new JsonStringEnumConverter()));
如果你想以字符串和int值的形式显示枚举,你可以尝试创建一个EnumSchemaFilter来改变模式,如下所示:
public class EnumSchemaFilter : ISchemaFilter
{
public void Apply(OpenApiSchema model, SchemaFilterContext context)
{
if (context.Type.IsEnum)
{
model.Enum.Clear();
Enum.GetNames(context.Type)
.ToList()
.ForEach(name => model.Enum.Add(new OpenApiString($"{Convert.ToInt64(Enum.Parse(context.Type, name))} = {name}")));
}
}
}
配置SwaggerGen使用上面的SchemaFilter:
services.AddSwaggerGen(c =>
{
c.SwaggerDoc("v1", new OpenApiInfo
{
Version = "v1",
Title = "ToDo API",
Description = "A simple example ASP.NET Core Web API",
TermsOfService = new Uri("https://example.com/terms"),
Contact = new OpenApiContact
{
Name = "Shayne Boyer",
Email = string.Empty,
Url = new Uri("https://twitter.com/spboyer"),
},
License = new OpenApiLicense
{
Name = "Use under LICX",
Url = new Uri("https://example.com/license"),
}
});
c.SchemaFilter<EnumSchemaFilter>();
});
asp.net core 3
using System.Text.Json.Serialization;
public class Startup
{
public void ConfigureServices(IServiceCollection services)
{
services.AddControllers().AddJsonOptions(options =>
options.JsonSerializerOptions.Converters.Add(new JsonStringEnumConverter()));
但是Swashbuckle Version 5.0.0-rc4似乎还没有准备好支持这个功能。所以我们需要在Swashbuckle配置文件中使用一个选项(已弃用),直到它像Newtonsoft库一样支持和反映它。
public void ConfigureServices(IServiceCollection services)
{
services.AddSwaggerGen(c =>
{
c.DescribeAllEnumsAsStrings();
这个答案和其他答案之间的区别是只使用Microsoft JSON库而不是Newtonsoft。
为了生成有名称和值的枚举,可以使用此解决方案。
先决条件:
你正在使用NSwag或Openapi-generator来生成API客户端
你有一个旧的Web Api项目(pre . net Core)并使用Swashbuckle。WebApi包
SchemaFilter登记:
GlobalConfiguration.Configuration
.EnableSwagger("/swagger", c =>
{
c.SchemaFilter<EnumSchemaFilter>();
});
EnumSchemaFilter:
public class EnumSchemaFilter : ISchemaFilter
{
public void Apply(Schema schema, SchemaRegistry schemaRegistry, Type type)
{
var enumProperties = schema.properties?.Where(p => p.Value.@enum != null);
if(enumProperties != null)
{
foreach (var property in enumProperties)
{
var array = Enum.GetNames(type.GetProperty(property.Key).PropertyType).ToArray();
property.Value.vendorExtensions.Add("x-enumNames", array); // NSwag
property.Value.vendorExtensions.Add("x-enum-varnames", array); // Openapi-generator
}
}
}
}