我想根据谓词筛选java.util.Collection。


当前回答

使用来自Apache Commons的CollectionUtils.filter(Collection,Predicate)。

其他回答

JFilter http://code.google.com/p/jfilter/最适合您的需求。

JFilter是一个简单、高性能的开源库,用于查询Java bean集合。

关键特性

Support of collection (java.util.Collection, java.util.Map and Array) properties. Support of collection inside collection of any depth. Support of inner queries. Support of parameterized queries. Can filter 1 million records in few 100 ms. Filter ( query) is given in simple json format, it is like Mangodb queries. Following are some examples. { "id":{"$le":"10"} where object id property is less than equals to 10. { "id": {"$in":["0", "100"]}} where object id property is 0 or 100. {"lineItems":{"lineAmount":"1"}} where lineItems collection property of parameterized type has lineAmount equals to 1. { "$and":[{"id": "0"}, {"billingAddress":{"city":"DEL"}}]} where id property is 0 and billingAddress.city property is DEL. {"lineItems":{"taxes":{ "key":{"code":"GST"}, "value":{"$gt": "1.01"}}}} where lineItems collection property of parameterized type which has taxes map type property of parameteriszed type has code equals to GST value greater than 1.01. {'$or':[{'code':'10'},{'skus': {'$and':[{'price':{'$in':['20', '40']}}, {'code':'RedApple'}]}}]} Select all products where product code is 10 or sku price in 20 and 40 and sku code is "RedApple".

从java 9开始收集。启用过滤:

public static <T, A, R>
    Collector<T, ?, R> filtering(Predicate<? super T> predicate,
                                 Collector<? super T, A, R> downstream)

因此过滤应该是:

collection.stream().collect(Collectors.filtering(predicate, collector))

例子:

List<Integer> oddNumbers = List.of(1, 19, 15, 10, -10).stream()
            .collect(Collectors.filtering(i -> i % 2 == 1, Collectors.toList()));

使用来自Apache Commons的CollectionUtils.filter(Collection,Predicate)。

“最好”这个要求太宽泛了。它是“最短的”吗?“最快”?“可读”? 过滤器的地方或到另一个集合?

最简单(但不是最易读)的方法是迭代它,并使用Iterator.remove()方法:

Iterator<Foo> it = col.iterator();
while( it.hasNext() ) {
  Foo foo = it.next();
  if( !condition(foo) ) it.remove();
}

现在,为了使其更具可读性,可以将其包装到实用程序方法中。然后发明一个IPredicate接口,创建该接口的匿名实现,并执行如下操作:

CollectionUtils.filterInPlace(col,
  new IPredicate<Foo>(){
    public boolean keepIt(Foo foo) {
      return foo.isBar();
    }
  });

where filterInPlace()迭代集合并调用Predicate.keepIt()来了解实例是否保留在集合中。

我真的没有看到为这项任务引入第三方库的正当理由。

从Java 8的早期发行版开始,你可以尝试这样做:

Collection<T> collection = ...;
Stream<T> stream = collection.stream().filter(...);

例如,如果你有一个整数列表,你想过滤> 10的数字,然后将这些数字打印到控制台,你可以这样做:

List<Integer> numbers = Arrays.asList(12, 74, 5, 8, 16);
numbers.stream().filter(n -> n > 10).forEach(System.out::println);