我知道下面是不可能的,因为枚举的类型必须是int

enum GroupTypes
{
    TheGroup = "OEM",
    TheOtherGroup = "CMB"
}

从我的数据库中,我得到了一个不全面的代码字段(OEM和CMBs)。我想让这个字段成为一个枚举或其他可以理解的东西。因为如果目标是可读性,解决方案就应该简洁。

我还有其他选择吗?


当前回答

我做过类似的事情;

public enum BusinessUnits
{
    NEW_EQUIPMENT = 0,
    USED_EQUIPMENT = 1,
    RENTAL_EQUIPMENT = 2,
    PARTS = 3,
    SERVICE = 4,
    OPERATOR_TRAINING = 5
}

public class BusinessUnitService
{
    public static string StringBusinessUnits(BusinessUnits BU)
    {
        switch (BU)
        {
            case BusinessUnits.NEW_EQUIPMENT: return "NEW EQUIPMENT";
            case BusinessUnits.USED_EQUIPMENT: return "USED EQUIPMENT";
            case BusinessUnits.RENTAL_EQUIPMENT: return "RENTAL EQUIPMENT";
            case BusinessUnits.PARTS: return "PARTS";
            case BusinessUnits.SERVICE: return "SERVICE";
            case BusinessUnits.OPERATOR_TRAINING: return "OPERATOR TRAINING";
            default: return String.Empty;
        }
    }
}

用这个称呼它;

BusinessUnitService.StringBusinessUnits(BusinessUnits.PARTS)

其他回答

另一种处理这个问题的方法是,有一个枚举和一个字符串数组,将枚举值映射到字符串列表:

public enum GroupTypes
{
    TheGroup  = 0,
    TheOtherGroup 
}

string[] GroupTypesStr = {
    "OEM",
    "CMB"
};

你可以这样使用它:

Log.Write(GroupTypesStr[(int)GroupTypes.TheOtherGroup]);

它将提示CMB

优点:

简单干净的代码。 高性能(特别是与那些方法相比 使用类)

缺点:

易于混乱的列表时,编辑它,但这将是一个好的 短名单。

使用类。

编辑:更好的例子

class StarshipType
{
    private string _Name;
    private static List<StarshipType> _StarshipTypes = new List<StarshipType>();

    public static readonly StarshipType Ultralight = new StarshipType("Ultralight");
    public static readonly StarshipType Light = new StarshipType("Light");
    public static readonly StarshipType Mediumweight = new StarshipType("Mediumweight");
    public static readonly StarshipType Heavy = new StarshipType("Heavy");
    public static readonly StarshipType Superheavy = new StarshipType("Superheavy");

    public string Name
    {
        get { return _Name; }
        private set { _Name = value; }
    }

    public static IList<StarshipType> StarshipTypes
    {
        get { return _StarshipTypes; }
    }

    private StarshipType(string name, int systemRatio)
    {
        Name = name;
        _StarshipTypes.Add(this);
    }

    public static StarshipType Parse(string toParse)
    {
        foreach (StarshipType s in StarshipTypes)
        {
            if (toParse == s.Name)
                return s;
        }
        throw new FormatException("Could not parse string.");
    }
}

你也可以使用扩展模型:

public enum MyEnum
{
    [Description("String 1")]
    V1= 1,
    [Description("String 2")]
    V2= 2
} 

你的扩展类

public static class MyEnumExtensions
{
    public static string ToDescriptionString(this MyEnum val)
    {
        DescriptionAttribute[] attributes = (DescriptionAttribute[])val
           .GetType()
           .GetField(val.ToString())
           .GetCustomAttributes(typeof(DescriptionAttribute), false);
        return attributes.Length > 0 ? attributes[0].Description : string.Empty;
    }
} 

用法:

MyEnum myLocal = MyEnum.V1;
print(myLocal.ToDescriptionString());

在VS 2015中,你可以使用nameof

public class LogCategory
{
    public static string Trace;
    public static string Debug;
    public static string Info;
    public static string Warning;
    public static string Error;
}

用法:

Logger.Write("This is almost like an enum.", nameof(LogCategory.Info));

c#不支持枚举字符串,但在大多数情况下,您可以使用List或Dictionary来获得所需的效果。

打印通过/失败结果:

List<string> PassFail = new List<string> { "FAIL", "PASS" };
bool result = true;
Console.WriteLine("Test1: " + PassFail[result.GetHashCode()]);