是否有一种简单的方法可以打印file.txt的完整路径?
file.txt = /nfs/an/disks/jj/home/dir/file.txt
<命令>
dir> <command> file.txt
应该打印
/nfs/an/disks/jj/home/dir/file.txt
是否有一种简单的方法可以打印file.txt的完整路径?
file.txt = /nfs/an/disks/jj/home/dir/file.txt
<命令>
dir> <command> file.txt
应该打印
/nfs/an/disks/jj/home/dir/file.txt
当前回答
我知道这是一个老问题了,但在这里补充一下信息:
Linux命令,可用于查找命令文件的文件路径。
$ which ls
/bin/ls
这里有一些注意事项;请参见https://www.cyberciti.biz/faq/how-do-i-find-the-path-to-a-command-file/。
其他回答
这很天真,但是我必须使它与POSIX兼容。需要进入文件目录的cd权限。
#!/bin/sh
if [ ${#} = 0 ]; then
echo "Error: 0 args. need 1" >&2
exit 1
fi
if [ -d ${1} ]; then
# Directory
base=$( cd ${1}; echo ${PWD##*/} )
dir=$( cd ${1}; echo ${PWD%${base}} )
if [ ${dir} = / ]; then
parentPath=${dir}
else
parentPath=${dir%/}
fi
if [ -z ${base} ] || [ -z ${parentPath} ]; then
if [ -n ${1} ]; then
fullPath=$( cd ${1}; echo ${PWD} )
else
echo "Error: unsupported scenario 1" >&2
exit 1
fi
fi
elif [ ${1%/*} = ${1} ]; then
if [ -f ./${1} ]; then
# File in current directory
base=$( echo ${1##*/} )
parentPath=$( echo ${PWD} )
else
echo "Error: unsupported scenario 2" >&2
exit 1
fi
elif [ -f ${1} ] && [ -d ${1%/*} ]; then
# File in directory
base=$( echo ${1##*/} )
parentPath=$( cd ${1%/*}; echo ${PWD} )
else
echo "Error: not file or directory" >&2
exit 1
fi
if [ ${parentPath} = / ]; then
fullPath=${fullPath:-${parentPath}${base}}
fi
fullPath=${fullPath:-${parentPath}/${base}}
if [ ! -e ${fullPath} ]; then
echo "Error: does not exist" >&2
exit 1
fi
echo ${fullPath}
你可以把它保存在壳里。Rc或者直接放到控制台
function absolute_path { echo "$PWD/$1"; }
alias ap="absolute_path"
例子:
ap somefile.txt
将输出
/home/user/somefile.txt
这可以简化
ls <file_name> | pwd
在Mac OSX中,执行以下步骤:
CD到目标文件的目录。 输入下列任意一个终端命令。
Terminalls "`pwd`/file.txt"
echo $(pwd)/file.txt
用实际的文件名替换file.txt。 按回车键
创建一个如下所示的函数(使用pwd回显文件的绝对路径,并将文件添加到路径的末尾:
abspath() { echo $(pwd "$1")/"$1"; }
现在你可以找到任何文件路径:
abspath myfile.ext