如何在c#中将数值转换为Excel列名,而不使用直接从Excel中获取值的自动化。
Excel 2007的范围可能是1到16384,这是它支持的列数。结果值应以excel列名的形式出现,例如A、AA、AAA等。
如何在c#中将数值转换为Excel列名,而不使用直接从Excel中获取值的自动化。
Excel 2007的范围可能是1到16384,这是它支持的列数。结果值应以excel列名的形式出现,例如A、AA、AAA等。
当前回答
这是编程测试中常见的问题。 它有一些约束条件: 每行最大列数= 702 输出应该有行号+列名,例如703的答案是2A。 (注意:我只是从另一个答案修改了现有的代码) 下面是相同的代码:
static string GetExcelColumnName(long columnNumber)
{
//max number of column per row
const long maxColPerRow = 702;
//find row number
long rowNum = (columnNumber / maxColPerRow);
//find tierable columns in the row.
long dividend = columnNumber - (maxColPerRow * rowNum);
string columnName = String.Empty;
long modulo;
while (dividend > 0)
{
modulo = (dividend - 1) % 26;
columnName = Convert.ToChar(65 + modulo).ToString() + columnName;
dividend = (int)((dividend - modulo) / 26);
}
return rowNum+1+ columnName;
}
}
其他回答
我在我的第一篇文章中发现了一个错误,所以我决定坐下来算算。我发现用来识别Excel列的数字系统不是另一个人说的26进制系统。以10为基数考虑以下情况。你也可以用字母表中的字母来做这件事。
空间 :.........................S1, s2, s3: S1, s2, s3 ....................................0,00, 000:..A aa aaa ....................................1,01, 001:..B ab aab ....................................…,…,…:……,…,… ....................................9,99,999:..Z, zz, ZZZ 空间中的总状态:10,100,1000:26,676,17576 国家总 :............... 1110年 ................ 18278年
Excel在以26为基数的字母空格中对列进行编号。你可以看到,一般来说,状态空间的级数是a, a^2, a^3,…对于以a为底的情况,状态的总数是a + a^2 + a^3 + ... .
Suppose you want to find the total number of states A in the first N spaces. The formula for doing so is A = (a)(a^N - 1 )/(a-1). This is important because we need to find the space N that corresponds to our index K. If I want to find out where K lies in the number system I need to replace A with K and solve for N. The solution is N = log{base a} (A (a-1)/a +1). If I use the example of a = 10 and K = 192, I know that N = 2.23804… . This tells me that K lies at the beginning of the third space since it is a little greater than two.
The next step is to find exactly how far in the current space we are. To find this, subtract from K the A generated using the floor of N. In this example, the floor of N is two. So, A = (10)(10^2 – 1)/(10-1) = 110, as is expected when you combine the states of the first two spaces. This needs to be subtracted from K because these first 110 states would have already been accounted for in the first two spaces. This leaves us with 82 states. So, in this number system, the representation of 192 in base 10 is 082.
使用基本索引为0的c#代码是
private string ExcelColumnIndexToName(int Index)
{
string range = string.Empty;
if (Index < 0 ) return range;
int a = 26;
int x = (int)Math.Floor(Math.Log((Index) * (a - 1) / a + 1, a));
Index -= (int)(Math.Pow(a, x) - 1) * a / (a - 1);
for (int i = x+1; Index + i > 0; i--)
{
range = ((char)(65 + Index % a)).ToString() + range;
Index /= a;
}
return range;
}
/ /旧邮政
c#中的零基础解决方案。
private string ExcelColumnIndexToName(int Index)
{
string range = "";
if (Index < 0 ) return range;
for(int i=1;Index + i > 0;i=0)
{
range = ((char)(65 + Index % 26)).ToString() + range;
Index /= 26;
}
if (range.Length > 1) range = ((char)((int)range[0] - 1)).ToString() + range.Substring(1);
return range;
}
如果有人需要在没有VBA的Excel中做到这一点,这里有一种方法:
=SUBSTITUTE(ADDRESS(1;colNum;4);"1";"")
其中colNum是列号
在VBA中:
Function GetColumnName(colNum As Integer) As String
Dim d As Integer
Dim m As Integer
Dim name As String
d = colNum
name = ""
Do While (d > 0)
m = (d - 1) Mod 26
name = Chr(65 + m) + name
d = Int((d - m) / 26)
Loop
GetColumnName = name
End Function
前面的答案大部分是正确的。下面是将列号转换为excel列的另一种方法。 如果我们把它看作一个基转换,解就很简单了。简单地,将列号转换为以26为基数,因为只有26个字母。 你可以这样做:
步骤:
将列设置为商 从商变量中减去1(从上一步),因为我们需要以97为a的ASCII表结束。 除以26,得到余数。 在余数上加97并转换为字符(因为97在ASCII表中是a) 商变成了新的商/ 26(因为我们可能会越过26列) 继续这样做,直到商大于0,然后返回结果
下面是这样做的代码:)
def convert_num_to_column(column_num):
result = ""
quotient = column_num
remainder = 0
while (quotient >0):
quotient = quotient -1
remainder = quotient%26
result = chr(int(remainder)+97)+result
quotient = int(quotient/26)
return result
print("--",convert_num_to_column(1).upper())
巧合和优雅的Ruby版本:
def col_name(col_idx)
name = ""
while col_idx>0
mod = (col_idx-1)%26
name = (65+mod).chr + name
col_idx = ((col_idx-mod)/26).to_i
end
name
end
我正在尝试在Java中做同样的事情… 我写了以下代码:
private String getExcelColumnName(int columnNumber) {
int dividend = columnNumber;
String columnName = "";
int modulo;
while (dividend > 0)
{
modulo = (dividend - 1) % 26;
char val = Character.valueOf((char)(65 + modulo));
columnName += val;
dividend = (int)((dividend - modulo) / 26);
}
return columnName;
}
现在,一旦我用columnNumber = 29运行它,它给我的结果=“CA”(而不是“AC”) 有什么意见吗? 我知道我可以通过StringBuilder....反转它但看着格雷厄姆的回答,我有点困惑....