如果你想以实用的方式引用单元格，那么如果你使用工作表的Cells方法，你会得到更可读的代码。它接受行和列索引，而不是传统的单元格引用。它与Offset方法非常相似。

简单而简洁的JavaScript函数，将列号转换为电子表格列名。

function column(number) { const name = []; for(let n = number - 1; n >= 0; n = Math.floor(n / 26) - 1) { name.push(String.fromCharCode(65 + n % 26)); } return name.reverse().join(""); }; console.log(column(1), "A"); console.log(column(26), "Z"); console.log(column(27), "AA"); console.log(column(52), "AZ"); console.log(column(53), "BA"); console.log(column(702), "ZZ"); console.log(column(703), "AAA"); console.log(column(704), "AAB"); console.log(column(16384), "XFD");

 static string[] ExcelColumnAlphabetIdentifiers = new string[] { "", "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", 
     "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z" };
 public static string ExcelColumnAlphabetIdentifier( int ColumnNumber)
    {
        StringBuilder sb = new StringBuilder();
        int remainder = ColumnNumber;
        do
        {
            sb.Append(ExcelColumnAlphabetIdentifiers[remainder % 26]);
            remainder = remainder / 26;
        }
        while (remainder > 0);
       return sb.ToString();
    }

只是抛出一个简单的使用递归的两行c#实现，因为这里所有的答案似乎都比必要的复杂得多。

/// <summary>
/// Gets the column letter(s) corresponding to the given column number.
/// </summary>
/// <param name="column">The one-based column index. Must be greater than zero.</param>
/// <returns>The desired column letter, or an empty string if the column number was invalid.</returns>
public static string GetColumnLetter(int column) {
    if (column < 1) return String.Empty;
    return GetColumnLetter((column - 1) / 26) + (char)('A' + (column - 1) % 26);
}

在VB中使用这个。2005年净额:

Private Function ColumnName(ByVal ColumnIndex As Integer) As String

   Dim Name As String = ""

   Name = (New Microsoft.Office.Interop.Owc11.Spreadsheet).Columns.Item(ColumnIndex).Address(False, False, Microsoft.Office.Interop.Owc11.XlReferenceStyle.xlA1)
   Name = Split(Name, ":")(0)

   Return Name

End Function

JavaScript解决方案

/**
 * Calculate the column letter abbreviation from a 1 based index
 * @param {Number} value
 * @returns {string}
 */
getColumnFromIndex = function (value) {
    var base = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'.split('');
    var remainder, result = "";
    do {
        remainder = value % 26;
        result = base[(remainder || 26) - 1] + result;
        value = Math.floor(value / 26);
    } while (value > 0);
    return result;
};