我想在一些不同的条件下在linux shell中执行一些东西,并且能够输出每次执行的执行时间。
我知道我可以写一个perl或python脚本,可以做到这一点,但有一种方法我可以在shell中做到这一点吗?(恰好是bash)
我想在一些不同的条件下在linux shell中执行一些东西,并且能够输出每次执行的执行时间。
我知道我可以写一个perl或python脚本,可以做到这一点,但有一种方法我可以在shell中做到这一点吗?(恰好是bash)
当前回答
使用内置的time关键字:
$ help time time: time [-p] PIPELINE Execute PIPELINE and print a summary of the real time, user CPU time, and system CPU time spent executing PIPELINE when it terminates. The return status is the return status of PIPELINE. The `-p' option prints the timing summary in a slightly different format. This uses the value of the TIMEFORMAT variable as the output format.
例子:
$ time sleep 2
real 0m2.009s user 0m0.000s sys 0m0.004s
其他回答
使用内置的time关键字:
$ help time time: time [-p] PIPELINE Execute PIPELINE and print a summary of the real time, user CPU time, and system CPU time spent executing PIPELINE when it terminates. The return status is the return status of PIPELINE. The `-p' option prints the timing summary in a slightly different format. This uses the value of the TIMEFORMAT variable as the output format.
例子:
$ time sleep 2
real 0m2.009s user 0m0.000s sys 0m0.004s
您可以获得比bash内置时间(即time(1), Robert Gamble提到过)更详细的信息。通常这是/usr/bin/时间
编者按: 为了确保您调用的是外部实用程序time而不是shell的time关键字,请以/usr/bin/time来调用它 time是posix强制的实用程序,但它需要支持的唯一选项是-p。 特定的平台实现特定的、非标准的扩展:-v与GNU的time实用程序一起工作,如下所示(问题被标记为linux);BSD/macOS实现使用-l来产生类似的输出-参见man 1次。
详细输出示例:
$ /usr/bin/time -v sleep 1
Command being timed: "sleep 1"
User time (seconds): 0.00
System time (seconds): 0.00
Percent of CPU this job got: 1%
Elapsed (wall clock) time (h:mm:ss or m:ss): 0:01.05
Average shared text size (kbytes): 0
Average unshared data size (kbytes): 0
Average stack size (kbytes): 0
Average total size (kbytes): 0
Maximum resident set size (kbytes): 0
Average resident set size (kbytes): 0
Major (requiring I/O) page faults: 0
Minor (reclaiming a frame) page faults: 210
Voluntary context switches: 2
Involuntary context switches: 1
Swaps: 0
File system inputs: 0
File system outputs: 0
Socket messages sent: 0
Socket messages received: 0
Signals delivered: 0
Page size (bytes): 4096
Exit status: 0
如果您只需要精确到秒,您可以使用内置的$SECONDS变量,该变量计算shell已经运行的秒数。
while true; do
start=$SECONDS
some_long_running_command
duration=$(( SECONDS - start ))
echo "This run took $duration seconds"
if some_condition; then break; fi
done
如果您想要更精确,请使用%N和date(并使用bc作为diff,因为$(())只处理整数)。
以下是如何做到这一点:
start=$(date +%s.%N)
# do some stuff here
dur=$(echo "$(date +%s.%N) - $start" | bc)
printf "Execution time: %.6f seconds" $dur
例子:
start=$(date +%s.%N); \
sleep 0.1s; \
dur=$(echo "$(date +%s.%N) - $start" | bc); \
printf "Execution time: %.6f seconds\n" $dur
结果:
Execution time: 0.104623 seconds
如果您打算以后使用时间来计算,请学习如何使用/usr/bin/time的-f选项来输出节省时间的代码。下面是我最近使用的一些代码,用于获取和排序整个班级的学生程序的执行时间:
fmt="run { date = '$(date)', user = '$who', test = '$test', host = '$(hostname)', times = { user = %U, system = %S, elapsed = %e } }"
/usr/bin/time -f "$fmt" -o $timefile command args...
后来我将所有$timefile文件连接起来,并将输出输出到Lua解释器中。你可以用Python或bash或任何你喜欢的语法做同样的事情。我喜欢这个技巧。