单例模式确保只创建一个类的实例。我如何在达特建立这个?


当前回答

实例化后不能更改对象的单例

class User {
  final int age;
  final String name;
  
  User({
    this.name,
    this.age
    });
  
  static User _instance;
  
  static User getInstance({name, age}) {
     if(_instance == null) {
       _instance = User(name: name, age: age);
       return _instance;
     }
    return _instance;
  }
}

  print(User.getInstance(name: "baidu", age: 24).age); //24
  
  print(User.getInstance(name: "baidu 2").name); // is not changed //baidu

  print(User.getInstance()); // {name: "baidu": age 24}

其他回答

这是另一种可能的方式:

void main() {
  var s1 = Singleton.instance;
  s1.somedata = 123;
  var s2 = Singleton.instance;
  print(s2.somedata); // 123
  print(identical(s1, s2));  // true
  print(s1 == s2); // true
  //var s3 = new Singleton(); //produces a warning re missing default constructor and breaks on execution
}

class Singleton {
  static final Singleton _singleton = new Singleton._internal();
  Singleton._internal();
  static Singleton get instance => _singleton;
  var somedata;
}

这里有一个简单的答案:

类应具有其类型的私有和静态属性。 构造函数应该是私有的,以防止外部对象初始化。 检查实例是否为空,如果是,创建一个实例并返回,否则返回现有实例。

实现(延迟加载)

class Singleton {
  static Singleton? _instance;

  Singleton._();

  static Singleton get instance => _instance ??= Singleton._();

  void someMethod(){
    ...
  }

  ...
}

实现(急装)

class Singleton {
  static Singleton _instance = Singleton._();

  Singleton._();

  static Singleton get instance => _instance;

  void someMethod(){
    ...
  }

  ...
}

使用

Singleton.instance.someMethod();

这是我做单例的方式,接受参数(你可以直接粘贴到https://dartpad.dev/):

void main() {
  
  Logger x = Logger('asd');
  Logger y = Logger('xyz');
  
  x.display('Hello');
  y.display('Hello There');
}


class Logger{
  
  
  Logger._(this.message);
  final String message;
  static Logger _instance = Logger._('??!?*');
  factory Logger(String message){
    if(_instance.message=='??!?*'){
      _instance = Logger._(message);
    }
    return _instance;
  }
  
  void display(String prefix){
    print(prefix+' '+message);
  }
  
}

输入:

Hello asd
Hello There asd

“? ? ! ?*'你看到的只是一个工作区,我做了初始化_instance变量暂时没有使它成为一个Logger?类型(空安全)。

这应该有用。

class GlobalStore {
    static GlobalStore _instance;
    static GlobalStore get instance {
       if(_instance == null)
           _instance = new GlobalStore()._();
       return _instance;
    }

    _(){

    }
    factory GlobalStore()=> instance;


}

实例化后不能更改对象的单例

class User {
  final int age;
  final String name;
  
  User({
    this.name,
    this.age
    });
  
  static User _instance;
  
  static User getInstance({name, age}) {
     if(_instance == null) {
       _instance = User(name: name, age: age);
       return _instance;
     }
    return _instance;
  }
}

  print(User.getInstance(name: "baidu", age: 24).age); //24
  
  print(User.getInstance(name: "baidu 2").name); // is not changed //baidu

  print(User.getInstance()); // {name: "baidu": age 24}