单例模式确保只创建一个类的实例。我如何在达特建立这个?
当前回答
这应该有用。
class GlobalStore {
static GlobalStore _instance;
static GlobalStore get instance {
if(_instance == null)
_instance = new GlobalStore()._();
return _instance;
}
_(){
}
factory GlobalStore()=> instance;
}
其他回答
这就是我如何在我的项目中实现单例
灵感来自flutter firebase => FirebaseFirestore.instance.collection('collectionName')
class FooAPI {
foo() {
// some async func to api
}
}
class SingletonService {
FooAPI _fooAPI;
static final SingletonService _instance = SingletonService._internal();
static SingletonService instance = SingletonService();
factory SingletonService() {
return _instance;
}
SingletonService._internal() {
// TODO: add init logic if needed
// FOR EXAMPLE API parameters
}
void foo() async {
await _fooAPI.foo();
}
}
void main(){
SingletonService.instance.foo();
}
来自我的项目的例子
class FirebaseLessonRepository implements LessonRepository {
FirebaseLessonRepository._internal();
static final _instance = FirebaseLessonRepository._internal();
static final instance = FirebaseLessonRepository();
factory FirebaseLessonRepository() => _instance;
var lessonsCollection = fb.firestore().collection('lessons');
// ... other code for crud etc ...
}
// then in my widgets
FirebaseLessonRepository.instance.someMethod(someParams);
你可以只使用Constant构造函数。
class Singleton {
const Singleton(); //Constant constructor
void hello() { print('Hello world'); }
}
例子:
Singleton s = const Singleton();
s.hello(); //Hello world
根据文件:
恒定的构造函数 如果类生成永不更改的对象,则可以使这些对象成为编译时常量。为此,定义一个const构造函数,并确保所有实例变量都是final变量。
这是另一种可能的方式:
void main() {
var s1 = Singleton.instance;
s1.somedata = 123;
var s2 = Singleton.instance;
print(s2.somedata); // 123
print(identical(s1, s2)); // true
print(s1 == s2); // true
//var s3 = new Singleton(); //produces a warning re missing default constructor and breaks on execution
}
class Singleton {
static final Singleton _singleton = new Singleton._internal();
Singleton._internal();
static Singleton get instance => _singleton;
var somedata;
}
你好,这样的东西怎么样?非常简单的实现,Injector本身是单例的,并且还添加了类。当然可以很容易地扩展。如果您正在寻找更复杂的东西,请检查这个包:https://pub.dartlang.org/packages/flutter_simple_dependency_injection
void main() {
Injector injector = Injector();
injector.add(() => Person('Filip'));
injector.add(() => City('New York'));
Person person = injector.get<Person>();
City city = injector.get<City>();
print(person.name);
print(city.name);
}
class Person {
String name;
Person(this.name);
}
class City {
String name;
City(this.name);
}
typedef T CreateInstanceFn<T>();
class Injector {
static final Injector _singleton = Injector._internal();
final _factories = Map<String, dynamic>();
factory Injector() {
return _singleton;
}
Injector._internal();
String _generateKey<T>(T type) {
return '${type.toString()}_instance';
}
void add<T>(CreateInstanceFn<T> createInstance) {
final typeKey = _generateKey(T);
_factories[typeKey] = createInstance();
}
T get<T>() {
final typeKey = _generateKey(T);
T instance = _factories[typeKey];
if (instance == null) {
print('Cannot find instance for type $typeKey');
}
return instance;
}
}
因为我不太喜欢使用new关键字或其他构造函数,比如对单例对象的调用,我更喜欢使用一个名为inst的静态getter:
// the singleton class
class Dao {
// singleton boilerplate
Dao._internal() {}
static final Dao _singleton = new Dao._internal();
static get inst => _singleton;
// business logic
void greet() => print("Hello from singleton");
}
使用示例:
Dao.inst.greet(); // call a method
// Dao x = new Dao(); // compiler error: Method not found: 'Dao'
// verify that there only exists one and only one instance
assert(identical(Dao.inst, Dao.inst));