有一些简单的方法来填充字符串在Java?
似乎是一些应该在一些stringutil类API,但我找不到任何东西,这样做。
有一些简单的方法来填充字符串在Java?
似乎是一些应该在一些stringutil类API,但我找不到任何东西,这样做。
当前回答
这是一个高效的实用工具类,用于Java中的左填充,右填充,中心填充和零填充字符串。
package com.example;
/**
* Utility class for left pad, right pad, center pad and zero fill.
*/
public final class StringPadding {
public static String left(String string, int length, char fill) {
if (string.length() < length) {
char[] chars = string.toCharArray();
char[] output = new char[length];
int delta = length - chars.length;
for (int i = 0; i < length; i++) {
if (i < delta) {
output[i] = fill;
} else {
output[i] = chars[i - delta];
}
}
return new String(output);
}
return string;
}
public static String right(String string, int length, char fill) {
if (string.length() < length) {
char[] chars = string.toCharArray();
char[] output = new char[length];
for (int i = 0; i < length; i++) {
if (i < chars.length) {
output[i] = chars[i];
} else {
output[i] = fill;
}
}
return new String(output);
}
return string;
}
public static String center(String string, int length, char fill) {
if (string.length() < length) {
char[] chars = string.toCharArray();
int delta = length - chars.length;
int a = (delta % 2 == 0) ? delta / 2 : delta / 2 + 1;
int b = a + chars.length;
char[] output = new char[length];
for (int i = 0; i < length; i++) {
if (i < a) {
output[i] = fill;
} else if (i < b) {
output[i] = chars[i - a];
} else {
output[i] = fill;
}
}
return new String(output);
}
return string;
}
public static String zerofill(String string, int length) {
return left(string, length, '0');
}
private StringPadding() {
}
/**
* For tests!
*/
public static void main(String[] args) {
String string = "123";
char blank = ' ';
System.out.println("left pad: [" + StringPadding.left(string, 10, blank) + "]");
System.out.println("right pad: [" + StringPadding.right(string, 10, blank) + "]");
System.out.println("center pad: [" + StringPadding.center(string, 10, blank) + "]");
System.out.println("zero fill: [" + StringPadding.zerofill(string, 10) + "]");
}
}
输出如下:
left pad: [ 123]
right pad: [123 ]
center pad: [ 123 ]
zero fill: [0000000123]
其他回答
为此编写自己的函数可能比其他答案更简单。
private static String padRight(String str, String padChar, int n) {
String paddedString = str;
while (paddedString.length() < n) {
paddedString = padChar + str;
}
return paddedString;
}
private static String padLeft(String str, String padChar, int n) {
String paddedString = str;
while (paddedString.length() < n) {
paddedString += padChar;
}
return paddedString;
}
简单的东西:
该值应该是字符串。如果不是,就转换成字符串。比如"" + 123或Integer.toString(123)
// let's assume value holds the String we want to pad
String value = "123";
子字符串从值length char索引开始,直到填充的结束长度:
String padded="00000000".substring(value.length()) + value;
// now padded is "00000123"
更精确的
垫:
String padded = value + ("ABCDEFGH".substring(value.length()));
// now padded is "123DEFGH"
垫左:
String padString = "ABCDEFGH";
String padded = (padString.substring(0, padString.length() - value.length())) + value;
// now padded is "ABCDE123"
这里有一个并行版本的你有很长的字符串:-)
int width = 100;
String s = "129018";
CharSequence padded = IntStream.range(0,width)
.parallel()
.map(i->i-(width-s.length()))
.map(i->i<0 ? '0' :s.charAt(i))
.collect(StringBuilder::new, (sb,c)-> sb.append((char)c), (sb1,sb2)->sb1.append(sb2));
从Java 11开始,string. repeat(int)可以用来左右填充给定的字符串。
System.out.println("*".repeat(5)+"apple");
System.out.println("apple"+"*".repeat(5));
输出:
*****apple
apple*****
你可以使用内置的StringBuilder append()和insert()方法, 对于可变字符串长度的填充:
AbstractStringBuilder append(CharSequence s, int start, int end) ;
例如:
private static final String MAX_STRING = " "; //20 spaces
Set<StringBuilder> set= new HashSet<StringBuilder>();
set.add(new StringBuilder("12345678"));
set.add(new StringBuilder("123456789"));
set.add(new StringBuilder("1234567811"));
set.add(new StringBuilder("12345678123"));
set.add(new StringBuilder("1234567812234"));
set.add(new StringBuilder("1234567812222"));
set.add(new StringBuilder("12345678122334"));
for(StringBuilder padMe: set)
padMe.append(MAX_STRING, padMe.length(), MAX_STRING.length());