我的应用程序有一个特定的功能,只能在根可用的设备上工作。与其让这个特性在使用时失败(然后向用户显示适当的错误消息),我更希望能够先静默地检查根目录是否可用,如果不可用,则首先隐藏相应的选项。
有办法做到这一点吗?
我的应用程序有一个特定的功能,只能在根可用的设备上工作。与其让这个特性在使用时失败(然后向用户显示适当的错误消息),我更希望能够先静默地检查根目录是否可用,如果不可用,则首先隐藏相应的选项。
有办法做到这一点吗?
当前回答
在rootbox中使用我的库非常简单。检查所需的代码如下:
//Pass true to <Shell>.start(...) call to run as superuser
Shell shell = null;
try {
shell = Shell.start(true);
} catch (IOException exception) {
exception.printStackTrace();
}
if (shell == null)
// We failed to execute su binary
return;
if (shell.isRoot()) {
// Verified running as uid 0 (root), can continue with commands
...
} else
throw Exception("Unable to gain root access. Make sure you pressed Allow/Grant in superuser prompt.");
其他回答
如果你不想使用任何第三方库或任何随机解决方案,那么就使用谷歌库来检测它。
Android设备验证
回应:
{
"timestampMs": 9860437986543,
"nonce": "R2Rra24fVm5xa2Mg",
"apkPackageName": "com.package.name.of.requesting.app",
"apkCertificateDigestSha256": ["base64 encoded, SHA-256 hash of the
certificate used to sign requesting app"],
"ctsProfileMatch": true,
"basicIntegrity": true,
}
ctsprofilmatch如果设备已根,则给出false。
参考链接: [1]: https://developer.android.com/training/safetynet/attestation
if [[ "`adb shell which su | grep -io "permission denied"`" != "permission denied" ]]; then
echo "Yes. Rooted device."
else
echo "No. Device not rooted. Only limited tasks can be performed. Done."
zenity --warning --title="Device Not Rooted" --text="The connected Android Device is <b>NOT ROOTED</b>. Only limited tasks can be performed." --no-wrap
fi
RootTools库提供了简单的方法来检查根:
RootTools.isRootAvailable()
参考
除了@Kevins的回答之外,我最近在使用他的系统时发现,Nexus 7.1对所有三个方法都返回false——没有哪个命令,没有测试键,SuperSU没有安装在/system/app中。
我补充说:
public static boolean checkRootMethod4(Context context) {
return isPackageInstalled("eu.chainfire.supersu", context);
}
private static boolean isPackageInstalled(String packagename, Context context) {
PackageManager pm = context.getPackageManager();
try {
pm.getPackageInfo(packagename, PackageManager.GET_ACTIVITIES);
return true;
} catch (NameNotFoundException e) {
return false;
}
}
这在某些情况下有点不太有用(如果你需要保证root访问),因为SuperSU完全有可能安装在没有SU访问的设备上。
然而,由于SuperSU可以安装并工作,但不在/system/app目录下,这个额外的情况将会根除(哈哈)这样的情况。
public static boolean isRootAvailable(){
Process p = null;
try{
p = Runtime.getRuntime().exec(new String[] {"su"});
writeCommandToConsole(p,"exit 0");
int result = p.waitFor();
if(result != 0)
throw new Exception("Root check result with exit command " + result);
return true;
} catch (IOException e) {
Log.e(LOG_TAG, "Su executable is not available ", e);
} catch (Exception e) {
Log.e(LOG_TAG, "Root is unavailable ", e);
}finally {
if(p != null)
p.destroy();
}
return false;
}
private static String writeCommandToConsole(Process proc, String command, boolean ignoreError) throws Exception{
byte[] tmpArray = new byte[1024];
proc.getOutputStream().write((command + "\n").getBytes());
proc.getOutputStream().flush();
int bytesRead = 0;
if(proc.getErrorStream().available() > 0){
if((bytesRead = proc.getErrorStream().read(tmpArray)) > 1){
Log.e(LOG_TAG,new String(tmpArray,0,bytesRead));
if(!ignoreError)
throw new Exception(new String(tmpArray,0,bytesRead));
}
}
if(proc.getInputStream().available() > 0){
bytesRead = proc.getInputStream().read(tmpArray);
Log.i(LOG_TAG, new String(tmpArray,0,bytesRead));
}
return new String(tmpArray);
}