如何以12小时格式(AM/PM)显示JavaScript datetime对象?
当前回答
这是最简单的方法,你可以实现这使用三元操作符,或者你也可以使用if else代替!
const d = new Date();
let hrs = d.getHours();
let m = d.getMinutes();
// Condition to add zero before minute
let min = m < 10 ? `0${m}` : m;
const currTime = hrs >= 12 ? `${hrs - 12}:${min} pm` : `${hrs}:${min} am`;
console.log(currTime);
其他回答
您可以使用这段简单的代码来确定am或PM
var today=new Date();
var noon=new Date(today.getFullYear(),today.getMonth(),today.getDate(),12,0,0);
var ampm = (today.getTime()<noon.getTime())?'am':'pm';
如果你把时间设置为字符串,输入var myTime = "15:30" 然后您可以使用下面的代码来获取am pm。
var hour = parseInt(myTime.split(":")[0]) % 12;
var timeInAmPm = (hour == 0 ? "12": hour ) + ":" + myTime.split(":")[1] + " " + (parseInt(parseInt(myTime.split(":")[0]) / 12) < 1 ? "am" : "pm");
const formatAMPM = (date) => {
try {
let time = date.split(" ");
let hours = time[4].split(":")[0];
let minutes = time[4].split(":")[1];
hours = hours || 12;
const ampm = hours >= 12 ? " PM" : " AM";
minutes = minutes < 10 ? `${minutes}` : minutes;
hours %= 12;
const strTime = `${hours}:${minutes} ${ampm}`;
return strTime;
} catch (e) {
return "";
}
};
const startTime = "2021-12-07T17:00:00.073Z"
formatAMPM(new Date(startTime).toUTCString())
一个简短而甜蜜的实现:
// returns date object in 12hr (AM/PM) format
var formatAMPM = function formatAMPM(d) {
var h = d.getHours();
return (h % 12 || 12)
+ ':' + d.getMinutes().toString().padStart(2, '0')
+ ' ' + (h < 12 ? 'A' : 'P') + 'M';
};
使用Moment.js
使用moment.js时,请在JavaScript中使用以下代码
H, HH 24 hour time
h, or hh 12 hour time (use in conjunction with a or A)
format()方法以特定格式返回日期。
moment(new Date()).format("YYYY-MM-DD HH:mm"); // 24H clock
moment(new Date()).format("YYYY-MM-DD hh:mm A"); // 12H clock (AM/PM)
moment(new Date()).format("YYYY-MM-DD hh:mm a"); // 12H clock (am/pm)