您可以通过简单的一行代码来实现这一点。

如果你的foo.bar()操作是异步的:

await Assert.ThrowsExceptionAsync<Exception>(() => foo.bar());

如果foo.bar()不是异步的

Assert.ThrowsException<Exception>(() => foo.bar());

查看nUnit文档中的例子:

[ExpectedException( typeof( ArgumentException ) )]

好吧，我来总结一下大家之前说过的话…不管怎样，这是我根据好的答案构建的代码:)剩下要做的就是复制和使用…

/// <summary>
/// Checks to make sure that the input delegate throws a exception of type TException.
/// </summary>
/// <typeparam name="TException">The type of exception expected.</typeparam>
/// <param name="methodToExecute">The method to execute to generate the exception.</param>
public static void AssertRaises<TException>(Action methodToExecute) where TException : System.Exception
{
    try
    {
        methodToExecute();
    }
    catch (TException) {
        return;
    }  
    catch (System.Exception ex)
    {
        Assert.Fail("Expected exception of type " + typeof(TException) + " but type of " + ex.GetType() + " was thrown instead.");
    }
    Assert.Fail("Expected exception of type " + typeof(TException) + " but no exception was thrown.");  
}

在VS内置单元测试中，如果你只是想验证抛出了“任何异常”，但你不知道类型，你可以使用catch all:

[TestMethod]
[ExpectedException(typeof(Exception), AllowDerivedTypes = true)]
public void ThrowExceptionTest()
{
    //...
}

对于“Visual Studio Team Test”，似乎您将ExpectedException属性应用到测试的方法。

文档中的示例:使用Visual Studio团队测试的单元测试演练

[TestMethod]
[ExpectedException(typeof(ArgumentException),
    "A userId of null was inappropriately allowed.")]
public void NullUserIdInConstructor()
{
   LogonInfo logonInfo = new LogonInfo(null, "P@ss0word");
}

这是测试方法的一个属性…你不使用Assert。看起来是这样的:

[ExpectedException(typeof(ExceptionType))]
public void YourMethod_should_throw_exception()