是否有比较版本号的标准习语?我不能直接使用String compareTo,因为我还不知道点释放的最大数量是多少。我需要比较版本,并有以下保持正确:

1.0 < 1.1
1.0.1 < 1.1
1.9 < 1.10

当前回答

由于本页上没有答案能很好地处理混合文本,我做了自己的版本:

import java.util.regex.Matcher;
import java.util.regex.Pattern;

class Main {
    static double parseVersion(String v) {
        if (v.isEmpty()) {
            return 0;
        }
        Pattern p = Pattern.compile("^(\\D*)(\\d*)(\\D*)$");
        Matcher m = p.matcher(v);
        m.find();
        if (m.group(2).isEmpty()) {
            // v1.0.0.[preview]
            return -1;
        }
        double i = Integer.parseInt(m.group(2));
        if (!m.group(3).isEmpty()) {
            // v1.0.[0b]
            i -= 0.1;
        }
        return i;
    }

    public static int versionCompare(String str1, String str2) {
        String[] v1 = str1.split("\\.");
        String[] v2 = str2.split("\\.");
        int i = 0;
        for (; i < v1.length && i < v2.length; i++) {
            double iv1 = parseVersion(v1[i]);
            double iv2 = parseVersion(v2[i]);

            if (iv1 != iv2) {
                return iv1 - iv2 < 0 ? -1 : 1;
            }
        }
        if (i < v1.length) {
            // "1.0.1", "1.0"
            double iv1 = parseVersion(v1[i]);
            return iv1 < 0 ? -1 : (int) Math.ceil(iv1);
        }
        if (i < v2.length) {
            double iv2 = parseVersion(v2[i]);
            return -iv2 < 0 ? -1 : (int) Math.ceil(iv2);
        }
        return 0;
    }


    public static void main(String[] args) {
        System.out.println("versionCompare(v1.0.0, 1.0.0)");
        System.out.println(versionCompare("v1.0.0", "1.0.0")); // 0

        System.out.println("versionCompare(v1.0.0b, 1.0.0)");
        System.out.println(versionCompare("v1.0.0b", "1.0.0")); // -1

        System.out.println("versionCompare(v1.0.0.preview, 1.0.0)");
        System.out.println(versionCompare("v1.0.0.preview", "1.0.0")); // -1

        System.out.println("versionCompare(v1.0, 1.0.0)");
        System.out.println(versionCompare("v1.0", "1.0.0")); // 0

        System.out.println("versionCompare(ver1.0, 1.0.1)");
        System.out.println(versionCompare("ver1.0", "1.0.1")); // -1
    }
}

不过,在需要比较“alpha”和“beta”的情况下,它仍然不够。

其他回答

下面是一个优化的实现:

public static final Comparator<CharSequence> VERSION_ORDER = new Comparator<CharSequence>() {

  @Override
  public int compare (CharSequence lhs, CharSequence rhs) {
    int ll = lhs.length(), rl = rhs.length(), lv = 0, rv = 0, li = 0, ri = 0;
    char c;
    do {
      lv = rv = 0;
      while (--ll >= 0) {
        c = lhs.charAt(li++);
        if (c < '0' || c > '9')
          break;
        lv = lv*10 + c - '0';
      }
      while (--rl >= 0) {
        c = rhs.charAt(ri++);
        if (c < '0' || c > '9')
          break;
        rv = rv*10 + c - '0';
      }
    } while (lv == rv && (ll >= 0 || rl >= 0));
    return lv - rv;
  }

};

结果:

"0.1" - "1.0" = -1
"1.0" - "1.0" = 0
"1.0" - "1.0.0" = 0
"10" - "1.0" = 9
"3.7.6" - "3.7.11" = -5
"foobar" - "1.0" = -1

使用Maven真的很简单:

import org.apache.maven.artifact.versioning.DefaultArtifactVersion;

DefaultArtifactVersion minVersion = new DefaultArtifactVersion("1.0.1");
DefaultArtifactVersion maxVersion = new DefaultArtifactVersion("1.10");

DefaultArtifactVersion version = new DefaultArtifactVersion("1.11");

if (version.compareTo(minVersion) < 0 || version.compareTo(maxVersion) > 0) {
    System.out.println("Sorry, your version is unsupported");
}

您可以从这个页面获得Maven Artifact的正确依赖项字符串:

<dependency>
<groupId>org.apache.maven</groupId>
<artifactId>maven-artifact</artifactId>
<version>3.0.3</version>
</dependency>

此代码尝试解决这种类型的比较版本。

大多数版本说明符,如>= 1.0,都是不言自明的。的 说明符~>具有特殊含义,最好通过示例来说明。~> 2.0.3是 与>= 2.0.3和< 2.1相同。~> 2.1与>= 2.1相同,且< 3.0.

public static boolean apply(String cmpDeviceVersion, String reqDeviceVersion)
{
    Boolean equal           = !cmpDeviceVersion.contains(">") && !cmpDeviceVersion.contains(">=") &&
                              !cmpDeviceVersion.contains("<") && !cmpDeviceVersion.contains("<=") &&
                              !cmpDeviceVersion.contains("~>");

    Boolean between         = cmpDeviceVersion.contains("~>");
    Boolean higher          = cmpDeviceVersion.contains(">") && !cmpDeviceVersion.contains(">=") && !cmpDeviceVersion.contains("~>");
    Boolean higherOrEqual   = cmpDeviceVersion.contains(">=");

    Boolean less            = cmpDeviceVersion.contains("<") && !cmpDeviceVersion.contains("<=");
    Boolean lessOrEqual     = cmpDeviceVersion.contains("<=");

    cmpDeviceVersion        = cmpDeviceVersion.replaceAll("[<>=~]", "");
    cmpDeviceVersion        = cmpDeviceVersion.trim();

    String[] version        = cmpDeviceVersion.split("\\.");
    String[] reqVersion     = reqDeviceVersion.split("\\.");

    if(equal)
    {
        return isEqual(version, reqVersion);
    }
    else if(between)
    {
        return isBetween(version, reqVersion);
    }
    else if(higher)
    {
        return isHigher(version, reqVersion);
    }
    else if(higherOrEqual)
    {
        return isEqual(version, reqVersion) || isHigher(version, reqVersion);
    }
    else if(less)
    {
        return isLess(version, reqVersion);
    }
    else if(lessOrEqual)
    {
        return isEqual(version, reqVersion) || isLess(version, reqVersion);
    }

    return false;
}

private static boolean isEqual(String[] version, String[] reqVersion)
{
    String strVersion = StringUtils.join(version);
    String strReqVersion = StringUtils.join(reqVersion);
    if(version.length > reqVersion.length)
    {
        Integer diff = version.length - reqVersion.length;
        strReqVersion += StringUtils.repeat(".0", diff);
    }
    else if(reqVersion.length > version.length)
    {
        Integer diff = reqVersion.length - version.length;
        strVersion += StringUtils.repeat(".0", diff);
    }

    return strVersion.equals(strReqVersion);
}

private static boolean isHigher(String[] version, String[] reqVersion)
{
    String strVersion = StringUtils.join(version);
    String strReqVersion = StringUtils.join(reqVersion);
    if(version.length > reqVersion.length)
    {
        Integer diff = version.length - reqVersion.length;
        strReqVersion += StringUtils.repeat(".0", diff);
    }
    else if(reqVersion.length > version.length)
    {
        Integer diff = reqVersion.length - version.length;
        strVersion += StringUtils.repeat(".0", diff);
    }

    return strReqVersion.compareTo(strVersion) > 0;
}

private static boolean isLess(String[] version, String[] reqVersion)
{
    String strVersion = StringUtils.join(version);
    String strReqVersion = StringUtils.join(reqVersion);
    if(version.length > reqVersion.length)
    {
        Integer diff = version.length - reqVersion.length;
        strReqVersion += StringUtils.repeat(".0", diff);
    }
    else if(reqVersion.length > version.length)
    {
        Integer diff = reqVersion.length - version.length;
        strVersion += StringUtils.repeat(".0", diff);
    }

    return strReqVersion.compareTo(strVersion) < 0;
}

private static boolean isBetween(String[] version, String[] reqVersion)
{
    return (isEqual(version, reqVersion) || isHigher(version, reqVersion)) &&
            isLess(getNextVersion(version), reqVersion);
}

private static String[] getNextVersion(String[] version)
{
    String[] nextVersion = new String[version.length];
    for(int i = version.length - 1; i >= 0 ; i--)
    {
        if(i == version.length - 1)
        {
            nextVersion[i] = "0";
        }
        else if((i == version.length - 2) && NumberUtils.isNumber(version[i]))
        {
            nextVersion[i] = String.valueOf(NumberUtils.toInt(version[i]) + 1);
        }
        else
        {
            nextVersion[i] = version[i];
        }
    }
    return nextVersion;
}

我自己写了一个小函数。更简单地使用列表

 public static boolean checkVersionUpdate(String olderVerison, String newVersion) {
        if (olderVerison.length() == 0 || newVersion.length() == 0) {
            return false;
        }
        List<String> newVerList = Arrays.asList(newVersion.split("\\."));
        List<String> oldVerList = Arrays.asList(olderVerison.split("\\."));

        int diff = newVerList.size() - oldVerList.size();
        List<String> newList = new ArrayList<>();
        if (diff > 0) {
            newList.addAll(oldVerList);
            for (int i = 0; i < diff; i++) {
                newList.add("0");
            }
            return examineArray(newList, newVerList, diff);
        } else if (diff < 0) {
            newList.addAll(newVerList);
            for (int i = 0; i < -diff; i++) {
                newList.add("0");
            }
            return examineArray(oldVerList, newList, diff);
        } else {
            return examineArray(oldVerList, newVerList, diff);
        }

    }

    public static boolean examineArray(List<String> oldList, List<String> newList, int diff) {
        boolean newVersionGreater = false;
        for (int i = 0; i < oldList.size(); i++) {
            if (Integer.parseInt(newList.get(i)) > Integer.parseInt(oldList.get(i))) {
                newVersionGreater = true;
                break;
            } else if (Integer.parseInt(newList.get(i)) < Integer.parseInt(oldList.get(i))) {
                newVersionGreater = false;
                break;
            } else {
                newVersionGreater = diff > 0;
            }
        }

        return newVersionGreater;
    }

我写了一个名为MgntUtils的开源库,它有一个用于字符串版本的实用程序。它正确地比较它们,适用于版本范围等等。下面是这个库javadoc参见方法TextUtils.comapreVersions(…)它已经被大量使用并经过了良好的测试。下面这篇文章描述了这个库以及如何获取它。它可以作为Maven工件和在github上获得(包括源代码和JavaDoc)