是否有比较版本号的标准习语?我不能直接使用String compareTo,因为我还不知道点释放的最大数量是多少。我需要比较版本,并有以下保持正确:

1.0 < 1.1
1.0.1 < 1.1
1.9 < 1.10

当前回答

对于我的项目,我使用我的公共版本库https://github.com/raydac/commons-version 它包含两个辅助类-用于解析版本(解析后的版本可以与另一个版本对象进行比较,因为它是可比的)和VersionValidator,它允许检查一些表达式的版本,如!=ide-1.1.1,>idea-1.3.4-SNAPSHOT;<1.2.3

其他回答

public int compare(String v1, String v2) {
        v1 = v1.replaceAll("\\s", "");
        v2 = v2.replaceAll("\\s", "");
        String[] a1 = v1.split("\\.");
        String[] a2 = v2.split("\\.");
        List<String> l1 = Arrays.asList(a1);
        List<String> l2 = Arrays.asList(a2);


        int i=0;
        while(true){
            Double d1 = null;
            Double d2 = null;

            try{
                d1 = Double.parseDouble(l1.get(i));
            }catch(IndexOutOfBoundsException e){
            }

            try{
                d2 = Double.parseDouble(l2.get(i));
            }catch(IndexOutOfBoundsException e){
            }

            if (d1 != null && d2 != null) {
                if (d1.doubleValue() > d2.doubleValue()) {
                    return 1;
                } else if (d1.doubleValue() < d2.doubleValue()) {
                    return -1;
                }
            } else if (d2 == null && d1 != null) {
                if (d1.doubleValue() > 0) {
                    return 1;
                }
            } else if (d1 == null && d2 != null) {
                if (d2.doubleValue() > 0) {
                    return -1;
                }
            } else {
                break;
            }
            i++;
        }
        return 0;
    }
public class VersionComparator {

    /* loop through both version strings
     * then loop through the inner string to computer the val of the int
     * for each integer read, do num*10+<integer read>
     * and stop when stumbling upon '.'
     * When '.' is encountered...
     * see if '.' is encountered for both strings
     * if it is then compare num1 and num2 
     * if num1 == num2... iterate over p1++, p2++
     * else return (num1 > num2) ? 1 : -1
     * If both the string end then compare(num1, num2) return 0, 1, -1
     * else loop through the longer string and 
     * verify if it only has trailing zeros
     * If it only has trailing zeros then return 0
     * else it is greater than the other string
     */
    public static int compareVersions(String v1, String v2) {
        int num1 = 0;
        int num2 = 0;
        int p1 = 0;
        int p2 = 0;

        while (p1 < v1.length() && p2 < v2.length()) {
            num1 = Integer.parseInt(v1.charAt(p1) + "");
            num2 = Integer.parseInt(v2.charAt(p2) + "");
            p1++;
            p2++;

            while (p1 < v1.length() && p2 < v2.length() && v1.charAt(p1) != '.' && v2.charAt(p2) != '.') {
                if (p1 < v1.length()) num1 = num1 * 10 + Integer.parseInt(v1.charAt(p1) + "");
                if (p2 < v2.length()) num2 = num2 * 10 + Integer.parseInt(v2.charAt(p2) + "");
                p1++;
                p2++;
            }

            if (p1 < v1.length() && p2 < v2.length() && v1.charAt(p1) == '.' && v2.charAt(p2) == '.') {
                if ((num1 ^ num2) == 0) {
                    p1++;
                    p2++;
                }
                else return (num1 > num2) ? 1 : -1;
            }
            else if (p1 < v1.length() && p2 < v2.length() && v1.charAt(p1) == '.') return -1;
            else if (p1 < v1.length() && p2 < v2.length() && v2.charAt(p2) == '.') return 1;
        }

        if (p1 == v1.length() && p2 == v2.length()) {
            if ((num1 ^ num2) == 0) return 0;
            else return (num1 > num2) ? 1 : -1;
        }
        else if (p1 == v1.length()) {
            if ((num1 ^ num2) == 0) {
                while (p2 < v2.length()) {
                    if (v2.charAt(p2) != '.' && v2.charAt(p2) != '0') return -1;
                    p2++;
                }
                return 0;
            }
            else return (num1 > num2) ? 1 : -1;
        }
        else {
            if ((num1 ^ num2) == 0) {
                while (p1 < v1.length()) {
                    if (v1.charAt(p1) != '.' && v1.charAt(p1) != '0') return 1;
                    p1++;
                }
                return 0;
            }
            else return (num1 > num2) ? 1 : -1;
        }
    }

    public static void main(String[] args) {
        System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
        System.out.println(compareVersions("11.21.1.0.0.1.0", "11.23") ^ -1);
        System.out.println(compareVersions("11.23", "11.23.0.0.0.1.0") ^ -1);
        System.out.println(compareVersions("11.2", "11.23") ^ -1);
        System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
        System.out.println(compareVersions("1.21.1.0.0.1.0", "2.23") ^ -1);
        System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
        System.out.println(compareVersions("11.23.0.0.0.0.0", "11.23") ^ 0);
        System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
        System.out.println(compareVersions("1.5.1.3", "1.5.1.3.0") ^ 0);
        System.out.println(compareVersions("1.5.1.4", "1.5.1.3.0") ^ 1);
        System.out.println(compareVersions("1.2.1.3", "1.5.1.3.0") ^ -1);
        System.out.println(compareVersions("1.2.1.3", "1.22.1.3.0") ^ -1);
        System.out.println(compareVersions("1.222.1.3", "1.22.1.3.0") ^ 1);
    }
}

使用Maven真的很简单:

import org.apache.maven.artifact.versioning.DefaultArtifactVersion;

DefaultArtifactVersion minVersion = new DefaultArtifactVersion("1.0.1");
DefaultArtifactVersion maxVersion = new DefaultArtifactVersion("1.10");

DefaultArtifactVersion version = new DefaultArtifactVersion("1.11");

if (version.compareTo(minVersion) < 0 || version.compareTo(maxVersion) > 0) {
    System.out.println("Sorry, your version is unsupported");
}

您可以从这个页面获得Maven Artifact的正确依赖项字符串:

<dependency>
<groupId>org.apache.maven</groupId>
<artifactId>maven-artifact</artifactId>
<version>3.0.3</version>
</dependency>

我现在就做了,然后问自己,这对吗?因为我从来没有找到过比我的更干净的解决方案

你只需要像下面这样拆分字符串版本("1.0.0"):

userVersion.split("\\.")

那么你将得到:{"1","0","0"}

现在,用我做过的方法

isUpdateAvailable(userVersion.split("\\."), latestVersionSplit.split("\\."));

方法:

/**
 * Compare two versions
 *
 * @param userVersionSplit   - User string array with major, minor and patch version from user (exemple: {"5", "2", "70"})
 * @param latestVersionSplit - Latest string array with major, minor and patch version from api (example: {"5", "2", "71"})
 * @return true if user version is smaller than latest version
 */
public static boolean isUpdateAvailable(String[] userVersionSplit, String[] latestVersionSplit) {

    try {
        int majorUserVersion = Integer.parseInt(userVersionSplit[0]);
        int minorUserVersion = Integer.parseInt(userVersionSplit[1]);
        int patchUserVersion = Integer.parseInt(userVersionSplit[2]);

        int majorLatestVersion = Integer.parseInt(latestVersionSplit[0]);
        int minorLatestVersion = Integer.parseInt(latestVersionSplit[1]);
        int patchLatestVersion = Integer.parseInt(latestVersionSplit[2]);

        if (majorUserVersion <= majorLatestVersion) {
            if (majorUserVersion < majorLatestVersion) {
                return true;
            } else {
                if (minorUserVersion <= minorLatestVersion) {
                    if (minorUserVersion < minorLatestVersion) {
                        return true;
                    } else {
                        return patchUserVersion < patchLatestVersion;
                    }
                }
            }
        }
    } catch (Exception ignored) {
        // Will be throw only if the versions pattern is different from "x.x.x" format
        // Will return false at the end
    }

    return false;
}

等待任何反馈:)

科特林:

@kotlin.jvm.Throws(InvalidParameterException::class)
fun String.versionCompare(remoteVersion: String?): Int {
    val remote = remoteVersion?.splitToSequence(".")?.toList() ?: return 1
    val local = this.splitToSequence(".").toList()

    if(local.filter { it.toIntOrNull() != null }.size != local.size) throw InvalidParameterException("version invalid: $this")
    if(remote.filter { it.toIntOrNull() != null }.size != remote.size) throw InvalidParameterException("version invalid: $remoteVersion")

    val totalRange = 0 until kotlin.math.max(local.size, remote.size)
    for (i in totalRange) {
        if (i < remote.size && i < local.size) {
            val result = local[i].compareTo(remote[i])
            if (result != 0) return result
        } else (
            return local.size.compareTo(remote.size)
        )
    }
    return 0
}