下面是c#方法。 Int。TryParse方法(String, Int32)

以防你不想用int。解析或双重。解析，你可以用这样的东西来滚动你自己的:

public static class Extensions
{
    public static bool IsNumeric(this string s)
    {
        foreach (char c in s)
        {
            if (!char.IsDigit(c) && c != '.')
            {
                return false;
            }
        }

        return true;
    }
}

下面是c#方法。 Int。TryParse方法(String, Int32)

 bool is_number(string str, char delimiter = '.')
    {
        if(str.Length==0) //Empty
        {
            return false;
        }
        bool is_delimetered = false;
        foreach (char c in str)
        {
            if ((c < '0' || c > '9') && (c != delimiter)) //ASCII table check. Not a digit && not delimeter
            {
                return false;
            }
            if (c == delimiter)
            {
                if (is_delimetered) //more than 1 delimiter
                {
                    return false;
                }
                else //first time delimiter
                {
                    is_delimetered = true;
                }
            }
        }
        return true; 
    }

public static bool IsNumeric(this string input)
{
    int n;
    if (!string.IsNullOrEmpty(input)) //.Replace('.',null).Replace(',',null)
    {
        foreach (var i in input)
        {
            if (!int.TryParse(i.ToString(), out n))
            {
                return false;
            }

        }
        return true;
    }
    return false;
}

//To my knowledge I did this in a simple way
static void Main(string[] args)
{
    string a, b;
    int f1, f2, x, y;
    Console.WriteLine("Enter two inputs");
    a = Convert.ToString(Console.ReadLine());
    b = Console.ReadLine();
    f1 = find(a);
    f2 = find(b);

    if (f1 == 0 && f2 == 0)
    {
        x = Convert.ToInt32(a);
        y = Convert.ToInt32(b);
        Console.WriteLine("Two inputs r number \n so that addition of these text box is= " + (x + y).ToString());
    }
    else
        Console.WriteLine("One or two inputs r string \n so that concatenation of these text box is = " + (a + b));
    Console.ReadKey();
}

static int find(string s)
{
    string s1 = "";
    int f;
    for (int i = 0; i < s.Length; i++)
       for (int j = 0; j <= 9; j++)
       {
           string c = j.ToString();
           if (c[0] == s[i])
           {
               s1 += c[0];
           }
       }

    if (s == s1)
        f = 0;
    else
        f = 1;

    return f;
}