根據一條線:
s = "Test abc test test abc test test test abc test test abc";
这似乎只是在上面的行中删除ABC的第一次出现:
s = s.replace('abc', '');
如何替代所有事件?
当前回答
我使用分割和加入或这个功能:
function replaceAll(text, busca, reemplaza) {
while (text.toString().indexOf(busca) != -1)
text = text.toString().replace(busca, reemplaza);
return text;
}
其他回答
这个解决方案结合了一些以前的答案,并更好地符合建议的2020年8月标准解决方案,这个解决方案在2020年9月对我来说仍然可行,因为String.replaceAll不在我使用的Node.js二进制中。
RegExp.escape 是一个单独的问题处理,但它在这里很重要,因为官方提出的解决方案将自动逃脱基于链条的查找输入。
如果你需要准确的标准符合,对于一个应用程序,它是严格依赖于标准实施,那么我建议使用Babel或其他工具,你得到“正确的答案”每次而不是Stack Overflow。
代码:
if (!Object.prototype.hasOwnProperty.call(RegExp, 'escape')) {
RegExp.escape = function(string) {
// https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Regular_Expressions#Escaping
// https://github.com/benjamingr/RegExp.escape/issues/37
return string.replace(/[.*+\-?^${}()|[\]\\]/g, '\\$&'); // $& means the whole matched string
};
}
if (!Object.prototype.hasOwnProperty.call(String, 'replaceAll')) {
String.prototype.replaceAll = function(find, replace) {
// https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replaceAll
// If you pass a RegExp to 'find', you _MUST_ include 'g' as a flag.
// TypeError: "replaceAll must be called with a global RegExp" not included, will silently cause significant errors. _MUST_ include 'g' as a flag for RegExp.
// String parameters to 'find' do not require special handling.
// Does not conform to "special replacement patterns" when "Specifying a string as a parameter" for replace
// Does not conform to "Specifying a function as a parameter" for replace
return this.replace(
Object.prototype.toString.call(find) == '[object RegExp]' ?
find :
new RegExp(RegExp.escape(find), 'g'),
replace
);
}
}
编码,小型:
Object.prototype.hasOwnProperty.call(RegExp,"escape")||(RegExp.escape=function(e){return e.replace(/[.*+\-?^${}()|[\]\\]/g,"\\$&")}),Object.prototype.hasOwnProperty.call(String,"replaceAll")||(String.prototype.replaceAll=function(e,t){return this.replace("[object RegExp]"==Object.prototype.toString.call(e)?e:new RegExp(RegExp.escape(e),"g"),t)});
例子:
console.log(
't*.STVAL'
.replaceAll(
new RegExp(RegExp.escape('T*.ST'), 'ig'),
'TEST'
)
);
console.log(
't*.STVAL'
.replaceAll(
't*.ST',
'TEST'
);
);
没有 RegExp.Escape 的代码:
if (!Object.prototype.hasOwnProperty.call(String, 'replaceAll')) {
String.prototype.replaceAll = function(find, replace) {
// https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replaceAll
// If you pass a RegExp to 'find', you _MUST_ include 'g' as a flag.
// TypeError: "replaceAll must be called with a global RegExp" not included, will silently cause significant errors. _MUST_ include 'g' as a flag for RegExp.
// String parameters to 'find' do not require special handling.
// Does not conform to "special replacement patterns" when "Specifying a string as a parameter" for replace
// Does not conform to "Specifying a function as a parameter" for replace
return this.replace(
Object.prototype.toString.call(find) == '[object RegExp]' ?
find :
new RegExp(find.replace(/[.*+\-?^${}()|[\]\\]/g, '\\$&'), 'g'),
replace
);
}
}
代码没有 RegExp.Escape,小型:
Object.prototype.hasOwnProperty.call(String,"replaceAll")||(String.prototype.replaceAll=function(e,t){return this.replace("[object RegExp]"==Object.prototype.toString.call(e)?e:new RegExp(e.replace(/[.*+\-?^${}()|[\]\\]/g,"\\$&"),"g"),t)});
要取代所有类型的字符,请尝试此代码:
假设我们需要发送“和 \ 在我的行中,然后我们将转换“到“和 \ 到“。
因此,这种方法将解决这个问题。
String.prototype.replaceAll = function (find, replace) {
var str = this;
return str.replace(new RegExp(find.replace(/[-\/\\^$*+?.()|[\]{}]/g, '\\$&'), 'g'), replace);
};
var message = $('#message').val();
message = message.replaceAll('\\', '\\\\'); /*it will replace \ to \\ */
message = message.replaceAll('"', '\\"'); /*it will replace " to \\"*/
我使用Ajax,我需要在JSON格式发送参数,然后我的方法看起来如下:
function sendMessage(source, messageID, toProfileID, userProfileID) {
if (validateTextBox()) {
var message = $('#message').val();
message = message.replaceAll('\\', '\\\\');
message = message.replaceAll('"', '\\"');
$.ajax({
type: "POST",
async: "false",
contentType: "application/json; charset=utf-8",
url: "services/WebService1.asmx/SendMessage",
data: '{"source":"' + source + '","messageID":"' + messageID + '","toProfileID":"' + toProfileID + '","userProfileID":"' + userProfileID + '","message":"' + message + '"}',
dataType: "json",
success: function (data) {
loadMessageAfterSend(toProfileID, userProfileID);
$("#<%=PanelMessageDelete.ClientID%>").hide();
$("#message").val("");
$("#delMessageContainer").show();
$("#msgPanel").show();
},
error: function (result) {
alert("message sending failed");
}
});
}
else {
alert("Please type message in message box.");
$("#message").focus();
}
}
String.prototype.replaceAll = function (find, replace) {
var str = this;
return str.replace(new RegExp(find.replace(/[-\/\\^$*+?.()|[\]{}]/g, '\\$&'), 'g'), replace);
};
最好的解决方案,以取代我们使用的任何字符的 indexOf(),包括(),和substring()功能,以取代相匹配的行与提供的行在当前行。
String.indexOf() 函数是找到 nth 匹配指数位置. String.includes() 方法确定一个行是否可以在另一个行中找到,随时返回真实或虚假。
下面的功能允许使用任何字符. 如 RegExp 不允许某些特殊字符如 ** 和某些字符需要逃避,如 $。
String.prototype.replaceAllMatches = function(obj) { // Obj format: { 'matchkey' : 'replaceStr' }
var retStr = this;
for (var x in obj) {
//var matchArray = retStr.match(new RegExp(x, 'ig'));
//for (var i = 0; i < matchArray.length; i++) {
var prevIndex = retStr.indexOf(x); // matchkey = '*', replaceStr = '$*' While loop never ends.
while (retStr.includes(x)) {
retStr = retStr.replaceMatch(x, obj[x], 0);
var replaceIndex = retStr.indexOf(x);
if( replaceIndex < prevIndex + (obj[x]).length) {
break;
} else {
prevIndex = replaceIndex;
}
}
}
return retStr;
};
String.prototype.replaceMatch = function(matchkey, replaceStr, matchIndex) {
var retStr = this, repeatedIndex = 0;
//var matchArray = retStr.match(new RegExp(matchkey, 'ig'));
//for (var x = 0; x < matchArray.length; x++) {
for (var x = 0; (matchkey != null) && (retStr.indexOf(matchkey) > -1); x++) {
if (repeatedIndex == 0 && x == 0) {
repeatedIndex = retStr.indexOf(matchkey);
} else { // matchIndex > 0
repeatedIndex = retStr.indexOf(matchkey, repeatedIndex + 1);
}
if (x == matchIndex) {
retStr = retStr.substring(0, repeatedIndex) + replaceStr + retStr.substring(repeatedIndex + (matchkey.length));
matchkey = null; // To break the loop.
}
}
return retStr;
};
我们还可以使用常规表达式对象,以匹配文本与模式,以下是将常规表达式对象使用的功能。
String.prototype.replaceAllRegexMatches = function(obj) { // Obj format: { 'matchkey' : 'replaceStr' }
var retStr = this;
for (var x in obj) {
retStr = retStr.replace(new RegExp(x, 'ig'), obj[x]);
}
return retStr;
};
请注意,常规表达式是没有引用的。
var str = "yash yas $dfdas.**";
console.log('String: ', str);
// No need to escape any special character
console.log('Index matched replace: ', str.replaceMatch('as', '*', 2));
console.log('Index Matched replace: ', str.replaceMatch('y', '~', 1));
console.log('All Matched replace: ', str.replaceAllMatches({'as': '**', 'y':'Y', '$':'-'}));
console.log('All Matched replace : ', str.replaceAllMatches({'**': '~~', '$':'&$&', '&':'%', '~':'>'}));
// You need to escape some special Characters
console.log('REGEX all matched replace: ', str.replaceAllRegexMatches({'as' : '**', 'y':'Y', '\\$':'-'}));
结果:
String: yash yas $dfdas.**
Index Matched replace: yash yas $dfd*.**
Index Matched replace: yash ~as $dfdas.**
All Matched replace: Y**h Y** -dfd**.**
All Matched replace: yash yas %$%dfdas.>>
REGEX All Matched replace: Y**h Y** -dfd**.**
'a cat is not a caterpillar'.replace(/\bcat\b/gi,'dog');
//"a dog is not a caterpillar"
這是一個簡單的雷格斯,避免在大多數情況下取代字的部分. 然而,一個<unk> - 仍然被認為是字的邊界. 所以條件可以用在這種情況下,以避免取代線,如冷貓:
'a cat is not a cool-cat'.replace(/\bcat\b/gi,'dog');//wrong
//"a dog is not a cool-dog" -- nips
'a cat is not a cool-cat'.replace(/(?:\b([^-]))cat(?:\b([^-]))/gi,'$1dog$2');
//"a dog is not a cool-cat"
Regexp 不是唯一的替代多种现象的方法,远离它,思考灵活,思考分裂!
var newText = "the cat looks like a cat".split('cat').join('dog');
否则,要防止替代词部分 - 批准的答案也会做什么! 你可以通过常规的表达方式来围绕这个问题,我承认,有点复杂,并且作为一个惊喜,一个缓慢的,也:
var regText = "the cat looks like a cat".replace(/(?:(^|[^a-z]))(([^a-z]*)(?=cat)cat)(?![a-z])/gi,"$1dog");
结果与接受的答案相同,但是,在这个行上使用 /cat/g 表达式:
var oops = 'the cat looks like a cat, not a caterpillar or coolcat'.replace(/cat/g,'dog');
//returns "the dog looks like a dog, not a dogerpillar or cooldog" ??
var caterpillar = 'the cat looks like a cat, not a caterpillar or coolcat'.replace(/(?:(^|[^a-z]))(([^a-z]*)(?=cat)cat)(?![a-z])/gi,"$1dog");
//return "the dog looks like a dog, not a caterpillar or coolcat"
RegExp(常规表达式)对象 Regular-Expressions.info
在这种情况下,它显著简化表达,并提供更多的灵活性,如用正确的资本化替换或在一个行中替换两只猫和猫:
'Two cats are not 1 Cat! They\'re just cool-cats, you caterpillar'
.replace(/(^|.\b)(cat)(s?\b.|$)/gi,function(all,char1,cat,char2)
{
// Check 1st, capitalize if required
var replacement = (cat.charAt(0) === 'C' ? 'D' : 'd') + 'og';
if (char1 === ' ' && char2 === 's')
{ // Replace plurals, too
cat = replacement + 's';
}
else
{ // Do not replace if dashes are matched
cat = char1 === '-' || char2 === '-' ? cat : replacement;
}
return char1 + cat + char2;//return replacement string
});
//returns:
//Two dogs are not 1 Dog! They're just cool-cats, you caterpillar
说你想用“x”取代所有的“abc”:
let some_str = 'abc def def lom abc abc def'.split('abc').join('x')
console.log(some_str) //x def def lom x x def
我试图思考一些更简单的东西,而不是修改链条的原型。
