就像上面的分裂/合并解决方案一样,下面的解决方案与逃避字符没有任何问题,与常规表达方法不同。

function replaceAll(s, find, repl, caseOff, byChar) {
    if (arguments.length<2)
        return false;
    var destDel = ! repl;       // If destDel delete all keys from target
    var isString = !! byChar;   // If byChar, replace set of characters
    if (typeof find !== typeof repl && ! destDel)
        return false;
    if (isString && (typeof find !== "string"))
        return false;

    if (! isString && (typeof find === "string")) {
        return s.split(find).join(destDel ? "" : repl);
    }

    if ((! isString) && (! Array.isArray(find) ||
        (! Array.isArray(repl) && ! destDel)))
        return false;

    // If destOne replace all strings/characters by just one element
    var destOne = destDel ? false : (repl.length === 1);

    // Generally source and destination should have the same size
    if (! destOne && ! destDel && find.length !== repl.length)
        return false

    var prox, sUp, findUp, i, done;
    if (caseOff)  { // Case insensitive

    // Working with uppercase keys and target
    sUp = s.toUpperCase();
    if (isString)
       findUp = find.toUpperCase()
    else
       findUp = find.map(function(el) {
                    return el.toUpperCase();
                });
    }
    else { // Case sensitive
        sUp = s;
        findUp = find.slice(); // Clone array/string
    }

    done = new Array(find.length); // Size: number of keys
    done.fill(null);

    var pos = 0;  // Initial position in target s
    var r = "";   // Initial result
    var aux, winner;
    while (pos < s.length) {       // Scanning the target
        prox  = Number.MAX_SAFE_INTEGER;
        winner = -1;  // No winner at the start
        for (i=0; i<findUp.length; i++) // Find next occurence for each string
            if (done[i]!==-1) { // Key still alive

                // Never search for the word/char or is over?
                if (done[i] === null || done[i] < pos) {
                    aux = sUp.indexOf(findUp[i], pos);
                    done[i] = aux;  // Save the next occurrence
                }
                else
                    aux = done[i]   // Restore the position of last search

                if (aux < prox && aux !== -1) { // If next occurrence is minimum
                    winner = i; // Save it
                    prox = aux;
                }
        } // Not done

        if (winner === -1) { // No matches forward
            r += s.slice(pos);
            break;
        } // No winner

        // Found the character or string key in the target

        i = winner;  // Restore the winner
        r += s.slice(pos, prox); // Update piece before the match

        // Append the replacement in target
        if (! destDel)
            r += repl[destOne ? 0 : i];
        pos = prox + (isString ? 1 : findUp[i].length); // Go after match
    }  // Loop

    return r; // Return the resulting string
}

文档如下:

替代All Syntax ====== 替代All(s, find, [repl, caseOff, byChar) 参数 ==========“s” 是替代序列的目标. “find” 可以是序列或序列的序列. “repl” 应该是相同的类型“find” 或空的 如果“find” 是序列,它是一个简单的替代所有“find” 事件在“s” 由序列“repl” 如果“find” 是序列,它将取代

function l() {
    return console.log.apply(null, arguments);
}

var k = 0;
l(++k, replaceAll("banana is a ripe fruit harvested near the river",
      ["ri", "nea"], ["do", "fa"]));  // 1
l(++k, replaceAll("banana is a ripe fruit harvested near the river",
      ["ri", "nea"], ["do"])); // 2
l(++k, replaceAll("banana is a ripe fruit harvested near the river",
      ["ri", "nea"])); // 3
l(++k, replaceAll("banana is a ripe fruit harvested near the river",
     "aeiou", "", "", true)); // 4
l(++k, replaceAll("banana is a ripe fruit harvested near the river",
      "aeiou", "a", "", true)); // 5
l(++k, replaceAll("banana is a ripe fruit harvested near the river",
      "aeiou", "uoiea", "", true)); // 6
l(++k, replaceAll("banana is a ripe fruit harvested near the river",
      "aeiou", "uoi", "", true)); // 7
l(++k, replaceAll("banana is a ripe fruit harvested near the river",
      ["ri", "nea"], ["do", "fa", "leg"])); // 8
l(++k, replaceAll("BANANA IS A RIPE FRUIT HARVESTED NEAR THE RIVER",
      ["ri", "nea"], ["do", "fa"])); // 9
l(++k, replaceAll("BANANA IS A RIPE FRUIT HARVESTED NEAR THE RIVER",
      ["ri", "nea"], ["do", "fa"], true)); // 10
return;

var str = "ff ff f f a de def";
str = str.replace(/f/g,'');
alert(str);

HTTP://jsfiddle.net/ANHR9/

String.prototype.replace 所有()

如果你不想处理替代() + RegExp。

但是,如果浏览器在2020年之前?

我推荐的替代All polyfill的选项:

替代All polyfill (与全球旗帜错误) (更多原则版)

if (!String.prototype.replaceAll) { // Check if the native function not exist
    Object.defineProperty(String.prototype, 'replaceAll', { // Define replaceAll as a prototype for (Mother/Any) String
        configurable: true, writable: true, enumerable: false, // Editable & non-enumerable property (As it should be)
        value: function(search, replace) { // Set the function by closest input names (For good info in consoles)
            return this.replace( // Using native String.prototype.replace()
                Object.prototype.toString.call(search) === '[object RegExp]' // IsRegExp?
                    ? search.global // Is the RegEx global?
                        ? search // So pass it
                        : function(){throw new TypeError('replaceAll called with a non-global RegExp argument')}() // If not throw an error
                    : RegExp(String(search).replace(/[.^$*+?()[{|\\]/g, "\\$&"), "g"), // Replace all reserved characters with '\' then make a global 'g' RegExp
                replace); // passing second argument
        }
    });
}

替代All polyfill (With handling global-flag missing by itself) (我的第一个偏好) - 为什么?

if (!String.prototype.replaceAll) { // Check if the native function not exist
    Object.defineProperty(String.prototype, 'replaceAll', { // Define replaceAll as a prototype for (Mother/Any) String
        configurable: true, writable: true, enumerable: false, // Editable & non-enumerable property (As it should be)
        value: function(search, replace) { // Set the function by closest input names (For good info in consoles)
            return this.replace( // Using native String.prototype.replace()
                Object.prototype.toString.call(search) === '[object RegExp]' // IsRegExp?
                    ? search.global // Is the RegEx global?
                        ? search // So pass it
                        : RegExp(search.source, /\/([a-z]*)$/.exec(search.toString())[1] + 'g') // If not, make a global clone from the RegEx
                    : RegExp(String(search).replace(/[.^$*+?()[{|\\]/g, "\\$&"), "g"), // Replace all reserved characters with '\' then make a global 'g' RegExp
                replace); // passing second argument
        }
    });
}

小型(我的第一个偏好):

if(!String.prototype.replaceAll){Object.defineProperty(String.prototype,'replaceAll',{configurable:!0,writable:!0,enumerable:!1,value:function(search,replace){return this.replace(Object.prototype.toString.call(search)==='[object RegExp]'?search.global?search:RegExp(search.source,/\/([a-z]*)$/.exec(search.toString())[1]+'g'):RegExp(String(search).replace(/[.^$*+?()[{|\\]/g,"\\$&"),"g"),replace)}})}

---

其他方法的聚合物分配

if (!String.prototype.replaceAll) {
    String.prototype.replaceAll = function(search, replace) { // <-- Naive method for assignment
        // ... (Polyfill code Here)
    }
}

for (var k in 'hi') console.log(k);
// 0
// 1
// replaceAll  <-- ?

非常可靠,但重

事实上,我提出的选项有点乐观,正如我们信任环境(浏览器和Node.js),它肯定是2012年至2021年左右。

此分類上一篇: HTTPS://polyfill.io

特别是替代:

<script src="https://polyfill.io/v3/polyfill.min.js?features=String.prototype.replaceAll"></script>

对抗全球常规表达:

anotherString = someString.replace(/cat/g, 'dog');

说你想用“x”取代所有的“abc”:

let some_str = 'abc def def lom abc abc def'.split('abc').join('x')
console.log(some_str) //x def def lom x x def

我试图思考一些更简单的东西,而不是修改链条的原型。

你可以尝试这样:

示例数据:

var text = "heloo,hai,hei"

text = text.replace(/[,]+/g, '')

或

text.forEach((value) => {
  hasil = hasil.replace(',', '')
})