如何使用JavaScript检查/不检查复选框?
当前回答
function setCheckboxValue(checkbox,value) {
if (checkbox.checked!=value)
checkbox.click();
}
其他回答
Javascript:
// Check
document.getElementById("checkbox").checked = true;
// Uncheck
document.getElementById("checkbox").checked = false;
jQuery 1.6 (+):
// Check
$("#checkbox").prop("checked", true);
// Uncheck
$("#checkbox").prop("checked", false);
jQuery (1.5 -):
// Check
$("#checkbox").attr("checked", true);
// Uncheck
$("#checkbox").attr("checked", false);
使用vanilla js:
//for one element:
document.querySelector('.myCheckBox').checked = true //will select the first matched element
document.querySelector('.myCheckBox').checked = false//will unselect the first matched element
//for multiple elements:
for (const checkbox of document.querySelectorAll('.myCheckBox')) {
//iterating over all matched elements
checkbox.checked = true //for selection
checkbox.checked = false //for unselection
}
检查:
document.getElementById("id-of-checkbox").checked = true;
取消:
document.getElementById("id-of-checkbox").checked = false;
试试这个:
//Check
document.getElementById('checkbox').setAttribute('checked', 'checked');
//UnCheck
document.getElementById('chk').removeAttribute('checked');
我们可以这样选中一个粒子复选框,
$('id of the checkbox')[0].checked = true
然后取消检查,
$('id of the checkbox')[0].checked = false