var a = [1, 2, 3];
var b = [3, 2, 1];
var c = new Array(1, 2, 3);

alert(a == b + "|" + b == c);

demo

如何检查这些数组是否相等,并获得一个方法,如果它们相等,则返回true ?

jQuery是否为此提供了任何方法?


当前回答

如果您希望检查对象数组的相等性和顺序并不重要,即。

areEqual ([{id:“0”},{id: " 1 "}], [{id: " 1 "}, {id: " 0 "})) / /真实的

首先要对数组进行排序。lodash有你需要的所有工具,通过组合sortBy和isEqual:

// arr1 & arr2: Arrays of objects 
// sortProperty: the property of the object with which you want to sort
// Note: ensure every object in both arrays has your chosen sortProperty
// For example, arr1 = [{id: "v-test_id0"}, {id: "v-test_id1"}]
// and          arr2 = [{id: "v-test_id1"}, {id: "v-test_id0"}]
// sortProperty should be 'id'

function areEqual (arr1, arr2, sortProperty) {
  return _.areEqual(_.sortBy(arr1, sortProperty), _.sortBy(arr2, sortProperty))
}

编辑:由于sortBy返回一个新数组,在排序之前不需要克隆数组。原始数组不会被改变。

注意,对于lodash的isEqual,顺序很重要。如果sortBy没有首先应用于每个数组,上面的例子将返回false。

其他回答

在JavaScript 1.6版中,这很简单:

Array.prototype.equals = function( array ) {
  return this.length == array.length && 
         this.every( function(this_i,i) { return this_i == array[i] } )  
  }

例如,[].equals([])给出true,而[1,2,3]。Equals([1,3,2])产生false。

如果您正在使用lodash,并且不想修改任何一个数组,则可以使用_.xor()函数。它将两个数组作为集合进行比较,并返回包含它们之差的集合。如果此差值的长度为零,则两个数组本质上相等:

var a = [1, 2, 3];
var b = [3, 2, 1];
var c = new Array(1, 2, 3);
_.xor(a, b).length === 0
true
_.xor(b, c).length === 0
true

使用map()和reduce():

function arraysEqual (a1, a2) {
    return a1 === a2 || (
        a1 !== null && a2 !== null &&
        a1.length === a2.length &&
        a1
            .map(function (val, idx) { return val === a2[idx]; })
            .reduce(function (prev, cur) { return prev && cur; }, true)
    );
}

它处理所有可能的东西,甚至在对象的结构中引用自己。您可以在代码的末尾看到示例。

var deepCompare = (function() {
    function internalDeepCompare (obj1, obj2, objects) {
        var i, objPair;

        if (obj1 === obj2) {
            return true;
        }

        i = objects.length;
        while (i--) {
            objPair = objects[i];
            if (  (objPair.obj1 === obj1 && objPair.obj2 === obj2) ||
                  (objPair.obj1 === obj2 && objPair.obj2 === obj1)  ) {                          
                return true;
            }                    
        }
        objects.push({obj1: obj1, obj2: obj2});

        if (obj1 instanceof Array) {
            if (!(obj2 instanceof Array)) {
                return false;
            }

            i = obj1.length;

            if (i !== obj2.length) {
               return false; 
            }

            while (i--) {
                if (!internalDeepCompare(obj1[i], obj2[i], objects)) {
                    return false;
                }
            }
        }
        else {
            switch (typeof obj1) {
                case "object":                
                    // deal with null
                    if (!(obj2 && obj1.constructor === obj2.constructor)) {
                        return false;
                    }

                    if (obj1 instanceof RegExp) {
                        if (!(obj2 instanceof RegExp && obj1.source === obj2.source)) {
                            return false;
                        }
                    }                 
                    else if (obj1 instanceof Date) {
                        if (!(obj2 instanceof Date && obj1.getTime() === obj2.getTime())) {
                            return false;
                        }
                    } 
                    else {    
                        for (i in obj1) {
                            if (obj1.hasOwnProperty(i)) {       
                                if (!(obj2.hasOwnProperty(i) && internalDeepCompare(obj1[i], obj2[i], objects))) {
                                    return false;
                                }
                            }
                        }         
                    }
                    break;
                case "function": 
                    if (!(typeof obj2 === "function" && obj1+"" === obj2+"")) {
                        return false;
                    }
                    break;
                default:                 //deal with NaN 
                    if (obj1 !== obj2 && obj1 === obj1 && obj2 === obj2) {
                        return false;            
                    }
            }
        }

        return true;
    }

    return function (obj1, obj2) {
        return internalDeepCompare(obj1, obj2, []);    
    };
}());

/*    
var a = [a, undefined, new Date(10), /.+/, {a:2}, function(){}, Infinity, -Infinity, NaN, 0, -0, 1, [4,5], "1", "-1", "a", null],
    b = [b, undefined, new Date(10), /.+/, {a:2}, function(){}, Infinity, -Infinity, NaN, 0, -0, 1, [4,5], "1", "-1", "a", null];
deepCompare(a, b);
*/

这是你应该做的。请不要使用stringify或< >。

function arraysEqual(a, b) {
  if (a === b) return true;
  if (a == null || b == null) return false;
  if (a.length !== b.length) return false;

  // If you don't care about the order of the elements inside
  // the array, you should sort both arrays here.
  // Please note that calling sort on an array will modify that array.
  // you might want to clone your array first.

  for (var i = 0; i < a.length; ++i) {
    if (a[i] !== b[i]) return false;
  }
  return true;
}