[].concat.apply([], [array1, array2, ...])

效率证明:http://jsperf.com/multi-array-concat/7

Tim Supinie mentions in the comments that this may cause the interpreter to exceed the call stack size. This is perhaps dependent on the js engine, but I've also gotten "Maximum call stack size exceeded" on Chrome at least. Test case: [].concat.apply([], Array(300000).fill().map(_=>[1,2,3])). (I've also gotten the same error using the currently accepted answer, so one is anticipating such use cases or building a library for others, special testing may be necessary no matter which solution you choose.)

这样解决。

let arr = [[1, 2], [3, 4], [5, 6]];
 console.log([].concat(...arr));

concat()方法用于连接两个或多个数组。它不会更改现有数组，只返回已连接数组的副本。

array1 = array1.concat(array2, array3, array4, ..., arrayN);

如果N个数组是从数据库中获得的，并且没有硬编码，i将使用ES6这样做

let get_fruits = [...get_fruits , ...DBContent.fruit];

轻松使用concat函数:

var a = [1,2,3];
var b = [2,3,4];
a = a.concat(b);
>> [1,2,3,2,3,4]

如果只有两个数组要连接，并且实际上需要追加其中一个数组，而不是创建一个新数组，则应该使用push或循环。

基准:https://jsperf.com/concat-small-arrays-vs-push-vs-loop/