目标是创建一个行为类似db结果集的模拟类。

例如,如果一个数据库查询返回,使用dict表达式,{'ab':100, 'cd':200},那么我想看到:

>>> dummy.ab
100

一开始我想也许我可以这样做:

ks = ['ab', 'cd']
vs = [12, 34]
class C(dict):
    def __init__(self, ks, vs):
        for i, k in enumerate(ks):
            self[k] = vs[i]
            setattr(self, k, property(lambda x: vs[i], self.fn_readyonly))

    def fn_readonly(self, v)
        raise "It is ready only"

if __name__ == "__main__":
    c = C(ks, vs)
    print c.ab

但是cab返回一个属性对象。

用k = property(lambda x: vs[i])替换setattr行根本没有用。

那么,在运行时创建实例属性的正确方法是什么呢?

附注:我知道在如何使用__getattribute__方法中提出了一个替代方案?


当前回答

我最近遇到了一个类似的问题,我提出的解决方案使用__getattr__和__setattr__为我想要它处理的属性,其他一切都传递给原始。

class C(object):
    def __init__(self, properties):
        self.existing = "Still Here"
        self.properties = properties

    def __getattr__(self, name):
        if "properties" in self.__dict__ and name in self.properties:
            return self.properties[name] # Or call a function, etc
        return self.__dict__[name]

    def __setattr__(self, name, value):
        if "properties" in self.__dict__ and name in self.properties:
            self.properties[name] = value
        else:
            self.__dict__[name] = value

if __name__ == "__main__":
    my_properties = {'a':1, 'b':2, 'c':3}
    c = C(my_properties)
    assert c.a == 1
    assert c.existing == "Still Here"
    c.b = 10
    assert c.properties['b'] == 10

其他回答

不确定我是否完全理解这个问题,但你可以在运行时使用类的内置__dict__修改实例属性:

class C(object):
    def __init__(self, ks, vs):
        self.__dict__ = dict(zip(ks, vs))


if __name__ == "__main__":
    ks = ['ab', 'cd']
    vs = [12, 34]
    c = C(ks, vs)
    print(c.ab) # 12

我最近遇到了一个类似的问题,我提出的解决方案使用__getattr__和__setattr__为我想要它处理的属性,其他一切都传递给原始。

class C(object):
    def __init__(self, properties):
        self.existing = "Still Here"
        self.properties = properties

    def __getattr__(self, name):
        if "properties" in self.__dict__ and name in self.properties:
            return self.properties[name] # Or call a function, etc
        return self.__dict__[name]

    def __setattr__(self, name, value):
        if "properties" in self.__dict__ and name in self.properties:
            self.properties[name] = value
        else:
            self.__dict__[name] = value

if __name__ == "__main__":
    my_properties = {'a':1, 'b':2, 'c':3}
    c = C(my_properties)
    assert c.a == 1
    assert c.existing == "Still Here"
    c.b = 10
    assert c.properties['b'] == 10

虽然给出了很多答案,但我没有找到一个让我满意的。我找到了自己的解决方案,使属性适用于动态情况。来源回答原来的问题:

#!/usr/local/bin/python3

INITS = { 'ab': 100, 'cd': 200 }

class DP(dict):
  def __init__(self):
    super().__init__()
    for k,v in INITS.items():
        self[k] = v 

def _dict_set(dp, key, value):
  dp[key] = value

for item in INITS.keys():
  setattr(
    DP,
    item,
    lambda key: property(
      lambda self: self[key], lambda self, value: _dict_set(self, key, value)
    )(item)
  )

a = DP()
print(a)  # {'ab': 100, 'cd': 200}
a.ab = 'ab100'
a.cd = False
print(a.ab, a.cd) # ab100 False

对我有用的是:

class C:
    def __init__(self):
        self._x=None

    def g(self):
        return self._x

    def s(self, x):
        self._x = x

    def d(self):
        del self._x

    def s2(self,x):
        self._x=x+x

    x=property(g,s,d)


c = C()
c.x="a"
print(c.x)

C.x=property(C.g, C.s2)
C.x=C.x.deleter(C.d)
c2 = C()
c2.x="a"
print(c2.x)

输出

a
aa

对于那些来自搜索引擎的人,这里是我在谈论动态属性时寻找的两件事:

class Foo:
    def __init__(self):
        # we can dynamically have access to the properties dict using __dict__
        self.__dict__['foo'] = 'bar'

assert Foo().foo == 'bar'


# or we can use __getattr__ and __setattr__ to execute code on set/get
class Bar:
    def __init__(self):
        self._data = {}
    def __getattr__(self, key):
        return self._data[key]
    def __setattr__(self, key, value):
        self._data[key] = value

bar = Bar()
bar.foo = 'bar'
assert bar.foo == 'bar'

如果你想放置动态创建的属性,__dict__是很好的。__getattr__只适合在需要该值时执行某些操作,例如查询数据库。set/get组合有助于简化对存储在类中的数据的访问(如上面的示例)。

如果您只想要一个动态属性,请查看property()内置函数。