假设我有一个值15.7784514,我想把它显示为15.77,没有舍入。

var num = parseFloat(15.7784514);
document.write(num.toFixed(1)+"<br />");
document.write(num.toFixed(2)+"<br />");
document.write(num.toFixed(3)+"<br />");
document.write(num.toFixed(10));

结果:

15.8
15.78
15.778
15.7784514000 

如何显示15.77?


当前回答

基于David D的回答:

function NumberFormat(num,n) {
  var num = (arguments[0] != null) ? arguments[0] : 0;
  var n = (arguments[1] != null) ? arguments[1] : 2;
  if(num > 0){
    num = String(num);
    if(num.indexOf('.') !== -1) {
      var numarr = num.split(".");
      if (numarr.length > 1) {
        if(n > 0){
          var temp = numarr[0] + ".";
          for(var i = 0; i < n; i++){
            if(i < numarr[1].length){
              temp += numarr[1].charAt(i);
            }
          }
          num = Number(temp);
        }
      }
    }
  }
  return Number(num);
}

console.log('NumberFormat(123.85,2)',NumberFormat(123.85,2));
console.log('NumberFormat(123.851,2)',NumberFormat(123.851,2));
console.log('NumberFormat(0.85,2)',NumberFormat(0.85,2));
console.log('NumberFormat(0.851,2)',NumberFormat(0.851,2));
console.log('NumberFormat(0.85156,2)',NumberFormat(0.85156,2));
console.log('NumberFormat(0.85156,4)',NumberFormat(0.85156,4));
console.log('NumberFormat(0.85156,8)',NumberFormat(0.85156,8));
console.log('NumberFormat(".85156",2)',NumberFormat(".85156",2));
console.log('NumberFormat("0.85156",2)',NumberFormat("0.85156",2));
console.log('NumberFormat("1005.85156",2)',NumberFormat("1005.85156",2));
console.log('NumberFormat("0",2)',NumberFormat("0",2));
console.log('NumberFormat("",2)',NumberFormat("",2));
console.log('NumberFormat(85156,8)',NumberFormat(85156,8));
console.log('NumberFormat("85156",2)',NumberFormat("85156",2));
console.log('NumberFormat("85156.",2)',NumberFormat("85156.",2));

// NumberFormat(123.85,2) 123.85
// NumberFormat(123.851,2) 123.85
// NumberFormat(0.85,2) 0.85
// NumberFormat(0.851,2) 0.85
// NumberFormat(0.85156,2) 0.85
// NumberFormat(0.85156,4) 0.8515
// NumberFormat(0.85156,8) 0.85156
// NumberFormat(".85156",2) 0.85
// NumberFormat("0.85156",2) 0.85
// NumberFormat("1005.85156",2) 1005.85
// NumberFormat("0",2) 0
// NumberFormat("",2) 0
// NumberFormat(85156,8) 85156
// NumberFormat("85156",2) 85156
// NumberFormat("85156.",2) 85156

其他回答

我固定使用以下简单的方法-

var num = 15.7784514;
Math.floor(num*100)/100;

结果是15.77

最有效的解决方案(对于2个分数位数)是在调用toFixed()之前减去0.005。

function toFixed2( num ) { return (num-0.005).toFixed(2) }

负数也会四舍五入(远离零)。运算符里没有提到负数。

我选择写这个来手动删除剩余的字符串,这样我就不必处理数字带来的数学问题:

num = num.toString(); //If it's not already a String
num = num.slice(0, (num.indexOf("."))+3); //With 3 exposing the hundredths place
Number(num); //If you need it back as a Number

这将得到“15.77”,其中num = 15.7784514;

function toFixed(num, fixed) {
    fixed = fixed || 0;
    var front = Math.floor(num);
    var back = 0;
    for (var i = 1; i <= fixed; i++) {
        var value = Math.floor(num * Math.pow(10, i)) % 10;
        back += value / Math.pow(10, i);
    }
    return front + back;
}

不舍入得到两个浮点数更可靠。

参考答案

VaR 数 = 10.5859; var fixed2FloatPoints = parseInt(number * 100) / 100; console.log(fixed2FloatPoints);

谢谢你!