我对PHP、JavaScript和许多其他脚本语言很有经验，但我对Java或Android没有太多经验。
我正在寻找一种方法将POST数据发送到PHP脚本并显示结果。
当前回答
这是一个如何在不使用外部Apache库的情况下POST多部分数据的例子:
byte[] buffer = getBuffer();
if(buffer.length > 0) {
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "RQdzAAihJq7Xp1kjraqf";
ByteArrayOutputStream baos = new ByteArrayOutputStream();
DataOutputStream dos = new DataOutputStream(baos);
// Send parameter #1
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"param1\"" + lineEnd);
dos.writeBytes("Content-Type: text/plain; charset=US-ASCII" + lineEnd);
dos.writeBytes("Content-Transfer-Encoding: 8bit" + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(myStringData + lineEnd);
// Send parameter #2
//dos.writeBytes(twoHyphens + boundary + lineEnd);
//dos.writeBytes("Content-Disposition: form-data; name=\"param2\"" + lineEnd + lineEnd);
//dos.writeBytes("foo2" + lineEnd);
// Send a binary file
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"param3\";filename=\"test_file.dat\"" + lineEnd);
dos.writeBytes("Content-Type: application/octet-stream" + lineEnd);
dos.writeBytes("Content-Transfer-Encoding: binary" + lineEnd);
dos.writeBytes(lineEnd);
dos.write(buffer);
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
dos.flush();
dos.close();
ByteArrayInputStream content = new ByteArrayInputStream(baos.toByteArray());
BasicHttpEntity entity = new BasicHttpEntity();
entity.setContent(content);
HttpPost httpPost = new HttpPost(myURL);
httpPost.addHeader("Connection", "Keep-Alive");
httpPost.addHeader("Content-Type", "multipart/form-data; boundary="+boundary);
//MultipartEntity entity = new MultipartEntity();
//entity.addPart("param3", new ByteArrayBody(buffer, "test_file.dat"));
//entity.addPart("param1", new StringBody(myStringData));
httpPost.setEntity(entity);
/*
String httpData = "";
ByteArrayOutputStream baos1 = new ByteArrayOutputStream();
entity.writeTo(baos1);
httpData = baos1.toString("UTF-8");
*/
/*
Header[] hdrs = httpPost.getAllHeaders();
for(Header hdr: hdrs) {
httpData += hdr.getName() + " | " + hdr.getValue() + " |_| ";
}
*/
//Log.e(TAG, "httpPost data: " + httpData);
response = httpClient.execute(httpPost);
}
其他回答
这是一个如何在不使用外部Apache库的情况下POST多部分数据的例子:
byte[] buffer = getBuffer();
if(buffer.length > 0) {
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "RQdzAAihJq7Xp1kjraqf";
ByteArrayOutputStream baos = new ByteArrayOutputStream();
DataOutputStream dos = new DataOutputStream(baos);
// Send parameter #1
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"param1\"" + lineEnd);
dos.writeBytes("Content-Type: text/plain; charset=US-ASCII" + lineEnd);
dos.writeBytes("Content-Transfer-Encoding: 8bit" + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(myStringData + lineEnd);
// Send parameter #2
//dos.writeBytes(twoHyphens + boundary + lineEnd);
//dos.writeBytes("Content-Disposition: form-data; name=\"param2\"" + lineEnd + lineEnd);
//dos.writeBytes("foo2" + lineEnd);
// Send a binary file
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"param3\";filename=\"test_file.dat\"" + lineEnd);
dos.writeBytes("Content-Type: application/octet-stream" + lineEnd);
dos.writeBytes("Content-Transfer-Encoding: binary" + lineEnd);
dos.writeBytes(lineEnd);
dos.write(buffer);
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
dos.flush();
dos.close();
ByteArrayInputStream content = new ByteArrayInputStream(baos.toByteArray());
BasicHttpEntity entity = new BasicHttpEntity();
entity.setContent(content);
HttpPost httpPost = new HttpPost(myURL);
httpPost.addHeader("Connection", "Keep-Alive");
httpPost.addHeader("Content-Type", "multipart/form-data; boundary="+boundary);
//MultipartEntity entity = new MultipartEntity();
//entity.addPart("param3", new ByteArrayBody(buffer, "test_file.dat"));
//entity.addPart("param1", new StringBody(myStringData));
httpPost.setEntity(entity);
/*
String httpData = "";
ByteArrayOutputStream baos1 = new ByteArrayOutputStream();
entity.writeTo(baos1);
httpData = baos1.toString("UTF-8");
*/
/*
Header[] hdrs = httpPost.getAllHeaders();
for(Header hdr: hdrs) {
httpData += hdr.getName() + " | " + hdr.getValue() + " |_| ";
}
*/
//Log.e(TAG, "httpPost data: " + httpData);
response = httpClient.execute(httpPost);
}
对我来说，接下来的工作是:
private sendData() {
JSONObject jsonObject = new JSONObject();
jsonObject.accumulate("key1", value1);
jsonObject.accumulate("key2", value2);
boolean success = sendPost(SERVER_URL + "/v1/auth", jsonObject);
}
private boolean sendPost(String url, JSONObject parameters) {
boolean requestResult = false;
InputStream inputStream = null;
String result = "";
try {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
String json = "";
json = parameters.toString();
StringEntity se = new StringEntity(json);
httpPost.setEntity(se);
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
HttpResponse httpResponse = httpclient.execute(httpPost);
inputStream = httpResponse.getEntity().getContent();
if (inputStream != null) {
result = convertInputStreamToString(inputStream);
requestResult = true;
} else {
result = "Did not work!";
requestResult = false;
}
System.out.println(result);
} catch (Exception e) {
Log.d("InputStream", e.getLocalizedMessage());
requestResult = false;
}
return requestResult;
}
方法将数据作为HTTP请求发布，
public static InputStream callPostService(String Url,
List<NameValuePair> data) {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(Url);
try {
httppost.setEntity(new UrlEncodedFormEntity(data));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
return entity.getContent();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
下面的方法适用于最新的Android库和使用okhttp。
OkHttpClient client = new OkHttpClient();
RequestBody formBody = new FormBody.Builder()
.add("key1", "value1")
.add("key2", "value2") //optional
.add("key3", "value3") //optional
.add("key4", "value4") //optional
.build();
Request request = new Request.Builder()
.url("http://.....") //URL
.post(formBody)
.build();
client.newCall(request).enqueue(new Callback() {
@Override
public void onFailure(@NonNull Call call, @NonNull IOException e) {
e.getStackTrace();
}
@Override
public void onResponse(@NonNull Call call, @NonNull Response response) throws IOException {
if(response.isSuccessful()){
ResponseBody responseBody = response.body();
Log.e("TAG_", responseBody.string());
}
}
您可以使用WebServer类POST一个HttpRequest，并在其侦听器接口中跟踪响应。
WebServer server=new WebServer(getApplicationContext());
server.setOnServerStatusListner(new WebServer.OnServerStatusListner() {
@Override
public void onServerResponded(String responce) {
}
@Override
public void onServerRevoked() {
}
});
现在创建一个DataRack来绑定数据
List<DataRack> racks=new ArrayList<DataRack>();
racks.add(new DataRack("name","Simon"));
racks.add(new DataRack("age","40"));
racks.add(new DataRack("location","Canada"));
现在只需发送带有该机架的POST请求
server.connectWithPOST(MainActivity.this,"http://sangeethnandakumar.esy.es/PROJECTS/PUBLIC_SERVICE/posttest.php",racks);
你需要包括我的库。文件在这里
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