private boolean hasContent(EditText et) {
       return (et.getText().toString().trim().length() > 0);
}

我曾经做过类似的事情;

EditText usernameEditText = (EditText) findViewById(R.id.editUsername);
sUsername = usernameEditText.getText().toString();
if (sUsername.matches("")) {
    Toast.makeText(this, "You did not enter a username", Toast.LENGTH_SHORT).show();
    return;
}

这个函数对我有用

private void checkForm() {
    EditText[] allFields = {
        field1_txt,
        field2_txt,
        field3_txt,
        field4_txt
    };
    
    List < EditText > ErrorFields = new ArrayList < EditText > (); 

    for (EditText edit: allFields) {
        if (TextUtils.isEmpty(edit.getText())) {

            // EditText was empty
            ErrorFields.add(edit); //add empty Edittext only in this ArayList
            
            for (int i = 0; i < ErrorFields.size(); i++) {
                EditText currentField = ErrorFields.get(i);
                currentField.setError("this field required");
                currentField.requestFocus();
            }
        }
    }
}

以下几点对我来说很有用:

if(searchText.getText().toString().equals("")) 
    Log.d("MY_LOG", "Empty");

首先，我从EditText检索文本，然后将其转换为字符串，最后使用.equals方法将其与“”进行比较。

如果EditText为空，为什么不禁用按钮呢?恕我直言，这看起来更专业:

        final EditText txtFrecuencia = (EditText) findViewById(R.id.txtFrecuencia);  
        final ToggleButton toggle = (ToggleButton) findViewById(R.id.toggleStartStop);
        txtFrecuencia.addTextChangedListener(new TextWatcher() {
        @Override
        public void afterTextChanged(Editable s) {
            toggle.setEnabled(txtFrecuencia.length() > 0);
        }

        @Override
        public void beforeTextChanged(CharSequence s, int start, int count,
                int after) {
        }

        @Override
        public void onTextChanged(CharSequence s, int start, int before,
                int count) {

        }
       });

我使用这个方法，使用trim()来避免空格:

EditText myEditText = (EditText) findViewById(R.id.editUsername);
if ("".equals(myEditText.getText().toString().trim()) {
    Toast.makeText(this, "You did not enter a value!", Toast.LENGTH_LONG).show();
    return;
}

一个例子，如果你有几个EditText´

if (("".equals(edtUser.getText().toString().trim()) || "".equals(edtPassword.getText().toString().trim()))){
        Toast.makeText(this, "a value is missing!", Toast.LENGTH_LONG).show();
        return;
}