在Linux下,如何发现哪个进程使用交换空间更多?


当前回答

我使用这个,如果你只有/proc,没有其他有用的。只需要设置nr为你想看到的顶部交换器的数量,它会告诉你进程名,交换占用空间(MB),它是ps -ef的完整进程线:

Nr =10;对于pid在$(对于文件在/proc//状态;do awk '/ vmswwap |Name|^Pid/{printf $2 "" $3}END{print ""}' $file;做|分类3 - n - r - k - $ {nr} | |头awk{打印$ 2});做awk ' / VmSwap |名称| ^ Pid / {printf 2”、“3美元}{打印”“}”结束/proc/$ Pid /状态| awk的{打印1美元”“2”“3/1024美元“m”}”| sed - e ' s /。[0 - 9]/ / g’;ps ef | awk“2美元= = $ Pid{打印}”,回声;完成

其他回答

top命令还包含一个字段,用于显示进程的页面错误数量。页面错误最多的进程是交换次数最多的进程。 对于长时间运行的守护进程,可能会在开始时产生大量的页面错误,并且这个数字在以后不会增加。所以我们需要观察页面故障是否在增加。

您可以使用Procpath(作者在这里),以简化从/proc/$PID/status解析vmswwap。

$ procpath record -f stat,cmdline,status -r 1 -d db.sqlite
$ sqlite3 -column db.sqlite \
  'SELECT status_name, status_vmswap FROM record ORDER BY status_vmswap DESC LIMIT 5'
Web Content  192136       
okular       186872       
thunderbird  183692       
Web Content  143404       
MainThread   86300

您还可以像这样绘制感兴趣的进程的vmswwap。在这里,我正在记录Firefox进程树,同时打开几十个选项卡,并启动一个占用大量内存的应用程序,试图导致它进行交换(这对Firefox来说并不令人信服,但您的情况可能不同)。

$ procpath record -f stat,cmdline,status -i 1 -d db2.sqlite \
  '$..children[?(@.stat.pid == 6029)]'
# interrupt by Ctrl+C
$ procpath plot -d db2.sqlite -q cpu --custom-value-expr status_vmswap \
  --title "CPU usage, % vs Swap, kB"

这是脚本的另一个变体,但意味着提供更可读的输出(你需要以根用户身份运行这个脚本才能得到准确的结果):

#!/bin/bash

    # find-out-what-is-using-your-swap.sh
    # -- Get current swap usage for all running processes
    # --
    # -- rev.0.3, 2012-09-03, Jan Smid          - alignment and intendation, sorting
    # -- rev.0.2, 2012-08-09, Mikko Rantalainen - pipe the output to "sort -nk3" to get sorted output
    # -- rev.0.1, 2011-05-27, Erik Ljungstrom   - initial version


SCRIPT_NAME=`basename $0`;
SORT="kb";                 # {pid|kB|name} as first parameter, [default: kb]
[ "$1" != "" ] && { SORT="$1"; }

[ ! -x `which mktemp` ] && { echo "ERROR: mktemp is not available!"; exit; }
MKTEMP=`which mktemp`;
TMP=`${MKTEMP} -d`;
[ ! -d "${TMP}" ] && { echo "ERROR: unable to create temp dir!"; exit; }

>${TMP}/${SCRIPT_NAME}.pid;
>${TMP}/${SCRIPT_NAME}.kb;
>${TMP}/${SCRIPT_NAME}.name;

SUM=0;
OVERALL=0;
    echo "${OVERALL}" > ${TMP}/${SCRIPT_NAME}.overal;

for DIR in `find /proc/ -maxdepth 1 -type d -regex "^/proc/[0-9]+"`;
do
    PID=`echo $DIR | cut -d / -f 3`
    PROGNAME=`ps -p $PID -o comm --no-headers`

    for SWAP in `grep Swap $DIR/smaps 2>/dev/null| awk '{ print $2 }'`
    do
        let SUM=$SUM+$SWAP
    done

    if (( $SUM > 0 ));
    then
        echo -n ".";
        echo -e "${PID}\t${SUM}\t${PROGNAME}" >> ${TMP}/${SCRIPT_NAME}.pid;
        echo -e "${SUM}\t${PID}\t${PROGNAME}" >> ${TMP}/${SCRIPT_NAME}.kb;
        echo -e "${PROGNAME}\t${SUM}\t${PID}" >> ${TMP}/${SCRIPT_NAME}.name;
    fi
    let OVERALL=$OVERALL+$SUM
    SUM=0
done
echo "${OVERALL}" > ${TMP}/${SCRIPT_NAME}.overal;
echo;
echo "Overall swap used: ${OVERALL} kB";
echo "========================================";
case "${SORT}" in
    name )
        echo -e "name\tkB\tpid";
        echo "========================================";
        cat ${TMP}/${SCRIPT_NAME}.name|sort -r;
        ;;

    kb )
        echo -e "kB\tpid\tname";
        echo "========================================";
        cat ${TMP}/${SCRIPT_NAME}.kb|sort -rh;
        ;;

    pid | * )
        echo -e "pid\tkB\tname";
        echo "========================================";
        cat ${TMP}/${SCRIPT_NAME}.pid|sort -rh;
        ;;
esac
rm -fR "${TMP}/";

这是我的一句话:

cat /proc/*/status | grep -E 'VmSwap:|Name:' | grep VmSwap -B1 | cut -d':' -f2 | grep -v '\-\-' | grep -o -E '[a-zA-Z0-9]+.*$' | cut -d' ' -f1 | xargs -n2 echo | sort -k2 -n

这一行的步骤是:

Get all the data in /proc/process/status for all processes Select the fields VmSwap and Name for each Remove the processes that don't have the VmSwap field Remove the names of the fields (VmSwap: and Name:) Remove lines with -- that were added by the previous step Remove the spaces at the start of the lines Remove the second part of each process name and " kB" after the swap usage number Take name and number (process name and swap usage) and put them in one line, one after the other Sort the lines by the swap usage

我在网上改编了一个不同的脚本来写这句长单句:

 { date;for f in /proc/[0-9]*/status; do 
   awk '{k[$1]=$2} END { if (k["VmSwap:"]) print k["Pid:"],k["Name:"],k["VmSwap:"];}' $f 2>/dev/null; 
   done | sort -n ; }

然后我将其扔进cronjob并将输出重定向到日志文件。这里的信息与在smaps文件中积累Swap:条目相同,但如果你想确定,你可以使用:

{ date;for m in /proc/*/smaps;do 
  awk '/^Swap/ {s+=$2} END { if (s) print FILENAME,s }' $m 2>/dev/null;
  done | tr -dc ' [0-9]\n' |sort -k 1n; }

这个版本的输出有两列:pid,交换量。在上面的版本中,tr删除非数值组件。在这两种情况下,输出都是按照pid数值排序的。