在Link react-router中传递道具

我正在使用react和react-router。我试图在反应路由器的“链接”中传递属性

var React  = require('react');
var Router = require('react-router');
var CreateIdeaView = require('./components/createIdeaView.jsx');

var Link = Router.Link;
var Route = Router.Route;
var DefaultRoute = Router.DefaultRoute;
var RouteHandler = Router.RouteHandler;
var App = React.createClass({
  render : function(){
    return(
      <div>
        <Link to="ideas" params={{ testvalue: "hello" }}>Create Idea</Link>
        <RouteHandler/>
      </div>
    );
  }
});

var routes = (
  <Route name="app" path="/" handler={App}>
    <Route name="ideas" handler={CreateIdeaView} />
    <DefaultRoute handler={Home} />
  </Route>
);

Router.run(routes, function(Handler) {

  React.render(<Handler />, document.getElementById('main'))
});

“Link”呈现页面，但不将属性传递给新视图。下面是视图代码

var React = require('react');
var Router = require('react-router');

var CreateIdeaView = React.createClass({
  render : function(){
    console.log('props form link',this.props,this)//props not recived
  return(
      <div>
        <h1>Create Post: </h1>
        <input type='text' ref='newIdeaTitle' placeholder='title'></input>
        <input type='text' ref='newIdeaBody' placeholder='body'></input>
      </div>
    );
  }
});

module.exports = CreateIdeaView;

如何使用“链接”传递数据?

当前回答

更新25-11-21 感谢alexadestech。Mx在上面写道。我能够转移整个对象，并从中抽出所有必要的字段在send-component中:

<Button type="submit" component={NavLink} to={{
        pathname: '/basequestion',
        state: {question} }}
        variant="contained"
        size="small">Take test</Button>

在receive-component:

import { useLocation } from "react-router"
const BaseQuestion = () => {
const location = useLocation();
const {description, title, images} = (location.state.question);

2021-11-25 14:25:32

其他回答

在我的情况下，我有一个空道具的功能组件，这解决了它:

<Link
  to={{
    pathname: `/dashboard/${device.device_id}`,
    state: { device },
  }}
>
  View Dashboard
</Link>

在你的函数组件中，你应该有这样的东西:

import { useLocation } from "react-router"
export default function Dashboard() {
  const location = useLocation()
  console.log(location.state)
  return <h1>{`Hello, I'm device ${location.state.device.device_id}!`}</h1>
}

2021-09-25 17:31:47

为了解决上面的问题(https://stackoverflow.com/a/44860918/2011818)，您还可以在Link对象的“To”中发送对象。

<Route path="/foo/:fooId" component={foo} / >

<Link to={{pathname:/foo/newb, sampleParam: "Hello", sampleParam2: "World!" }}> CLICK HERE </Link>

this.props.match.params.fooId //newb
this.props.location.sampleParam //"Hello"
this.props.location.sampleParam2 //"World!"

2019-09-16 04:56:32

我为此挣扎了几个小时，没有一个答案对我有用。最后，我设法在文档中找到了React Router 6的解决方案。

下面是完整的例子:

// App.js

<BrowserRouter>
    <Routes>
        <Route path="/books/:bookId" element={ <BookDetails /> } />
    </Routes>
</BrowserRouter>

// BookDetails.js

import React from "react"
import { useParams } from "react-router-dom"

export default function BookPage() {
    const params = useParams()
    return <div> { console.log(params.bookId) } </div>
}

注意，useParams不能在类组件中调用，因此必须使用函数组件(详细信息请参阅此回答)。

2021-12-09 22:40:03

至于react-router-dom 4.x。X (https://www.npmjs.com/package/react-router-dom)你可以传递参数给组件路由到via:

<Route path="/ideas/:value" component ={CreateIdeaView} />

通过(考虑testValue道具被传递给相应的组件(例如上面的App组件)来呈现链接)

<Link to={`/ideas/${ this.props.testValue }`}>Create Idea</Link>

将道具传递给组件构造函数，值参数将通过

props.match.params.value

2017-04-26 15:30:53

路线:

<Route state={this.state} exact path="/customers/:id" render={(props) => <PageCustomer {...props} state={this.state} />} />

然后可以像这样访问PageCustomer组件中的参数:

例如，PageCustomer组件中的api调用:

axios({
   method: 'get',
   url: '/api/customers/' + this.props.match.params.id,
   data: {},
   headers: {'X-Requested-With': 'XMLHttpRequest'}
 })

2019-01-02 13:57:59

在Link react-router中传递道具

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