我想用JavaScript格式化价格。我想要一个函数,它将浮点作为参数,并返回如下格式的字符串:
"$ 2,500.00"
我该怎么做?
我想用JavaScript格式化价格。我想要一个函数,它将浮点作为参数,并返回如下格式的字符串:
"$ 2,500.00"
我该怎么做?
当前回答
http://code.google.com/p/javascript-number-formatter/:
短、快、灵活但独立。只有75行,包括MIT许可证信息、空白行和注释。接受标准数字格式,如#、##0.00或带否定的-000.####。接受任何国家/地区格式,如###0,00,#,###.##,#‘###.##或任何类型的非编号符号。接受任意数字分组。#、##、#0.000或#、####0.##均有效。接受任何冗余/防傻瓜格式。##、###、##。#或0#、#00####0#都正常。自动数字舍入。简单的界面,只需提供如下掩码和值:格式(“0.0000”,3.141592)
UPDATE这是我自己开发的应用程序,用于最常见的任务:
var NumUtil = {};
/**
Petty print 'num' wth exactly 'signif' digits.
pp(123.45, 2) == "120"
pp(0.012343, 3) == "0.0123"
pp(1.2, 3) == "1.20"
*/
NumUtil.pp = function(num, signif) {
if (typeof(num) !== "number")
throw 'NumUtil.pp: num is not a number!';
if (isNaN(num))
throw 'NumUtil.pp: num is NaN!';
if (num < 1e-15 || num > 1e15)
return num;
var r = Math.log(num)/Math.LN10;
var dot = Math.floor(r) - (signif-1);
r = r - Math.floor(r) + (signif-1);
r = Math.round(Math.exp(r * Math.LN10)).toString();
if (dot >= 0) {
for (; dot > 0; dot -= 1)
r += "0";
return r;
} else if (-dot >= r.length) {
var p = "0.";
for (; -dot > r.length; dot += 1) {
p += "0";
}
return p+r;
} else {
return r.substring(0, r.length + dot) + "." + r.substring(r.length + dot);
}
}
/** Append leading zeros up to 2 digits. */
NumUtil.align2 = function(v) {
if (v < 10)
return "0"+v;
return ""+v;
}
/** Append leading zeros up to 3 digits. */
NumUtil.align3 = function(v) {
if (v < 10)
return "00"+v;
else if (v < 100)
return "0"+v;
return ""+v;
}
NumUtil.integer = {};
/** Round to integer and group by 3 digits. */
NumUtil.integer.pp = function(num) {
if (typeof(num) !== "number") {
console.log("%s", new Error().stack);
throw 'NumUtil.integer.pp: num is not a number!';
}
if (isNaN(num))
throw 'NumUtil.integer.pp: num is NaN!';
if (num > 1e15)
return num;
if (num < 0)
throw 'Negative num!';
num = Math.round(num);
var group = num % 1000;
var integ = Math.floor(num / 1000);
if (integ === 0) {
return group;
}
num = NumUtil.align3(group);
while (true) {
group = integ % 1000;
integ = Math.floor(integ / 1000);
if (integ === 0)
return group + " " + num;
num = NumUtil.align3(group) + " " + num;
}
return num;
}
NumUtil.currency = {};
/** Round to coins and group by 3 digits. */
NumUtil.currency.pp = function(amount) {
if (typeof(amount) !== "number")
throw 'NumUtil.currency.pp: amount is not a number!';
if (isNaN(amount))
throw 'NumUtil.currency.pp: amount is NaN!';
if (amount > 1e15)
return amount;
if (amount < 0)
throw 'Negative amount!';
if (amount < 1e-2)
return 0;
var v = Math.round(amount*100);
var integ = Math.floor(v / 100);
var frac = NumUtil.align2(v % 100);
var group = integ % 1000;
integ = Math.floor(integ / 1000);
if (integ === 0) {
return group + "." + frac;
}
amount = NumUtil.align3(group);
while (true) {
group = integ % 1000;
integ = Math.floor(integ / 1000);
if (integ === 0)
return group + " " + amount + "." + frac;
amount = NumUtil.align3(group) + " " + amount;
}
return amount;
}
其他回答
+1向Jonathan M提供原始方法。由于这是一个明确的货币格式化程序,我继续在输出中添加了货币符号(默认为“$”),并添加了一个默认逗号作为千位分隔符。如果您实际上不需要货币符号(或千位分隔符),只需使用“”(空字符串)作为它的参数。
Number.prototype.formatMoney = function(decPlaces, thouSeparator, decSeparator, currencySymbol) {
// check the args and supply defaults:
decPlaces = isNaN(decPlaces = Math.abs(decPlaces)) ? 2 : decPlaces;
decSeparator = decSeparator == undefined ? "." : decSeparator;
thouSeparator = thouSeparator == undefined ? "," : thouSeparator;
currencySymbol = currencySymbol == undefined ? "$" : currencySymbol;
var n = this,
sign = n < 0 ? "-" : "",
i = parseInt(n = Math.abs(+n || 0).toFixed(decPlaces)) + "",
j = (j = i.length) > 3 ? j % 3 : 0;
return sign + currencySymbol + (j ? i.substr(0, j) + thouSeparator : "") + i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + thouSeparator) + (decPlaces ? decSeparator + Math.abs(n - i).toFixed(decPlaces).slice(2) : "");
};
这可能奏效:
function format_currency(v, number_of_decimals, decimal_separator, currency_sign){
return (isNaN(v)? v : currency_sign + parseInt(v||0).toLocaleString() + decimal_separator + (v*1).toFixed(number_of_decimals).slice(-number_of_decimals));
}
没有循环,没有正则表达式,没有数组,没有奇异条件。
String.prototype.toPrice = function () {
var v;
if (/^\d+(,\d+)$/.test(this))
v = this.replace(/,/, '.');
else if (/^\d+((,\d{3})*(\.\d+)?)?$/.test(this))
v = this.replace(/,/g, "");
else if (/^\d+((.\d{3})*(,\d+)?)?$/.test(this))
v = this.replace(/\./g, "").replace(/,/, ".");
var x = parseFloat(v).toFixed(2).toString().split("."),
x1 = x[0],
x2 = ((x.length == 2) ? "." + x[1] : ".00"),
exp = /^([0-9]+)(\d{3})/;
while (exp.test(x1))
x1 = x1.replace(exp, "$1" + "," + "$2");
return x1 + x2;
}
alert("123123".toPrice()); //123,123.00
alert("123123,316".toPrice()); //123,123.32
alert("12,312,313.33213".toPrice()); //12,312,313.33
alert("123.312.321,32132".toPrice()); //123,312,321.32
快速快捷的解决方案(适用于任何地方!)
(12345.67).toFixed(2).replace(/\d(?=(\d{3})+\.)/g, '$&,'); // 12,345.67
此解决方案背后的思想是用第一个匹配和逗号替换匹配的部分,即“$&,”。匹配是使用前瞻方法完成的。您可以将表达式读为“匹配一个数字,如果它后面跟着三个数字集(一个或多个)和一个点的序列”。
测验:
1 --> "1.00"
12 --> "12.00"
123 --> "123.00"
1234 --> "1,234.00"
12345 --> "12,345.00"
123456 --> "123,456.00"
1234567 --> "1,234,567.00"
12345.67 --> "12,345.67"
演示:http://jsfiddle.net/hAfMM/9571/
扩展短解决方案
您还可以扩展Number对象的原型,以添加对任意数量的小数[0..n]和数字组大小[0..x]的额外支持:
/**
* Number.prototype.format(n, x)
*
* @param integer n: length of decimal
* @param integer x: length of sections
*/
Number.prototype.format = function(n, x) {
var re = '\\d(?=(\\d{' + (x || 3) + '})+' + (n > 0 ? '\\.' : '$') + ')';
return this.toFixed(Math.max(0, ~~n)).replace(new RegExp(re, 'g'), '$&,');
};
1234..format(); // "1,234"
12345..format(2); // "12,345.00"
123456.7.format(3, 2); // "12,34,56.700"
123456.789.format(2, 4); // "12,3456.79"
演示/测试:http://jsfiddle.net/hAfMM/435/
超扩展短解决方案
在此超级扩展版本中,您可以设置不同的分隔符类型:
/**
* Number.prototype.format(n, x, s, c)
*
* @param integer n: length of decimal
* @param integer x: length of whole part
* @param mixed s: sections delimiter
* @param mixed c: decimal delimiter
*/
Number.prototype.format = function(n, x, s, c) {
var re = '\\d(?=(\\d{' + (x || 3) + '})+' + (n > 0 ? '\\D' : '$') + ')',
num = this.toFixed(Math.max(0, ~~n));
return (c ? num.replace('.', c) : num).replace(new RegExp(re, 'g'), '$&' + (s || ','));
};
12345678.9.format(2, 3, '.', ','); // "12.345.678,90"
123456.789.format(4, 4, ' ', ':'); // "12 3456:7890"
12345678.9.format(0, 3, '-'); // "12-345-679"
演示/测试:http://jsfiddle.net/hAfMM/612/
已经有好的答案了。这里有一个简单的乐趣尝试:
function currencyFormat(no) {
var ar = (+no).toFixed(2).split('.');
return [
numberFormat(ar[0] | 0),
'.',
ar[1]
].join('');
}
function numberFormat(no) {
var str = no + '';
var ar = [];
var i = str.length -1;
while(i >= 0) {
ar.push((str[i-2] || '') + (str[i-1] || '') + (str[i] || ''));
i = i-3;
}
return ar.reverse().join(',');
}
然后运行一些示例:
console.log(
currencyFormat(1),
currencyFormat(1200),
currencyFormat(123),
currencyFormat(9870000),
currencyFormat(12345),
currencyFormat(123456.232)
)