我想用JavaScript格式化价格。我想要一个函数,它将浮点作为参数,并返回如下格式的字符串:
"$ 2,500.00"
我该怎么做?
我想用JavaScript格式化价格。我想要一个函数,它将浮点作为参数,并返回如下格式的字符串:
"$ 2,500.00"
我该怎么做?
当前回答
因为每个问题都需要单线解决方案:
Number.prototype.formatCurrency = function() { return this.toFixed(2).toString().split(/[-.]/).reverse().reduceRight(function (t, c, i) { return (i == 2) ? '-' + t : (i == 1) ? t + c.replace(/(\d)(?=(\d{3})+$)/g, '$1,') : t + '.' + c; }, '$'); }
这很容易针对不同的地区进行更改。只需将“$1”更改为“$1.”和“.”转换为“”、“”和。以数字表示。可以通过更改末尾的“$”来更改货币符号。
或者,如果您有ES6,您可以使用默认值声明函数:
Number.prototype.formatCurrency = function(thou = ',', dec = '.', sym = '$') { return this.toFixed(2).toString().split(/[-.]/).reverse().reduceRight(function (t, c, i) { return (i == 2) ? '-' + t : (i == 1) ? t + c.replace(/(\d)(?=(\d{3})+$)/g, '$1' + thou) : t + dec + c; }, sym); }
console.log((4215.57).formatCurrency())
$4,215.57
console.log((4216635.57).formatCurrency('.', ','))
$4.216.635,57
console.log((4216635.57).formatCurrency('.', ',', "\u20AC"))
€4.216.635,57
哦,它也适用于负数:
console.log((-6635.574).formatCurrency('.', ',', "\u20AC"))
-€6.635,57
console.log((-1066.507).formatCurrency())
-$1,066.51
当然,你不必有货币符号:
console.log((1234.586).formatCurrency(',','.',''))
1,234.59
console.log((-7890123.456).formatCurrency(',','.',''))
-7,890,123.46
console.log((1237890.456).formatCurrency('.',',',''))
1.237.890,46
其他回答
function CurrencyFormatted(amount)
{
var i = parseFloat(amount);
if(isNaN(i)) { i = 0.00; }
var minus = '';
if(i < 0) { minus = '-'; }
i = Math.abs(i);
i = parseInt((i + .005) * 100);
i = i / 100;
s = new String(i);
if(s.indexOf('.') < 0) { s += '.00'; }
if(s.indexOf('.') == (s.length - 2)) { s += '0'; }
s = minus + s;
return s;
}
来自WillMaster。
另一种方式:
function centsToDollaString(x){
var cents = x + ""
while(cents.length < 4){
cents = "0" + cents;
}
var dollars = cents.substr(0,cents.length - 2)
var decimal = cents.substr(cents.length - 2, 2)
while(dollars.length % 3 != 0){
dollars = "0" + dollars;
}
str = dollars.replace(/(\d{3})(?=\d)/g, "$1" + ",").replace(/^0*(?=.)/, "");
return "$" + str + "." + decimal;
}
乔纳森·M的代码对我来说太复杂了,所以我重写了它,在Firefox v30上获得了30%的速度提升,在Chrome v35上获得了60%的速度提升(http://jsperf.com/number-formating2):
Number.prototype.formatNumber = function(decPlaces, thouSeparator, decSeparator) {
decPlaces = isNaN(decPlaces = Math.abs(decPlaces)) ? 2 : decPlaces;
decSeparator = decSeparator == undefined ? "." : decSeparator;
thouSeparator = thouSeparator == undefined ? "," : thouSeparator;
var n = this.toFixed(decPlaces);
if (decPlaces) {
var i = n.substr(0, n.length - (decPlaces + 1));
var j = decSeparator + n.substr(-decPlaces);
} else {
i = n;
j = '';
}
function reverse(str) {
var sr = '';
for (var l = str.length - 1; l >= 0; l--) {
sr += str.charAt(l);
}
return sr;
}
if (parseInt(i)) {
i = reverse(reverse(i).replace(/(\d{3})(?=\d)/g, "$1" + thouSeparator));
}
return i + j;
};
用法:
var sum = 123456789.5698;
var formatted = '$' + sum.formatNumber(2, ',', '.'); // "$123,456,789.57"
这里有一个普通JavaScript的简单格式化程序:
function numberFormatter (num) {
console.log(num)
var wholeAndDecimal = String(num.toFixed(2)).split(".");
console.log(wholeAndDecimal)
var reversedWholeNumber = Array.from(wholeAndDecimal[0]).reverse();
var formattedOutput = [];
reversedWholeNumber.forEach( (digit, index) => {
formattedOutput.push(digit);
if ((index + 1) % 3 === 0 && index < reversedWholeNumber.length - 1) {
formattedOutput.push(",");
}
})
formattedOutput = formattedOutput.reverse().join('') + "." + wholeAndDecimal[1];
return formattedOutput;
}
在将PHP number_format()转换为javascript之后,这对我很有用
function number_format(number, decimals = 0, dec_point = ".",thousands_sep = ",") {
number = (number + '').replace(/[^0-9+\-Ee.]/g, '');
var n = !isFinite(+number) ? 0 : +number,
prec = !isFinite(+decimals) ? 0 : Math.abs(decimals),
s = '',
toFixedFix = function(n, prec)
{
var k = Math.pow(10, prec);
return '' + (Math.round(n * k) / k).toFixed(prec);
};
// Fix for IE parseFloat(0.55).toFixed(0) = 0;
s = (prec ? toFixedFix(n, prec) : '' +
Math.round(n)).split('.');
if (s[0].length > 3)
{
s[0] = s[0].replace(/\B(?=(?:\d{3})+(?!\d))/g,
thousands_sep);
}
if ((s[1] || '').length < prec)
{
s[1] = s[1] || '';
s[1] += new Array(prec - s[1].length + 1).join('0');
}
return s.join(dec_point);
}