Table1 (id, name) Table2 (id, name)

查询:

SELECT name   
FROM table2  
-- that are not in table1 already

当前回答

你可以在mssql中使用EXCEPT或在oracle中使用MINUS,它们是相同的:

http://blog.sqlauthority.com/2008/08/07/sql-server-except-clause-in-sql-server-is-similar-to-minus-clause-in-oracle/

其他回答

你可以在mssql中使用EXCEPT或在oracle中使用MINUS,它们是相同的:

http://blog.sqlauthority.com/2008/08/07/sql-server-except-clause-in-sql-server-is-similar-to-minus-clause-in-oracle/

小心陷阱。如果表1中的字段Name包含null,你就会感到惊讶。 更好的是:

SELECT name
FROM table2
WHERE name NOT IN
    (SELECT ISNULL(name ,'')
     FROM table1)

我尝试了以上所有的解决方案,但它们都不适合我。下面的查询对我有用。

SELECT NAME
FROM   table_1
WHERE  NAME NOT IN
       (SELECT    a.NAME
        FROM      table_1 AS a
        LEFT JOIN table_2 AS b
        ON        a.NAME = b.NAME
        WHERE     any further condition);

首先定义表的别名,如t1和t2。 然后得到第二个表的记录。 然后使用where条件匹配记录:

SELECT name FROM table2 as t2
WHERE NOT EXISTS (SELECT * FROM table1 as t1 WHERE t1.name = t2.name)

那对我来说很有用

SELECT * 
FROM [dbo].[table1] t1
LEFT JOIN [dbo].[table2] t2 ON t1.[t1_ID] = t2.[t2_ID]
WHERE t2.[t2_ID] IS NULL