使用下划线的属性或propertyOf:

Var检验= { foo: { 酒吧:{ 记者:“你好” ｝ ｝ ｝ Var字符串= 'foo.bar.baz'; / / document . write (_.propertyOf(测试)(string.split (' . '))) document . write (_.property (string.split(' . '))(测试); < script src = " https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.9.1/underscore-min.js " > < /脚本>

祝你好运…

在这里我提供了更多的方法，这些方法在很多方面看起来都更快:

选项1:Split string on。Or [Or] Or ' Or "，颠倒过来，跳过空项。

function getValue(path, origin) {
    if (origin === void 0 || origin === null) origin = self ? self : this;
    if (typeof path !== 'string') path = '' + path;
    var parts = path.split(/\[|\]|\.|'|"/g).reverse(), name; // (why reverse? because it's usually faster to pop off the end of an array)
    while (parts.length) { name=parts.pop(); if (name) origin=origin[name]; }
    return origin;
}

选项2(最快的，除了eval):低级字符扫描(没有regex/split/等等，只是一个快速字符扫描)。 注意:该命令不支持索引引用。

function getValue(path, origin) {
    if (origin === void 0 || origin === null) origin = self ? self : this;
    if (typeof path !== 'string') path = '' + path;
    var c = '', pc, i = 0, n = path.length, name = '';
    if (n) while (i<=n) ((c = path[i++]) == '.' || c == '[' || c == ']' || c == void 0) ? (name?(origin = origin[name], name = ''):(pc=='.'||pc=='['||pc==']'&&c==']'?i=n+2:void 0),pc=c) : name += c;
    if (i==n+2) throw "Invalid path: "+path;
    return origin;
} // (around 1,000,000+/- ops/sec)

选项3:(新:选项2扩展到支持引号-有点慢，但仍然很快)

function getValue(path, origin) {
    if (origin === void 0 || origin === null) origin = self ? self : this;
    if (typeof path !== 'string') path = '' + path;
    var c, pc, i = 0, n = path.length, name = '', q;
    while (i<=n)
        ((c = path[i++]) == '.' || c == '[' || c == ']' || c == "'" || c == '"' || c == void 0) ? (c==q&&path[i]==']'?q='':q?name+=c:name?(origin?origin=origin[name]:i=n+2,name='') : (pc=='['&&(c=='"'||c=="'")?q=c:pc=='.'||pc=='['||pc==']'&&c==']'||pc=='"'||pc=="'"?i=n+2:void 0), pc=c) : name += c;
    if (i==n+2 || name) throw "Invalid path: "+path;
    return origin;
}

JSPerf： http://jsperf.com/ways-to-dereference-a-delimited-property-string/3

"eval(...)" is still king though (performance wise that is). If you have property paths directly under your control, there shouldn't be any issues with using 'eval' (especially if speed is desired). If pulling property paths "over the wire" (on the line!? lol :P), then yes, use something else to be safe. Only an idiot would say to never use "eval" at all, as there ARE good reasons when to use it. Also, "It is used in Doug Crockford's JSON parser." If the input is safe, then no problems at all. Use the right tool for the right job, that's it.

也适用于对象内的数组/数组。 防御无效值。

/** * Retrieve nested item from object/array * @param {Object|Array} obj * @param {String} path dot separated * @param {*} def default value ( if result undefined ) * @returns {*} */ function path(obj, path, def){ var i, len; for(i = 0,path = path.split('.'), len = path.length; i < len; i++){ if(!obj || typeof obj !== 'object') return def; obj = obj[path[i]]; } if(obj === undefined) return def; return obj; } ////////////////////////// // TEST // ////////////////////////// var arr = [true, {'sp ace': true}, true] var obj = { 'sp ace': true, arr: arr, nested: {'dotted.str.ing': true}, arr3: arr } shouldThrow(`path(obj, "arr.0")`); shouldBeDefined(`path(obj, "arr[0]")`); shouldBeEqualToNumber(`path(obj, "arr.length")`, 3); shouldBeTrue(`path(obj, "sp ace")`); shouldBeEqualToString(`path(obj, "none.existed.prop", "fallback")`, "fallback"); shouldBeTrue(`path(obj, "nested['dotted.str.ing'])`); <script src="https://cdn.rawgit.com/coderek/e7b30bac7634a50ad8fd/raw/174b6634c8f57aa8aac0716c5b7b2a7098e03584/js-test.js"></script>

如果您想要一个能够正确检测和报告路径解析的任何问题的详细信息的解决方案，我为此编写了自己的解决方案——库路径-值。

const {resolveValue} = require('path-value');

resolveValue(someObject, 'part1.name'); //=> Part 1
resolveValue(someObject, 'part2.qty'); //=> 50
resolveValue(someObject, 'part3.0.name'); //=> Part 3A

请注意，对于索引，我们使用.0，而不是[0]，因为解析后者会增加性能损失，而.0直接在JavaScript中工作，因此非常快。

然而，完整的ES5 JavaScript语法也被支持，它只需要首先被标记化:

const {resolveValue, tokenizePath} = require('path-value');

const path = tokenizePath('part3[0].name'); //=> ['part3', '0', 'name']

resolveValue(someObject, path); //=> Part 3A

根据阿尔尼塔克的回答。

我把填充材料包在格子里，将函数简化为单链还原。

如果对象。byPath === undefined) { 对象。byPath = (obj, path) =>路径 .replace (/ \ [(\ w +) \] / g, 1美元。) .replace(/ ^ \。/”) .split (/ \ / g)。 .reduce((ref, key) => key in ref ?Ref [key]: Ref, obj) ｝ Const data = { foo: { 酒吧:[{ 记者:1 }) ｝ ｝ console.log(对象。小路(数据,foo.bar [0] .baz '))

请注意，以下选项并不适用于所有有效的unicode属性名(但据我所知，其他选项也不适用)。

const PATTERN = /[\^|\[|\.]([$|\w]+)/gu function propValue(o, s) { const names = [] for(let [, name] of [...s.matchAll(PATTERN)]) names.push(name) return names.reduce((p, propName) => { if(!p.hasOwnProperty(propName)) throw 'invalid property name' return p[propName] }, o) } let path = 'myObject.1._property2[0][0].$property3' let o = { 1: { _property2: [ [{ $property3: 'Hello World' }] ] } } console.log(propValue(o, path)) // 'Hello World'