斯威夫特的版本。也许能帮到别人。

class TextField: UITextField {
   override var placeholder: String? {
        didSet {
            let placeholderString = NSAttributedString(string: placeholder!, attributes: [NSForegroundColorAttributeName: UIColor.whiteColor()])
            self.attributedPlaceholder = placeholderString
        }
    }
}

[txt_field setValue:ColorFromHEX(@"#525252") forKeyPath:@"_placeholderLabel.textColor"];

你可以重写drawPlaceholderInRect:(CGRect)rect来手动渲染占位符文本:

- (void) drawPlaceholderInRect:(CGRect)rect {
    [[UIColor blueColor] setFill];
    [[self placeholder] drawInRect:rect withFont:[UIFont systemFontOfSize:16]];
}

我需要保持占位符的对齐，这样亚当的答案对我来说就不够了。

为了解决这个问题，我使用了一个小的变化，我希望也能帮助到你们:

- (void) drawPlaceholderInRect:(CGRect)rect {
    //search field placeholder color
    UIColor* color = [UIColor whiteColor];

    [color setFill];
    [self.placeholder drawInRect:rect withFont:self.font lineBreakMode:UILineBreakModeTailTruncation alignment:self.textAlignment];
}

小心谨慎。

let attributes = [ NSAttributedString.Key.foregroundColor: UIColor.someColor ]
let placeHolderString = NSAttributedString(string: "DON'T_DELETE", attributes: attributes)
txtField.attributedPlaceholder = placeHolderString

需要注意的是，你必须在“DON'T_DELETE”所在的地方输入一个非空字符串，即使该字符串在其他地方的代码中设置了。也许能帮你省下五分钟的脑筋。

如果子类化你必须做layoutSubviews(不是在init) 奇怪的是，你不需要清除正常的占位符。如果你使用带属性的占位符，它知道不绘制占位符。

迅速:

if let placeholder = yourTextField.placeholder {
    yourTextField.attributedPlaceholder = NSAttributedString(string:placeholder, 
        attributes: [NSForegroundColorAttributeName: UIColor.blackColor()])
}

在Swift 4.0中:

if let placeholder = yourTextField.placeholder {
    yourTextField.attributedPlaceholder = NSAttributedString(string:placeholder, 
        attributes: [NSAttributedStringKey.foregroundColor: UIColor.black])
}