我试着:

somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray.push(anotherarray.flatten!)

我预期的

["some", "thing", "another", "thing"]

但有

["some", "thing", nil]

当前回答

a = ["some", "thing"]
b = ["another", "thing"]

将b追加到a并将结果存储在a中:

a.push(*b)

or

a += b

在这两种情况下,a都变成:

["some", "thing", "another", "thing"]

但在前一种情况下,b的元素被追加到现有的a数组中,在后一种情况下,两个数组连接在一起,结果存储在a中。

其他回答

somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray + anotherarray # => ["some", "thing", "another", "thing"]
somearray.concat anotherarray # => ["some", "thing", "another", "thing"]
somearray.push(anotherarray).flatten # => ["some", "thing", "another", "thing"]
somearray.push *anotherarray # => ["another", "thing", "another", "thing"]
 

我发现更容易推入或追加数组,然后将它们压平,如下所示:

somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray.push anotherarray # => ["some", "thing", ["another", "thing"]]
#or
somearray << anotherarray # => ["some", "thing", ["another", "thing"]]
somearray.flatten!  # => ["some", "thing", "another", "thing"]
somearray # => ["some", "thing", "another", "thing"]

Somearray = ["some", "thing"]

Anotherarray = ["another", "thing"]

Somearray + anotherarray

如果新数据可以是数组或标量,并且如果它是数组,则希望防止新数据嵌套,splat操作符非常棒!它为标量返回一个标量,为数组返回一个已解压的参数列表。

1.9.3-p551 :020 > a = [1, 2]
 => [1, 2] 
1.9.3-p551 :021 > b = [3, 4]
 => [3, 4] 
1.9.3-p551 :022 > c = 5
 => 5 
1.9.3-p551 :023 > a.object_id
 => 6617020 
1.9.3-p551 :024 > a.push *b
 => [1, 2, 3, 4] 
1.9.3-p551 :025 > a.object_id
 => 6617020 
1.9.3-p551 :026 > a.push *c
 => [1, 2, 3, 4, 5] 
1.9.3-p551 :027 > a.object_id
 => 6617020 
a = ["some", "thing"]
b = ["another", "thing"]

将b追加到a并将结果存储在a中:

a.push(*b)

or

a += b

在这两种情况下,a都变成:

["some", "thing", "another", "thing"]

但在前一种情况下,b的元素被追加到现有的a数组中,在后一种情况下,两个数组连接在一起,结果存储在a中。