我对Python和多线程编程非常陌生。基本上,我有一个脚本,将文件复制到另一个位置。我想把这个放在另一个线程,这样我就可以输出....表示脚本仍在运行。
我遇到的问题是,如果文件不能复制,它将抛出异常。如果在主线程中运行,这是可以的;但是,使用以下代码是无效的:
try:
threadClass = TheThread(param1, param2, etc.)
threadClass.start() ##### **Exception takes place here**
except:
print "Caught an exception"
在线程类本身中,我试图重新抛出异常,但它不起作用。我在这里看到有人问类似的问题,但他们似乎都在做一些比我试图做的更具体的事情(我不太理解所提供的解决方案)。我看到有人提到sys.exc_info()的用法,但我不知道在哪里或如何使用它。
编辑:线程类的代码如下:
class TheThread(threading.Thread):
def __init__(self, sourceFolder, destFolder):
threading.Thread.__init__(self)
self.sourceFolder = sourceFolder
self.destFolder = destFolder
def run(self):
try:
shul.copytree(self.sourceFolder, self.destFolder)
except:
raise
捕获线程异常并与调用方方法通信的一个简单方法是将字典或列表传递给worker方法。
示例(将字典传递给工作方法):
import threading
def my_method(throw_me):
raise Exception(throw_me)
def worker(shared_obj, *args, **kwargs):
try:
shared_obj['target'](*args, **kwargs)
except Exception as err:
shared_obj['err'] = err
shared_obj = {'err':'', 'target': my_method}
throw_me = "Test"
th = threading.Thread(target=worker, args=(shared_obj, throw_me), kwargs={})
th.start()
th.join()
if shared_obj['err']:
print(">>%s" % shared_obj['err'])
Pygolang提供同步功能。工作组,特别是将异常从派生的工作线程传播到主线程。例如:
#!/usr/bin/env python
"""This program demostrates how with sync.WorkGroup an exception raised in
spawned thread is propagated into main thread which spawned the worker."""
from __future__ import print_function
from golang import sync, context
def T1(ctx, *argv):
print('T1: run ... %r' % (argv,))
raise RuntimeError('T1: problem')
def T2(ctx):
print('T2: ran ok')
def main():
wg = sync.WorkGroup(context.background())
wg.go(T1, [1,2,3])
wg.go(T2)
try:
wg.wait()
except Exception as e:
print('Tmain: caught exception: %r\n' %e)
# reraising to see full traceback
raise
if __name__ == '__main__':
main()
在运行时给出以下结果:
T1: run ... ([1, 2, 3],)
T2: ran ok
Tmain: caught exception: RuntimeError('T1: problem',)
Traceback (most recent call last):
File "./x.py", line 28, in <module>
main()
File "./x.py", line 21, in main
wg.wait()
File "golang/_sync.pyx", line 198, in golang._sync.PyWorkGroup.wait
pyerr_reraise(pyerr)
File "golang/_sync.pyx", line 178, in golang._sync.PyWorkGroup.go.pyrunf
f(pywg._pyctx, *argv, **kw)
File "./x.py", line 10, in T1
raise RuntimeError('T1: problem')
RuntimeError: T1: problem
问题的原始代码将是:
wg = sync.WorkGroup(context.background())
def _(ctx):
shul.copytree(sourceFolder, destFolder)
wg.go(_)
# waits for spawned worker to complete and, on error, reraises
# its exception on the main thread.
wg.wait()
虽然不可能直接捕获在不同线程中抛出的异常,但下面的代码可以相当透明地获取与此功能非常接近的内容。子线程必须继承ExThread类而不是线程。线程和父线程在等待线程完成任务时必须调用child_thread.join_with_exception()方法,而不是child_thread.join()方法。
此实现的技术细节:当子线程抛出异常时,它将通过Queue传递给父线程,并在父线程中再次抛出。注意,在这种方法中没有忙碌等待。
#!/usr/bin/env python
import sys
import threading
import Queue
class ExThread(threading.Thread):
def __init__(self):
threading.Thread.__init__(self)
self.__status_queue = Queue.Queue()
def run_with_exception(self):
"""This method should be overriden."""
raise NotImplementedError
def run(self):
"""This method should NOT be overriden."""
try:
self.run_with_exception()
except BaseException:
self.__status_queue.put(sys.exc_info())
self.__status_queue.put(None)
def wait_for_exc_info(self):
return self.__status_queue.get()
def join_with_exception(self):
ex_info = self.wait_for_exc_info()
if ex_info is None:
return
else:
raise ex_info[1]
class MyException(Exception):
pass
class MyThread(ExThread):
def __init__(self):
ExThread.__init__(self)
def run_with_exception(self):
thread_name = threading.current_thread().name
raise MyException("An error in thread '{}'.".format(thread_name))
def main():
t = MyThread()
t.start()
try:
t.join_with_exception()
except MyException as ex:
thread_name = threading.current_thread().name
print "Caught a MyException in thread '{}': {}".format(thread_name, ex)
if __name__ == '__main__':
main()
我喜欢的一种方法是基于观察者模式。我定义了一个信号类,线程用它向侦听器发出异常。它还可以用于从线程返回值。例子:
import threading
class Signal:
def __init__(self):
self._subscribers = list()
def emit(self, *args, **kwargs):
for func in self._subscribers:
func(*args, **kwargs)
def connect(self, func):
self._subscribers.append(func)
def disconnect(self, func):
try:
self._subscribers.remove(func)
except ValueError:
raise ValueError('Function {0} not removed from {1}'.format(func, self))
class WorkerThread(threading.Thread):
def __init__(self, *args, **kwargs):
super(WorkerThread, self).__init__(*args, **kwargs)
self.Exception = Signal()
self.Result = Signal()
def run(self):
if self._Thread__target is not None:
try:
self._return_value = self._Thread__target(*self._Thread__args, **self._Thread__kwargs)
except Exception as e:
self.Exception.emit(e)
else:
self.Result.emit(self._return_value)
if __name__ == '__main__':
import time
def handle_exception(exc):
print exc.message
def handle_result(res):
print res
def a():
time.sleep(1)
raise IOError('a failed')
def b():
time.sleep(2)
return 'b returns'
t = WorkerThread(target=a)
t2 = WorkerThread(target=b)
t.Exception.connect(handle_exception)
t2.Result.connect(handle_result)
t.start()
t2.start()
print 'Threads started'
t.join()
t2.join()
print 'Done'
我没有足够的使用线程的经验来断言这是一种完全安全的方法。但这对我来说很管用,我喜欢这种灵活性。
我喜欢这门课:
https://gist.github.com/earonesty/b88d60cb256b71443e42c4f1d949163e
import threading
from typing import Any
class PropagatingThread(threading.Thread):
"""A Threading Class that raises errors it caught, and returns the return value of the target on join."""
def __init__(self, *args, **kwargs):
self._target = None
self._args = ()
self._kwargs = {}
super().__init__(*args, **kwargs)
self.exception = None
self.return_value = None
assert self._target
def run(self):
"""Don't override this if you want the behavior of this class, use target instead."""
try:
if self._target:
self.return_value = self._target(*self._args, **self._kwargs)
except Exception as e:
self.exception = e
finally:
# see super().run() for why this is necessary
del self._target, self._args, self._kwargs
def join(self, timeout=None) -> Any:
super().join(timeout)
if self.exception:
raise self.exception
return self.return_value
这是一个棘手的小问题,我想提出我的解决方案。我发现了一些其他的解决方案(异步。例如IO)看起来很有前途,但也呈现出一些黑盒子。队列/事件循环方法将您与某个实现联系在一起。然而,并发期货的源代码只有大约1000行,很容易理解。它让我很容易地解决了我的问题:创建临时的工作线程,而不需要太多的设置,并且能够在主线程中捕获异常。
我的解决方案使用并发期货API和线程API。它允许你创建一个worker,给你线程和未来。这样,你就可以加入线程来等待结果:
worker = Worker(test)
thread = worker.start()
thread.join()
print(worker.future.result())
...或者你可以让worker在完成时发送一个回调:
worker = Worker(test)
thread = worker.start(lambda x: print('callback', x))
...或者你可以循环直到事件完成:
worker = Worker(test)
thread = worker.start()
while True:
print("waiting")
if worker.future.done():
exc = worker.future.exception()
print('exception?', exc)
result = worker.future.result()
print('result', result)
break
time.sleep(0.25)
代码如下:
from concurrent.futures import Future
import threading
import time
class Worker(object):
def __init__(self, fn, args=()):
self.future = Future()
self._fn = fn
self._args = args
def start(self, cb=None):
self._cb = cb
self.future.set_running_or_notify_cancel()
thread = threading.Thread(target=self.run, args=())
thread.daemon = True #this will continue thread execution after the main thread runs out of code - you can still ctrl + c or kill the process
thread.start()
return thread
def run(self):
try:
self.future.set_result(self._fn(*self._args))
except BaseException as e:
self.future.set_exception(e)
if(self._cb):
self._cb(self.future.result())
...和测试函数:
def test(*args):
print('args are', args)
time.sleep(2)
raise Exception('foo')