我对Python和多线程编程非常陌生。基本上,我有一个脚本,将文件复制到另一个位置。我想把这个放在另一个线程,这样我就可以输出....表示脚本仍在运行。
我遇到的问题是,如果文件不能复制,它将抛出异常。如果在主线程中运行,这是可以的;但是,使用以下代码是无效的:
try:
threadClass = TheThread(param1, param2, etc.)
threadClass.start() ##### **Exception takes place here**
except:
print "Caught an exception"
在线程类本身中,我试图重新抛出异常,但它不起作用。我在这里看到有人问类似的问题,但他们似乎都在做一些比我试图做的更具体的事情(我不太理解所提供的解决方案)。我看到有人提到sys.exc_info()的用法,但我不知道在哪里或如何使用它。
编辑:线程类的代码如下:
class TheThread(threading.Thread):
def __init__(self, sourceFolder, destFolder):
threading.Thread.__init__(self)
self.sourceFolder = sourceFolder
self.destFolder = destFolder
def run(self):
try:
shul.copytree(self.sourceFolder, self.destFolder)
except:
raise
使用异常存储包装线程。
import threading
import sys
class ExcThread(threading.Thread):
def __init__(self, target, args = None):
self.args = args if args else []
self.target = target
self.exc = None
threading.Thread.__init__(self)
def run(self):
try:
self.target(*self.args)
raise Exception('An error occured here.')
except Exception:
self.exc=sys.exc_info()
def main():
def hello(name):
print(!"Hello, {name}!")
thread_obj = ExcThread(target=hello, args=("Jack"))
thread_obj.start()
thread_obj.join()
exc = thread_obj.exc
if exc:
exc_type, exc_obj, exc_trace = exc
print(exc_type, ':',exc_obj, ":", exc_trace)
main()
并发。Futures模块使得在单独的线程(或进程)中工作并处理任何由此产生的异常变得简单:
import concurrent.futures
import shutil
def copytree_with_dots(src_path, dst_path):
with concurrent.futures.ThreadPoolExecutor(max_workers=1) as executor:
# Execute the copy on a separate thread,
# creating a future object to track progress.
future = executor.submit(shutil.copytree, src_path, dst_path)
while future.running():
# Print pretty dots here.
pass
# Return the value returned by shutil.copytree(), None.
# Raise any exceptions raised during the copy process.
return future.result()
并发。futures包含在Python 3.2中,并可作为早期版本的反向移植futures模块使用。
我喜欢的一种方法是基于观察者模式。我定义了一个信号类,线程用它向侦听器发出异常。它还可以用于从线程返回值。例子:
import threading
class Signal:
def __init__(self):
self._subscribers = list()
def emit(self, *args, **kwargs):
for func in self._subscribers:
func(*args, **kwargs)
def connect(self, func):
self._subscribers.append(func)
def disconnect(self, func):
try:
self._subscribers.remove(func)
except ValueError:
raise ValueError('Function {0} not removed from {1}'.format(func, self))
class WorkerThread(threading.Thread):
def __init__(self, *args, **kwargs):
super(WorkerThread, self).__init__(*args, **kwargs)
self.Exception = Signal()
self.Result = Signal()
def run(self):
if self._Thread__target is not None:
try:
self._return_value = self._Thread__target(*self._Thread__args, **self._Thread__kwargs)
except Exception as e:
self.Exception.emit(e)
else:
self.Result.emit(self._return_value)
if __name__ == '__main__':
import time
def handle_exception(exc):
print exc.message
def handle_result(res):
print res
def a():
time.sleep(1)
raise IOError('a failed')
def b():
time.sleep(2)
return 'b returns'
t = WorkerThread(target=a)
t2 = WorkerThread(target=b)
t.Exception.connect(handle_exception)
t2.Result.connect(handle_result)
t.start()
t2.start()
print 'Threads started'
t.join()
t2.join()
print 'Done'
我没有足够的使用线程的经验来断言这是一种完全安全的方法。但这对我来说很管用,我喜欢这种灵活性。
这个问题有很多非常奇怪复杂的答案。我是不是把它简化了,因为对我来说,这似乎对大多数事情都足够了。
from threading import Thread
class PropagatingThread(Thread):
def run(self):
self.exc = None
try:
if hasattr(self, '_Thread__target'):
# Thread uses name mangling prior to Python 3.
self.ret = self._Thread__target(*self._Thread__args, **self._Thread__kwargs)
else:
self.ret = self._target(*self._args, **self._kwargs)
except BaseException as e:
self.exc = e
def join(self, timeout=None):
super(PropagatingThread, self).join(timeout)
if self.exc:
raise self.exc
return self.ret
如果你确定你只会在一个或另一个版本的Python上运行,你可以将run()方法减少到只有被破坏的版本(如果你只在3之前的Python版本上运行),或者仅仅是干净的版本(如果你只在3开始的Python版本上运行)。
使用示例:
def f(*args, **kwargs):
print(args)
print(kwargs)
raise Exception('I suck at this')
t = PropagatingThread(target=f, args=(5,), kwargs={'hello':'world'})
t.start()
t.join()
当您加入时,您将看到在另一个线程上引发异常。
如果您正在使用six或仅在Python 3上使用,则可以改进重新引发异常时获得的堆栈跟踪信息。您可以将内部异常包装在一个新的外部异常中,而不是仅在连接点处使用堆栈,并使用
six.raise_from(RuntimeError('Exception in thread'),self.exc)
or
raise RuntimeError('Exception in thread') from self.exc
使用异常存储包装线程。
import threading
import sys
class ExcThread(threading.Thread):
def __init__(self, target, args = None):
self.args = args if args else []
self.target = target
self.exc = None
threading.Thread.__init__(self)
def run(self):
try:
self.target(*self.args)
raise Exception('An error occured here.')
except Exception:
self.exc=sys.exc_info()
def main():
def hello(name):
print(!"Hello, {name}!")
thread_obj = ExcThread(target=hello, args=("Jack"))
thread_obj.start()
thread_obj.join()
exc = thread_obj.exc
if exc:
exc_type, exc_obj, exc_trace = exc
print(exc_type, ':',exc_obj, ":", exc_trace)
main()
我使用这个版本,它是最小的,它工作得很好。
class SafeThread(threading.Thread):
def __init__(self, *args, **kwargs):
super(SafeThread, self).__init__(*args, **kwargs)
self.exception = None
def run(self) -> None:
try:
super(SafeThread, self).run()
except Exception as ex:
self.exception = ex
traceback.print_exc()
def join(self, *args, **kwargs) -> None:
super(SafeThread, self).join(*args, **kwargs)
if self.exception:
raise self.exception
要使用它,只需替换线程。带安全线程的线程
t = SafeThread(target = some_function, args = (some, args,))
t.start()
# do something else here if you want as the thread runs in the background
t.join()