以上这些方法对我都没用。我需要使用Buffer对象:

  const chunks = [];

  readStream.on("data", function (chunk) {
    chunks.push(chunk);
  });

  // Send the buffer or you can put it into a var
  readStream.on("end", function () {
    res.send(Buffer.concat(chunks));
  });

还有一个是使用承诺的字符串:

function getStream(stream) {
  return new Promise(resolve => {
    const chunks = [];

    # Buffer.from is required if chunk is a String, see comments
    stream.on("data", chunk => chunks.push(Buffer.from(chunk)));
    stream.on("end", () => resolve(Buffer.concat(chunks).toString()));
  });
}

用法:

const stream = fs.createReadStream(__filename);
getStream(stream).then(r=>console.log(r));

如果需要，删除. tostring()以用于二进制数据。

更新:@AndreiLED正确地指出了字符串的问题。我不能得到一个流返回字符串与节点的版本，但api指出这是可能的。

以上这些方法对我都没用。我需要使用Buffer对象:

  const chunks = [];

  readStream.on("data", function (chunk) {
    chunks.push(chunk);
  });

  // Send the buffer or you can put it into a var
  readStream.on("end", function () {
    res.send(Buffer.concat(chunks));
  });

从nodejs文档中，你应该这样做——永远记住一个字符串，而不知道编码只是一堆字节:

var readable = getReadableStreamSomehow();
readable.setEncoding('utf8');
readable.on('data', function(chunk) {
  assert.equal(typeof chunk, 'string');
  console.log('got %d characters of string data', chunk.length);
})

流没有简单的. tostring()函数(我理解)，也没有类似于. tostringasync (cb)函数(我不理解)的东西。

所以我创建了自己的helper函数:

var streamToString = function(stream, callback) {
  var str = '';
  stream.on('data', function(chunk) {
    str += chunk;
  });
  stream.on('end', function() {
    callback(str);
  });
}

// how to use:
streamToString(myStream, function(myStr) {
  console.log(myStr);
});

在我的例子中，响应头的内容类型是content - type: text/plain。所以，我已经从Buffer读取了数据:

let data = [];
stream.on('data', (chunk) => {
 console.log(Buffer.from(chunk).toString())
 data.push(Buffer.from(chunk).toString())
});