我会把商品名称写在汇总单上。 因此，通过将鼠标悬停在helloworld()函数上，文本将显示hello = Item1和world = Item2

 helloworld("Hi1,Hi2");

/// <summary>
/// Return hello = Item1 and world Item2
/// </summary>
/// <param name="input">string to split</param>
/// <returns></returns>
private static Tuple<bool, bool> helloworld(string input)
{
    bool hello = false;
    bool world = false;
    foreach (var hw in input.Split(','))
    {
        switch (hw)
        {
            case "Hi1":
                hello= true;
                break;
            case "Hi2":
                world= true;
                break;
        }

    }
    return new Tuple<bool, bool>(hello, world);
}

我想我会创建一个类，但另一种选择是输出参数。

public void GetOrderRelatedIds(out int OrderGroupId, out int OrderTypeId, out int OrderSubTypeId, out int OrderRequirementId)

因为你的元组只包含整数，你可以用Dictionary<string,int>来表示它

var orderIds = new Dictionary<string, int> {
    {"OrderGroupId", 1},
    {"OrderTypeId", 2},
    {"OrderSubTypeId", 3},
    {"OrderRequirementId", 4}.
};

但我也不建议这样做。

您可以编写一个包含元组的类。

您需要重写Equals和GetHashCode函数

和==和!=操作符。

class Program
{
    public class MyTuple
    {
        private Tuple<int, int> t;

        public MyTuple(int a, int b)
        {
            t = new Tuple<int, int>(a, b);
        }

        public int A
        {
            get
            {
                return t.Item1;
            }
        }

        public int B
        {
            get
            {
                return t.Item2;
            }
        }

        public override bool Equals(object obj)
        {
            return t.Equals(((MyTuple)obj).t);
        }

        public override int GetHashCode()
        {
            return t.GetHashCode();
        }

        public static bool operator ==(MyTuple m1, MyTuple m2)
        {
            return m1.Equals(m2);
        }

        public static bool operator !=(MyTuple m1, MyTuple m2)
        {
            return !m1.Equals(m2);
        }
    }

    static void Main(string[] args)
    {
        var v1 = new MyTuple(1, 2);
        var v2 = new MyTuple(1, 2);

        Console.WriteLine(v1 == v2);

        Dictionary<MyTuple, int> d = new Dictionary<MyTuple, int>();
        d.Add(v1, 1);

        Console.WriteLine(d.ContainsKey(v2));
    }
}

将返回:

True

True

这是非常烦人的，我希望未来的c#版本能够解决这一需求。我发现最简单的方法是使用不同的数据结构类型，或者重命名“items”，以使您和其他阅读您的代码的人能够正常阅读。

Tuple<ApiResource, JSendResponseStatus> result = await SendApiRequest();
ApiResource apiResource = result.Item1;
JSendResponseStatus jSendStatus = result.Item2;

(double, int) t1 = (4.5, 3);
Console.WriteLine($"Tuple with elements {t1.Item1} and {t1.Item2}.");
// Output:
// Tuple with elements 4.5 and 3.

(double Sum, int Count) t2 = (4.5, 3);
Console.WriteLine($"Sum of {t2.Count} elements is {t2.Sum}.");
// Output:
// Sum of 3 elements is 4.5.

来自Docs: https://learn.microsoft.com/en-us/dotnet/csharp/language-reference/builtin-types/value-tuples

在。net 4中，你也许可以看看ExpandoObject，但是，不要在这种简单的情况下使用它，因为编译时错误会变成运行时错误。

class Program
{
    static void Main(string[] args)
    {
        dynamic employee, manager;

        employee = new ExpandoObject();
        employee.Name = "John Smith";
        employee.Age = 33;

        manager = new ExpandoObject();
        manager.Name = "Allison Brown";
        manager.Age = 42;
        manager.TeamSize = 10;

        WritePerson(manager);
        WritePerson(employee);
    }
    private static void WritePerson(dynamic person)
    {
        Console.WriteLine("{0} is {1} years old.",
                          person.Name, person.Age);
        // The following statement causes an exception
        // if you pass the employee object.
        // Console.WriteLine("Manages {0} people", person.TeamSize);
    }
}
// This code example produces the following output:
// John Smith is 33 years old.
// Allison Brown is 42 years old.

另一个值得一提的是方法中的匿名类型，但是如果您想要返回它，则需要创建一个类。

var MyStuff = new
    {
        PropertyName1 = 10,
        PropertyName2 = "string data",
        PropertyName3 = new ComplexType()
    };