我通常使用:

var list = new List<T> ();
fillList (list);
var randomizedList = new List<T> ();
var rnd = new Random ();
while (list.Count != 0)
{
    var index = rnd.Next (0, list.Count);
    randomizedList.Add (list [index]);
    list.RemoveAt (index);
}

可以使用morelinq包中的Shuffle扩展方法，它适用于IEnumerables

安装包morelinq

using MoreLinq;
...    
var randomized = list.Shuffle();

如果你不介意使用两个list，那么这可能是最简单的方法，但可能不是最有效或最不可预测的方法:

List<int> xList = new List<int>() { 1, 2, 3, 4, 5 };
List<int> deck = new List<int>();

foreach (int xInt in xList)
    deck.Insert(random.Next(0, deck.Count + 1), xInt);

IEnumerable扩展方法:

public static IEnumerable<T> Randomize<T>(this IEnumerable<T> source)
{
    Random rnd = new Random();
    return source.OrderBy<T, int>((item) => rnd.Next());
}

只是想建议使用IComparer<T>和List.Sort()的变体:

public class RandomIntComparer : IComparer<int>
{
    private readonly Random _random = new Random();
    
    public int Compare(int x, int y)
    {
        return _random.Next(-1, 2);
    }
}

用法:

list.Sort(new RandomIntComparer());

private List<GameObject> ShuffleList(List<GameObject> ActualList) {


    List<GameObject> newList = ActualList;
    List<GameObject> outList = new List<GameObject>();

    int count = newList.Count;

    while (newList.Count > 0) {

        int rando = Random.Range(0, newList.Count);

        outList.Add(newList[rando]);

        newList.RemoveAt(rando);

     

    }

    return (outList);

}

用法:

List<GameObject> GetShuffle = ShuffleList(ActualList);