const formatDate = d => [
    d.getFullYear(),
    (d.getMonth() + 1).toString().padStart(2, '0'),
    d.getDate().toString().padStart(2, '0')
].join('-');

您可以使用padstart。

padStart(n， '0')确保字符串中至少有n个字符，并在它前面加上'0'，直到达到该长度。

Join('-')连接一个数组，在每个元素之间添加'-'符号。

getMonth()从0开始，因此是+1。

如果你使用momentjs，现在它们包含了一个YYYY-MM-DD格式的常量:

date.format(moment.HTML5_FMT.DATE)

只需利用内置的toISOString方法，将您的日期转换为ISO 8601格式:

let yourDate = new Date()
yourDate.toISOString().split('T')[0]

yourDate是你的日期对象。

编辑:@exbuddha在评论中写了这个来处理时区:

const offset = yourDate.getTimezoneOffset()
yourDate = new Date(yourDate.getTime() - (offset*60*1000))
return yourDate.toISOString().split('T')[0]

之前的一些答案是可以的，但是不是很灵活。我想要一些能够真正处理更多边缘情况的东西，所以我采用了@orangleliu的答案并扩展了它。https://jsfiddle.net/8904cmLd/1/

function DateToString(inDate, formatString) {
    // Written by m1m1k 2018-04-05

    // Validate that we're working with a date
    if(!isValidDate(inDate))
    {
        inDate = new Date(inDate);
    }

    // See the jsFiddle for extra code to be able to use DateToString('Sun May 11,2014', 'USA');
    //formatString = CountryCodeToDateFormat(formatString);

    var dateObject = {
        M: inDate.getMonth() + 1,
        d: inDate.getDate(),
        D: inDate.getDate(),
        h: inDate.getHours(),
        m: inDate.getMinutes(),
        s: inDate.getSeconds(),
        y: inDate.getFullYear(),
        Y: inDate.getFullYear()
    };

    // Build Regex Dynamically based on the list above.
    // It should end up with something like this: "/([Yy]+|M+|[Dd]+|h+|m+|s+)/g"
    var dateMatchRegex = joinObj(dateObject, "+|") + "+";
    var regEx = new RegExp(dateMatchRegex,"g");
    formatString = formatString.replace(regEx, function(formatToken) {
        var datePartValue = dateObject[formatToken.slice(-1)];
        var tokenLength = formatToken.length;

        // A conflict exists between specifying 'd' for no zero pad -> expand
        // to '10' and specifying yy for just two year digits '01' instead
        // of '2001'.  One expands, the other contracts.
        //
        // So Constrict Years but Expand All Else
        if (formatToken.indexOf('y') < 0 && formatToken.indexOf('Y') < 0)
        {
            // Expand single digit format token 'd' to
            // multi digit value '10' when needed
            var tokenLength = Math.max(formatToken.length, datePartValue.toString().length);
        }
        var zeroPad = (datePartValue.toString().length < formatToken.length ? "0".repeat(tokenLength) : "");
        return (zeroPad + datePartValue).slice(-tokenLength);
    });

    return formatString;
}

使用示例:

DateToString('Sun May 11,2014', 'MM/DD/yy');
DateToString('Sun May 11,2014', 'yyyy.MM.dd');
DateToString(new Date('Sun Dec 11,2014'),'yy-M-d');

最短的

.toJSON().slice(0,10);

var d =新的日期(' 2014年5月11日' +' UTC');//解析为UTC let str = d.toJSON().slice(0,10);//显示为UTC console.log (str);

将日期转换为yyyy-mm-dd格式的最简单方法是这样做:

var date = new Date("Sun May 11,2014");
var dateString = new Date(date.getTime() - (date.getTimezoneOffset() * 60000 ))
                    .toISOString()
                    .split("T")[0];

工作原理:

new Date("Sun May 11,2014") converts the string "Sun May 11,2014" to a date object that represents the time Sun May 11 2014 00:00:00 in a timezone based on current locale (host system settings) new Date(date.getTime() - (date.getTimezoneOffset() * 60000 )) converts your date to a date object that corresponds with the time Sun May 11 2014 00:00:00 in UTC (standard time) by subtracting the time zone offset .toISOString() converts the date object to an ISO 8601 string 2014-05-11T00:00:00.000Z .split("T") splits the string to array ["2014-05-11", "00:00:00.000Z"] [0] takes the first element of that array

Demo

var date =新日期(“太阳5月11日”); var dateString =新日期(日期。 toISOString()。 斯普利特(“T”)[0]; 游戏机。log (dateString);

注意:

The first part of the code (new Date(...)) may need to be tweaked a bit if your input format is different from that of the OP. As mikeypie pointed out in the comments, if the date string is already in the expected output format and the local timezone is west of UTC, then new Date('2022-05-18') results in 2022-05-17. And a user's locale (eg. MM/DD/YYYY vs DD-MM-YYYY) may also impact how a date is parsed by new Date(...). So do some proper testing if you want to use this code for different input formats.