我有一个字符串,我想用它作为文件名,所以我想用Python删除文件名中不允许的所有字符。
我宁愿严格一点,所以假设我想只保留字母、数字和一小组其他字符,如“_-.()”。”。最优雅的解决方案是什么?
文件名需要在多个操作系统(Windows, Linux和Mac OS)上有效——它是我库中的一个MP3文件,以歌曲标题为文件名,并在3台机器之间共享和备份。
我有一个字符串,我想用它作为文件名,所以我想用Python删除文件名中不允许的所有字符。
我宁愿严格一点,所以假设我想只保留字母、数字和一小组其他字符,如“_-.()”。”。最优雅的解决方案是什么?
文件名需要在多个操作系统(Windows, Linux和Mac OS)上有效——它是我库中的一个MP3文件,以歌曲标题为文件名,并在3台机器之间共享和备份。
当前回答
一句话:
valid_file_name = re.sub('[^\w_.)( -]', '', any_string)
你也可以用“_”字符让它更具可读性(例如替换斜杠)
其他回答
不完全是OP要求的,但这是我使用的,因为我需要唯一的和可逆的转换:
# p3 code
def safePath (url):
return ''.join(map(lambda ch: chr(ch) if ch in safePath.chars else '%%%02x' % ch, url.encode('utf-8')))
safePath.chars = set(map(lambda x: ord(x), '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz+-_ .'))
结果“有些”可读,至少从系统管理员的角度来看是这样。
我相信这不是一个很好的答案,因为它修改了它循环的字符串,但它似乎工作得很好:
import string
for chr in your_string:
if chr == ' ':
your_string = your_string.replace(' ', '_')
elif chr not in string.ascii_letters or chr not in string.digits:
your_string = your_string.replace(chr, '')
给,这应该涵盖了所有的基础。它为您处理所有类型的问题,包括(但不限于)字符替换。
适用于Windows、*nix和几乎所有其他文件系统。只允许打印字符。
def txt2filename(txt, chr_set='normal'):
"""Converts txt to a valid Windows/*nix filename with printable characters only.
args:
txt: The str to convert.
chr_set: 'normal', 'universal', or 'inclusive'.
'universal': ' -.0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'
'normal': Every printable character exept those disallowed on Windows/*nix.
'extended': All 'normal' characters plus the extended character ASCII codes 128-255
"""
FILLER = '-'
# Step 1: Remove excluded characters.
if chr_set == 'universal':
# Lookups in a set are O(n) vs O(n * x) for a str.
printables = set(' -.0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz')
else:
if chr_set == 'normal':
max_chr = 127
elif chr_set == 'extended':
max_chr = 256
else:
raise ValueError(f'The chr_set argument may be normal, extended or universal; not {chr_set=}')
EXCLUDED_CHRS = set(r'<>:"/\|?*') # Illegal characters in Windows filenames.
EXCLUDED_CHRS.update(chr(127)) # DEL (non-printable).
printables = set(chr(x)
for x in range(32, max_chr)
if chr(x) not in EXCLUDED_CHRS)
result = ''.join(x if x in printables else FILLER # Allow printable characters only.
for x in txt)
# Step 2: Device names, '.', and '..' are invalid filenames in Windows.
DEVICE_NAMES = 'CON,PRN,AUX,NUL,COM1,COM2,COM3,COM4,' \
'COM5,COM6,COM7,COM8,COM9,LPT1,LPT2,' \
'LPT3,LPT4,LPT5,LPT6,LPT7,LPT8,LPT9,' \
'CONIN$,CONOUT$,..,.'.split() # This list is an O(n) operation.
if result in DEVICE_NAMES:
result = f'-{result}-'
# Step 3: Maximum length of filename is 255 bytes in Windows and Linux (other *nix flavors may allow longer names).
result = result[:255]
# Step 4: Windows does not allow filenames to end with '.' or ' ' or begin with ' '.
result = re.sub(r'^[. ]', FILLER, result)
result = re.sub(r' $', FILLER, result)
return result
这个解决方案不需要外部库。它也替代了不可打印的文件名,因为它们并不总是容易处理。
这是我最终使用的解决方案:
import unicodedata
validFilenameChars = "-_.() %s%s" % (string.ascii_letters, string.digits)
def removeDisallowedFilenameChars(filename):
cleanedFilename = unicodedata.normalize('NFKD', filename).encode('ASCII', 'ignore')
return ''.join(c for c in cleanedFilename if c in validFilenameChars)
unicodedata。Normalize调用将重音字符替换为同等的非重音字符,这比简单地将它们剥离要好。之后,所有不允许的字符都将被删除。
我的解决方案没有预先添加一个已知字符串,以避免可能的不允许文件名,因为我知道给定特定的文件名格式,它们不会出现。这需要一个更普遍的解决方案。
This whitelist approach (ie, allowing only the chars present in valid_chars) will work if there aren't limits on the formatting of the files or combination of valid chars that are illegal (like ".."), for example, what you say would allow a filename named " . txt" which I think is not valid on Windows. As this is the most simple approach I'd try to remove whitespace from the valid_chars and prepend a known valid string in case of error, any other approach will have to know about what is allowed where to cope with Windows file naming limitations and thus be a lot more complex.
>>> import string
>>> valid_chars = "-_.() %s%s" % (string.ascii_letters, string.digits)
>>> valid_chars
'-_.() abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789'
>>> filename = "This Is a (valid) - filename%$&$ .txt"
>>> ''.join(c for c in filename if c in valid_chars)
'This Is a (valid) - filename .txt'