我已经升级了我的系统,并为我正在开发的web应用程序安装了MySql 5.7.9和php。我有一个查询,是动态创建的,当运行在旧版本的MySQL它工作得很好。自从升级到5.7,我得到这个错误:

SELECT列表的表达式#1不在GROUP BY子句中,并且包含 未聚合列的support_desk.mod_users_groups。Group_id '就是 在功能上不依赖于GROUP BY子句中的列;这是 sql_mode=only_full_group_by不兼容

请注意Mysql 5.7的手册页中关于Server SQL Modes的主题。

这个问题让我很困扰:

SELECT mod_users_groups.group_id AS 'value', 
       group_name AS 'text' 
FROM mod_users_groups
LEFT JOIN mod_users_data ON mod_users_groups.group_id = mod_users_data.group_id 
WHERE  mod_users_groups.active = 1 
  AND mod_users_groups.department_id = 1 
  AND mod_users_groups.manage_work_orders = 1 
  AND group_name != 'root' 
  AND group_name != 'superuser' 
GROUP BY group_name 
HAVING COUNT(`user_id`) > 0 
ORDER BY group_name

我不理解only_full_group_by,不足以弄清楚我需要做什么来修复查询。我是否可以关闭only_full_group_by选项,或者还有其他需要做的事情?


当前回答

很抱歉,没有使用准确的SQL

我使用这个查询来克服Mysql警告。

SELECT count(*) AS cnt, `regions_id`
FROM regionables 
WHERE `regionable_id` = '115' OR `regionable_id` = '714'
GROUP BY `regions_id`
HAVING cnt > 1

注意我存在的关键

count(*) AS cnt

其他回答

我使用Laravel 5.3, mysql 5.7.12,在Laravel homestead(0.5.0,我相信)

即使在显式地设置编辑/etc/mysql/my.cnf以反映:

[mysqld]
sql_mode = STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_AUTO_CREATE_USER,NO_ENGINE_SUBSTITUTION

我仍然在接收错误。

我不得不改变config/database.php从true到false:

    'mysql' => [
        'strict' => false, //behave like 5.6
        //'strict' => true //behave like 5.7
    ], 

进一步阅读:

https://laracasts.com/discuss/channels/servers/set-set-sql-mode-on-homestead https://mattstauffer.co/blog/strict-mode-and-other-mysql-customizations-in-laravel-5-2

使用ANY_VALUE()引用未聚合的列。

SELECT name,           address , MAX(age) FROM t GROUP BY name; -- fails
SELECT name, ANY_VALUE(address), MAX(age) FROM t GROUP BY name; -- works

从MySQL 5.7文档:

You can achieve the same effect without disabling ONLY_FULL_GROUP_BY by using ANY_VALUE() to refer to the nonaggregated column. ... This query might be invalid with ONLY_FULL_GROUP_BY enabled because the nonaggregated address column in the select list is not named in the GROUP BY clause: SELECT name, address, MAX(age) FROM t GROUP BY name; ... If you know that, for a given data set, each name value in fact uniquely determines the address value, address is effectively functionally dependent on name. To tell MySQL to accept the query, you can use the ANY_VALUE() function: SELECT name, ANY_VALUE(address), MAX(age) FROM t GROUP BY name;

可以为group_id添加唯一索引;如果您确定group_id是唯一的。

它可以在不修改查询的情况下解决您的问题。

迟来的回答,但在回答中还没有提到。也许它应该完善现有的已经很全面的答案。至少,当我不得不分割一个包含太多字段的表时,它确实解决了我的问题。

我不得不在我的Ubuntu 18.04上编辑下面的文件:

/ etc / mysql / mysql上。d / mysqld cnf。

with

sql_mode=STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_AUTO_CREATE_USER,NO_ENGINE_SUBSTITUTION

and

Sudo服务mysql重启

如果你使用的是wamp 3.0.6或任何高于stable 2.5的版本,你可能会遇到这个问题,首先是sql的问题。您必须相应地命名字段。但是还有另一种解决方法。点击wamp的绿色图标。Mysql -> Mysql settings-> sql_mode->无。或者从控制台更改默认值。

mysql> set global sql_mode='STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_AUTO_CREATE_USER,NO_ENGINE_SUBSTITUTION';
mysql> set session sql_mode='STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_AUTO_CREATE_USER,NO_ENGINE_SUBSTITUTION';