我有一个脚本，打印当前的日期和时间在JavaScript，但日期总是错误的。代码如下:
var currentdate = new Date();
var datetime = "Last Sync: " + currentdate.getDay() + "/" + currentdate.getMonth()
+ "/" + currentdate.getFullYear() + " @ "
+ currentdate.getHours() + ":"
+ currentdate.getMinutes() + ":" + currentdate.getSeconds();
它应该打印18/04/2012 15:07:33和打印3/3/2012 15:07:33
当前回答
getDay()获取星期几。3号是星期三。你需要getDate()，它会返回18。
同样，getMonth()从0开始，你需要加1来得到4(四月)。
演示:http://jsfiddle.net/4zVxp/
其他回答
getDay()获取星期几。3号是星期三。你需要getDate()，它会返回18。
同样，getMonth()从0开始，你需要加1来得到4(四月)。
演示:http://jsfiddle.net/4zVxp/
var currentdate = new Date();
var datetime = "Last Sync: " + currentdate.getDate() + "/"+(currentdate.getMonth()+1)
+ "/" + currentdate.getFullYear() + " @ "
+ currentdate.getHours() + ":"
+ currentdate.getMinutes() + ":" + currentdate.getSeconds();
将. getday()方法更改为. getdate()，并将1添加到month，因为它从0开始计算月份。
我想现在分享我的答案已经很晚了，但我认为这是值得的。
function __getCurrentDateTime(format){
var dt=new Date(),x,date=[];
date['d']=dt.getDate();
date['dd']=dt.getDate()>10?dt.getDate():'0'+dt.getDate();
date['m']=dt.getMonth()+1;
date['mm']=(dt.getMonth()+1)>10?(dt.getMonth()+1):'0'+(dt.getMonth()+1);
date['yyyy']=dt.getFullYear();
date['yy']=dt.getFullYear().toString().slice(-2);
date['h']=(dt.getHours()>12?dt.getHours()-12:dt.getHours());
date['hh']=dt.getHours();
date['mi']=dt.getMinutes();
date['mimi']=dt.getMinutes()<10?('0'+dt.getMinutes()):dt.getMinutes();
date['s']=dt.getSeconds();
date['ss']=dt.getSeconds()<10?('0'+dt.getSeconds()):dt.getSeconds();
date['sss']=dt.getMilliseconds();
date['ampm']=(dt.getHours()>=12?'PM':'AM');
x=format.toLowerCase();
x=x.indexOf('dd')!=-1?x.replace(/(dd)/i,date['dd']):x.replace(/(d)/i,date['d']);
x=x.indexOf('mm')!=-1?x.replace(/(mm)/i,date['mm']):x.replace(/(m)/i,date['m']);
x=x.indexOf('yyyy')!=-1?x.replace(/(yyyy)/i,date['yyyy']):x.replace(/(yy)/i,date['yy']);
x=x.indexOf('hh')!=-1?x.replace(/(hh)/i,date['hh']):x.replace(/(h)/i,date['h']);
x=x.indexOf('mimi')!=-1?x.replace(/(mimi)/i,date['mimi']):x.replace(/(mi)/i,date['mi']);
if(x.indexOf('sss')!=-1){ x=x.replace(/(sss)/i,date['sss']); }
x=x.indexOf('ss')!=-1?x.replace(/(ss)/i,date['ss']):x.replace(/(s)/i,date['s']);
if(x.indexOf('ampm')!=-1){ x=x.replace(/(ampm)/i,date['ampm']); }
return x;
}
console.log(__getCurrentDateTime()); //returns in dd-mm-yyyy HH:MM:SS
console.log(__getCurrentDateTime('dd-mm-yyyy')); //return in 05-12-2016
console.log(__getCurrentDateTime('dd/mm*yyyy')); //return in 05/12*2016
console.log(__getCurrentDateTime('hh:mimi:ss')); //return in 13:05:30
console.log (__getCurrentDateTime (' h mi: ss ampm '));//下午1:5:30返回
只使用:
var d = new Date();
document.write(d.toLocaleString());
document.write("<br>");
我善意的回答是使用这个小小的JS: https://github.com/rhroyston/clock-js
clock.now --> 1462248501241
clock.time --> 11:08 PM
clock.weekday --> monday
clock.day --> 2
clock.month --> may
clock.year --> 2016
clock.since(1462245888784) --> 44 minutes
clock.until(1462255888784) --> 2 hours
clock.what.time(1462245888784) --> 10:24 PM
clock.what.weekday(1461968554458) --> friday
clock.what.day('14622458887 84') --> 2
clock.what.month(1461968554458) --> april
clock.what.year('1461968554458') --> 2016
clock.what.time() --> 11:11 PM
clock.what.weekday('14619685abcd') --> clock.js error : expected unix timestamp as argument
clock.unit.seconds --> 1000
clock.unit.minutes --> 60000
clock.unit.hours --> 3600000
clock.unit.days --> 86400000
clock.unit.weeks --> 604800000
clock.unit.months --> 2628002880
clock.unit.years --> 31536000000
