你可以这样做，我认为这是最短、最干净、最快的:

Object.entries(test).filter(([key]) => (!~~key && key !== "0"))

给定以下混合类型枚举定义:

enum testEnum {
  Critical = "critical",
  Major = 3,
  Normal = "2",
  Minor = "minor",
  Info = "info",
  Debug = 0
};

它将会变成以下内容:

var testEnum = { 关键:“至关重要的”, 主要:3, 正常:“2”, 小:“小”, 信息:“信息”, 调试:0, [0]:“关键”, [1]: 3, [2]:“2”, [3]:“小”, [4]:“信息”, [5]: 0 ｝ 函数safeEnumEntries(test) { return Object.entries(test).filter(([key]) => (!~~key && key !== "0"); }; console.log (safeEnumEntries (testEnum));

执行函数后，你只会得到好的条目:

[
  ["Critical", "critical"],
  ["Major", 3],
  ["Normal", "2"],
  ["Minor", "minor"],
  ["Info", "info"],
  ["Debug", 0]
] 

这对于基于键值的enum更有效:

enum yourEnum {
  ["First Key"] = "firstWordValue",
  ["Second Key"] = "secondWordValue"
}

Object.keys(yourEnum)[Object.values(yourEnum).findIndex(x => x === yourValue)]
// Result for passing values as yourValue
// FirstKey
// SecondKey

简单地说

如果你的枚举如下:

export enum Colors1 {
  Red = 1,
  Green = 2,
  Blue = 3
}

要获得特定的文本和值:

console.log(Colors1.Red); // 1 
console.log(Colors1[Colors1.Red]); // Red

获取值和文本列表:

public getTextAndValues(e: { [s: number]: string }) {
  for (const enumMember in e) {
    if (parseInt(enumMember, 10) >= 0) {
      console.log(e[enumMember]) // Value, such as 1,2,3
      console.log(parseInt(enumMember, 10)) // Text, such as Red,Green,Blue
    }
  }
}
this.getTextAndValues(Colors1)

如果你的枚举如下:

export enum Colors2 {
  Red = "Red",
  Green = "Green",
  Blue = "Blue"
}

要获得特定的文本和值:

console.log(Colors2.Red); // Red
console.log(Colors2["Red"]); // Red

获取值和文本列表:

public getTextAndValues(e: { [s: string]: string }) {
  for (const enumMember in e) {
    console.log(e[enumMember]);// Value, such as Red,Green,Blue
    console.log(enumMember); //  Text, such as Red,Green,Blue
  }
}
this.getTextAndValues(Colors2)

Typescript游乐场示例

enum TransactionStatus {
  SUBMITTED = 'submitted',
  APPROVED = 'approved',
  PAID = 'paid',
  CANCELLED = 'cancelled',
  DECLINED = 'declined',
  PROCESSING = 'processing',
}


let set1 = Object.entries(TransactionStatus).filter(([,value]) => value === TransactionStatus.SUBMITTED || value === TransactionStatus.CANCELLED).map(([key,]) => {
    return key
})


let set2 = Object.entries(TransactionStatus).filter(([,value]) => value === TransactionStatus.PAID || value === TransactionStatus.APPROVED).map(([key,]) => {
    return key
})

let allKeys = Object.keys(TransactionStatus)



console.log({set1,set2,allKeys})

他们在官方文件中提供了一个叫做“反向映射”的概念。它帮助了我:

https://www.typescriptlang.org/docs/handbook/enums.html#reverse-mappings

解决方法很简单:

enum Enum {
 A,
}

let a = Enum.A;
let nameOfA = Enum[a]; // "A"

如果它是你的枚举，你定义如下所示，名称和值是相同的，它会直接给你条目的名称。

enum myEnum { 
    entry1="entry1", 
    entry2="entry2"
 }

for (var entry in myEnum) { 
    // use entry's name here, e.g., "entry1"
}