我想迭代一个TypeScript枚举对象,并获得每个枚举符号名称,例如: enum myEnum {entry1, entry2}
for (var entry in myEnum) {
// use entry's name here, e.g., "entry1"
}
我想迭代一个TypeScript枚举对象,并获得每个枚举符号名称,例如: enum myEnum {entry1, entry2}
for (var entry in myEnum) {
// use entry's name here, e.g., "entry1"
}
当前回答
使用当前版本的TypeScript,你可以使用这些函数将Enum映射到你选择的记录。注意,不能用这些函数定义字符串值,因为它们查找值为数字的键。
enum STATES {
LOGIN,
LOGOUT,
}
export const enumToRecordWithKeys = <E extends any>(enumeration: E): E => (
Object.keys(enumeration)
.filter(key => typeof enumeration[key] === 'number')
.reduce((record, key) => ({...record, [key]: key }), {}) as E
);
export const enumToRecordWithValues = <E extends any>(enumeration: E): E => (
Object.keys(enumeration)
.filter(key => typeof enumeration[key] === 'number')
.reduce((record, key) => ({...record, [key]: enumeration[key] }), {}) as E
);
const states = enumToRecordWithKeys(STATES)
const statesWithIndex = enumToRecordWithValues(STATES)
console.log(JSON.stringify({
STATES,
states,
statesWithIndex,
}, null ,2));
// Console output:
{
"STATES": {
"0": "LOGIN",
"1": "LOGOUT",
"LOGIN": 0,
"LOGOUT": 1
},
"states": {
"LOGIN": "LOGIN",
"LOGOUT": "LOGOUT"
},
"statesWithIndex": {
"LOGIN": 0,
"LOGOUT": 1
}
}
其他回答
唯一的解决方案,适用于我在所有情况下(即使值是字符串)是以下:
var enumToString = function(enumType, enumValue) {
for (var enumMember in enumType) {
if (enumType[enumMember]==enumValue) return enumMember
}
}
简单地说
如果你的枚举如下:
export enum Colors1 {
Red = 1,
Green = 2,
Blue = 3
}
要获得特定的文本和值:
console.log(Colors1.Red); // 1
console.log(Colors1[Colors1.Red]); // Red
获取值和文本列表:
public getTextAndValues(e: { [s: number]: string }) {
for (const enumMember in e) {
if (parseInt(enumMember, 10) >= 0) {
console.log(e[enumMember]) // Value, such as 1,2,3
console.log(parseInt(enumMember, 10)) // Text, such as Red,Green,Blue
}
}
}
this.getTextAndValues(Colors1)
如果你的枚举如下:
export enum Colors2 {
Red = "Red",
Green = "Green",
Blue = "Blue"
}
要获得特定的文本和值:
console.log(Colors2.Red); // Red
console.log(Colors2["Red"]); // Red
获取值和文本列表:
public getTextAndValues(e: { [s: string]: string }) {
for (const enumMember in e) {
console.log(e[enumMember]);// Value, such as Red,Green,Blue
console.log(enumMember); // Text, such as Red,Green,Blue
}
}
this.getTextAndValues(Colors2)
如果它是你的枚举,你定义如下所示,名称和值是相同的,它会直接给你条目的名称。
enum myEnum {
entry1="entry1",
entry2="entry2"
}
for (var entry in myEnum) {
// use entry's name here, e.g., "entry1"
}
从TypeScript 2.4开始,枚举不再包含键作为成员。来源TypeScript自述文件
需要注意的是,字符串初始化的枚举不能反向映射到原始枚举成员名。换句话说,你不能写Colors["RED"]来获得字符串"RED"。
我的解决方案:
export const getColourKey = (value: string ) => {
let colourKey = '';
for (const key in ColourEnum) {
if (value === ColourEnum[key]) {
colourKey = key;
break;
}
}
return colourKey;
};
当我遇到同样的问题时,你可以使用我写的enum-values包:
Git: enum-values
var names = EnumValues.getNames(myEnum);