如何在PHP中计算两个日期时间之间的分钟差异?
当前回答
DateTime::diff很酷,但对于这种需要单个单元结果的计算来说很尴尬。手动减去时间戳效果更好:
$date1 = new DateTime('2020-09-01 01:00:00');
$date2 = new DateTime('2021-09-01 14:00:00');
$diff_mins = abs($date1->getTimestamp() - $date2->getTimestamp()) / 60;
其他回答
这就是我如何显示“xx次前”在php > 5.2 ..这里是DateTime对象的更多信息
//Usage:
$pubDate = $row['rssfeed']['pubDates']; // e.g. this could be like 'Sun, 10 Nov 2013 14:26:00 GMT'
$diff = ago($pubDate); // output: 23 hrs ago
// Return the value of time different in "xx times ago" format
function ago($timestamp)
{
$today = new DateTime(date('y-m-d h:i:s')); // [2]
//$thatDay = new DateTime('Sun, 10 Nov 2013 14:26:00 GMT');
$thatDay = new DateTime($timestamp);
$dt = $today->diff($thatDay);
if ($dt->y > 0){
$number = $dt->y;
$unit = "year";
} else if ($dt->m > 0) {
$number = $dt->m;
$unit = "month";
} else if ($dt->d > 0) {
$number = $dt->d;
$unit = "day";
} else if ($dt->h > 0) {
$number = $dt->h;
$unit = "hour";
} else if ($dt->i > 0) {
$number = $dt->i;
$unit = "minute";
} else if ($dt->s > 0) {
$number = $dt->s;
$unit = "second";
}
$unit .= $number > 1 ? "s" : "";
$ret = $number." ".$unit." "."ago";
return $ret;
}
我找到了很多解,但我从来没有得到正确的解。但是我已经创建了一些代码来查找分钟,请检查它。
<?php
$time1 = "23:58";
$time2 = "01:00";
$time1 = explode(':',$time1);
$time2 = explode(':',$time2);
$hours1 = $time1[0];
$hours2 = $time2[0];
$mins1 = $time1[1];
$mins2 = $time2[1];
$hours = $hours2 - $hours1;
$mins = 0;
if($hours < 0)
{
$hours = 24 + $hours;
}
if($mins2 >= $mins1) {
$mins = $mins2 - $mins1;
}
else {
$mins = ($mins2 + 60) - $mins1;
$hours--;
}
if($mins < 9)
{
$mins = str_pad($mins, 2, '0', STR_PAD_LEFT);
}
if($hours < 9)
{
$hours =str_pad($hours, 2, '0', STR_PAD_LEFT);
}
echo $hours.':'.$mins;
?>
它以小时和分钟为单位输出,例如01小时02分钟,如01:02
减去这些次数,再除以60。
下面是一个计算从2019/02/01 10:23:45经过的时间(以分钟为单位)的例子:
$diff_time=(strtotime(date("Y/m/d H:i:s"))-strtotime("2019/02/01 10:23:45"))/60;
<?php
$date1 = time();
sleep(2000);
$date2 = time();
$mins = ($date2 - $date1) / 60;
echo $mins;
?>
一个更通用的版本,返回日,小时,分钟或秒的结果,包括分数/小数:
function DateDiffInterval($sDate1, $sDate2, $sUnit='H') {
//subtract $sDate2-$sDate1 and return the difference in $sUnit (Days,Hours,Minutes,Seconds)
$nInterval = strtotime($sDate2) - strtotime($sDate1);
if ($sUnit=='D') { // days
$nInterval = $nInterval/60/60/24;
} else if ($sUnit=='H') { // hours
$nInterval = $nInterval/60/60;
} else if ($sUnit=='M') { // minutes
$nInterval = $nInterval/60;
} else if ($sUnit=='S') { // seconds
}
return $nInterval;
} //DateDiffInterval
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