如何在PHP中计算两个日期时间之间的分钟差异?
当前回答
<?php
$date1 = time();
sleep(2000);
$date2 = time();
$mins = ($date2 - $date1) / 60;
echo $mins;
?>
其他回答
以下是答案:
$to_time = strtotime("2008-12-13 10:42:00");
$from_time = strtotime("2008-12-13 10:21:00");
echo round(abs($to_time - $from_time) / 60,2). " minute";
<?php
$start = strtotime('12:01:00');
$end = strtotime('13:16:00');
$mins = ($end - $start) / 60;
echo $mins;
?>
输出:
75
这就是我如何显示“xx次前”在php > 5.2 ..这里是DateTime对象的更多信息
//Usage:
$pubDate = $row['rssfeed']['pubDates']; // e.g. this could be like 'Sun, 10 Nov 2013 14:26:00 GMT'
$diff = ago($pubDate); // output: 23 hrs ago
// Return the value of time different in "xx times ago" format
function ago($timestamp)
{
$today = new DateTime(date('y-m-d h:i:s')); // [2]
//$thatDay = new DateTime('Sun, 10 Nov 2013 14:26:00 GMT');
$thatDay = new DateTime($timestamp);
$dt = $today->diff($thatDay);
if ($dt->y > 0){
$number = $dt->y;
$unit = "year";
} else if ($dt->m > 0) {
$number = $dt->m;
$unit = "month";
} else if ($dt->d > 0) {
$number = $dt->d;
$unit = "day";
} else if ($dt->h > 0) {
$number = $dt->h;
$unit = "hour";
} else if ($dt->i > 0) {
$number = $dt->i;
$unit = "minute";
} else if ($dt->s > 0) {
$number = $dt->s;
$unit = "second";
}
$unit .= $number > 1 ? "s" : "";
$ret = $number." ".$unit." "."ago";
return $ret;
}
一个更通用的版本,返回日,小时,分钟或秒的结果,包括分数/小数:
function DateDiffInterval($sDate1, $sDate2, $sUnit='H') {
//subtract $sDate2-$sDate1 and return the difference in $sUnit (Days,Hours,Minutes,Seconds)
$nInterval = strtotime($sDate2) - strtotime($sDate1);
if ($sUnit=='D') { // days
$nInterval = $nInterval/60/60/24;
} else if ($sUnit=='H') { // hours
$nInterval = $nInterval/60/60;
} else if ($sUnit=='M') { // minutes
$nInterval = $nInterval/60;
} else if ($sUnit=='S') { // seconds
}
return $nInterval;
} //DateDiffInterval
<?php
$date1 = time();
sleep(2000);
$date2 = time();
$mins = ($date2 - $date1) / 60;
echo $mins;
?>
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