试一试:

$date = "2017-10-01";


function date_checker($input,$devider){
  $output = false;

  $input = explode($devider, $input);
  $year = $input[0];
  $month = $input[1];
  $day = $input[2];

  if (is_numeric($year) && is_numeric($month) && is_numeric($day)) {
    if (strlen($year) == 4 && strlen($month) == 2 && strlen($day) == 2) {
      $output = true;
    }
  }
  return $output;
}

if (date_checker($date, '-')) {
  echo "The function is working";
}else {
  echo "The function isNOT working";
}

判断是否有字符串是日期

function checkIsAValidDate($myDateString){
    return (bool)strtotime($myDateString);
}

恐怕大多数投票的解决方案(https://stackoverflow.com/a/19271434/3283279)不能正常工作。第四个测试用例(var_dump(validateDate('2012-2-25'));// false)是错误的。日期是正确的，因为它对应的格式- m允许一个月前导零或不前导零(参见:http://php.net/manual/en/datetime.createfromformat.php)。因此，日期2012-2-25的格式是Y-m-d，测试用例必须为真而不是假。

我认为更好的解决方案是测试可能的错误，如下所示:

function validateDate($date, $format = 'Y-m-d') {
    DateTime::createFromFormat($format, $date);
    $errors = DateTime::getLastErrors();

    return $errors['warning_count'] === 0 && $errors['error_count'] === 0;
}

正则表达式的解决方案

function verify_date($date){
  /* correct format = "2012-09-15 11:23:32" or "2012-09-15"*/
  if (preg_match("/^[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1])( (0[0-9]|[1-2][0-4]):(0[0-9]|[1-5][0-9]):(0[0-9]|[1-5][0-9]))?$/",$date)) {
    return true;
  } else {
    die("Wrong date format: it should be '2012-09-15 11:23:32' or '2012-09-15', date received is: ".$date);
  }
}

试试这个:

$myday = '2022-1-30'; 
if (($timestamp = strtotime($myday)) === false) {
    echo 'The string ('.$myday.') is not date';
} else {
    echo 'The string ('.$myday.') is date = ' . date('l dS \o\f F Y h:i:s A', $timestamp);
}

试一试:

$date = "2017-10-01";


function date_checker($input,$devider){
  $output = false;

  $input = explode($devider, $input);
  $year = $input[0];
  $month = $input[1];
  $day = $input[2];

  if (is_numeric($year) && is_numeric($month) && is_numeric($day)) {
    if (strlen($year) == 4 && strlen($month) == 2 && strlen($day) == 2) {
      $output = true;
    }
  }
  return $output;
}

if (date_checker($date, '-')) {
  echo "The function is working";
}else {
  echo "The function isNOT working";
}