当从代码中调用web资源时,一个常见的任务是构建一个包含所有必要参数的查询字符串。虽然这绝不是火箭科学,但有一些漂亮的细节需要注意,例如,如果不是第一个参数,则添加&,对参数进行编码等。

实现它的代码非常简单,但有点乏味:

StringBuilder SB = new StringBuilder();
if (NeedsToAddParameter A) 
{ 
  SB.Append("A="); SB.Append(HttpUtility.UrlEncode("TheValueOfA")); 
}

if (NeedsToAddParameter B) 
{
  if (SB.Length>0) SB.Append("&"); 
  SB.Append("B="); SB.Append(HttpUtility.UrlEncode("TheValueOfB")); }
}

这是一个非常常见的任务,人们希望存在一个实用工具类,使其更加优雅和可读。扫描MSDN,我没有找到一个,这让我想到了以下问题:

你所知道的最优雅干净的方法是什么?


当前回答

只是想说说我的看法

public static class HttpClientExt
{
    public static Uri AddQueryParams(this Uri uri, string query)
    {
        var ub = new UriBuilder(uri);
        ub.Query = string.IsNullOrEmpty(uri.Query) ? query : string.Join("&", uri.Query.Substring(1), query);
        return ub.Uri;
    }

    public static Uri AddQueryParams(this Uri uri, IEnumerable<string> query)
    {
        return uri.AddQueryParams(string.Join("&", query));
    } 

    public static Uri AddQueryParams(this Uri uri, string key, string value)
    {
        return uri.AddQueryParams(string.Join("=", HttpUtility.UrlEncode(key), HttpUtility.UrlEncode(value)));
    }

    public static Uri AddQueryParams(this Uri uri, params KeyValuePair<string,string>[] kvps)
    {
        return uri.AddQueryParams(kvps.Select(kvp => string.Join("=", HttpUtility.UrlEncode(kvp.Key), HttpUtility.UrlEncode(kvp.Value))));
    }

    public static Uri AddQueryParams(this Uri uri, IDictionary<string, string> kvps)
    {
        return uri.AddQueryParams(kvps.Select(kvp => string.Join("=", HttpUtility.UrlEncode(kvp.Key), HttpUtility.UrlEncode(kvp.Value))));
    }

    public static Uri AddQueryParams(this Uri uri, NameValueCollection nvc)
    {
        return uri.AddQueryParams(nvc.AllKeys.SelectMany(nvc.GetValues, (key, value) => string.Join("=", HttpUtility.UrlEncode(key), HttpUtility.UrlEncode(value))));
    }
}

文档说uri。查询将以?如果它是非空的,如果你要修改它,你应该把它剪掉。

注意HttpUtility。UrlEncode可以在System.Web中找到。

用法:

var uri = new Uri("https://api.del.icio.us/v1/posts/suggest").AddQueryParam("url","http://stackoverflow.com")

其他回答

public string UrlQueryStr(object data)
{
    if (data == null)
        return string.Empty;

    object val;
    StringBuilder sb = new StringBuilder();

    foreach (PropertyDescriptor prop in TypeDescriptor.GetProperties(data))
    {
        if ((val = prop.GetValue(data)) != null)
        {
            sb.AppendFormat("{0}{1}={2}", sb.Length == 0 ? '?' : '&',
                HttpUtility.UrlEncode(prop.Name), HttpUtility.UrlEncode(val.ToString()));
        }
    }
    return sb.ToString();
}

结合顶部的答案创建一个匿名对象版本:

var queryString = HttpUtility2.BuildQueryString(new
{
    key2 = "value2",
    key1 = "value1",
});

这会产生这样的结果:

key2 = value2&key1 = value1

代码如下:

public static class HttpUtility2
{
    public static string BuildQueryString<T>(T obj)
    {
        var queryString = HttpUtility.ParseQueryString(string.Empty);

        foreach (var property in TypeDescriptor.GetProperties(typeof(T)).Cast<PropertyDescriptor>())
        {
            var value = (property.GetValue(obj) ?? "").ToString();
            queryString.Add(property.Name, value);
        }

        return queryString.ToString();
    }
}

未经测试,但我认为沿着这些路线的东西会工作得很好

public class QueryString
{
    private Dictionary<string,string> _Params = new Dictionary<string,string>();

    public overide ToString()
    {
        List<string> returnParams = new List<string>();

        foreach (KeyValuePair param in _Params)
        {
            returnParams.Add(String.Format("{0}={1}", param.Key, param.Value));
        }

        // return String.Format("?{0}", String.Join("&", returnParams.ToArray())); 

        // credit annakata
        return "?" + String.Join("&", returnParams.ToArray());
    }

    public void Add(string key, string value)
    {
        _Params.Add(key, HttpUtility.UrlEncode(value));
    }
}

QueryString query = new QueryString();

query.Add("param1", "value1");
query.Add("param2", "value2");

return query.ToString();

我为我的剃刀项目写了一个助手,使用了其他答案的一些提示。

ParseQueryString业务是必要的,因为我们不允许篡改当前请求的QueryString对象。

@helper GetQueryStringWithValue(string key, string value) {
    var queryString = System.Web.HttpUtility.ParseQueryString(HttpContext.Current.Request.QueryString.ToString());
    queryString[key] = value;
    @Html.Raw(queryString.ToString())
}

我是这样使用的:

location.search = '?@Helpers.GetQueryStringWithValue("var-name", "var-value")';

如果希望它接受多个值,只需将参数更改为Dictionary,并将对添加到查询字符串中。

我的提供:

public static Uri AddQuery(this Uri uri, string name, string value)
{
    // this actually returns HttpValueCollection : NameValueCollection
    // which uses unicode compliant encoding on ToString()
    var query = HttpUtility.ParseQueryString(uri.Query);

    query.Add(name, value);

    var uriBuilder = new UriBuilder(uri)
    {
        Query = query.ToString()
    };

    return uriBuilder.Uri;
}

用法:

var uri = new Uri("http://stackoverflow.com").AddQuery("such", "method")
                                             .AddQuery("wow", "soFluent");

// http://stackoverflow.com?such=method&wow=soFluent