我有一个PHP脚本,可以将PNG图像编码为Base64字符串。

我想用JavaScript做同样的事情。我知道如何打开文件,但我不知道如何进行编码。我不习惯使用二进制数据。


当前回答

对于更新的浏览器编码Uint8Array到字符串,并解码字符串到Uint8Array。

const base64 = {
    decode: s => Uint8Array.from(atob(s), c => c.charCodeAt(0)),
    encode: b => btoa(String.fromCharCode(...new Uint8Array(b)))
};

对于Node.js,你可以使用以下代码将string、Buffer或Uint8Array编码为string,并从string、Buffer或Uint8Array解码为Buffer。

const base64 = {
    decode: s => Buffer.from(s, 'base64'),
    encode: b => Buffer.from(b).toString('base64')
};

其他回答

基本上,我只是稍微清理了一下原始代码,这样JSLint就不会抱怨太多了,而且我把注释中标记为私有的方法实际上变成了私有的。我还添加了我在自己的项目中需要的两个方法,即decodeToHex和encodeFromHex。

代码:

var Base64 = (function() {
    "use strict";

    var _keyStr = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=";

    var _utf8_encode = function (string) {

        var utftext = "", c, n;

        string = string.replace(/\r\n/g,"\n");

        for (n = 0; n < string.length; n++) {

            c = string.charCodeAt(n);

            if (c < 128) {

                utftext += String.fromCharCode(c);

            } else if((c > 127) && (c < 2048)) {

                utftext += String.fromCharCode((c >> 6) | 192);
                utftext += String.fromCharCode((c & 63) | 128);
            } else {

                utftext += String.fromCharCode((c >> 12) | 224);
                utftext += String.fromCharCode(((c >> 6) & 63) | 128);
                utftext += String.fromCharCode((c & 63) | 128);
            }
        }
        return utftext;
    };

    var _utf8_decode = function (utftext) {
        var string = "", i = 0, c = 0, c1 = 0, c2 = 0;

        while ( i < utftext.length ) {

            c = utftext.charCodeAt(i);

            if (c < 128) {

                string += String.fromCharCode(c);
                i++;

            } else if((c > 191) && (c < 224)) {

                c1 = utftext.charCodeAt(i+1);
                string += String.fromCharCode(((c & 31) << 6) | (c1 & 63));
                i += 2;

            } else {

                c1 = utftext.charCodeAt(i+1);
                c2 = utftext.charCodeAt(i+2);
                string += String.fromCharCode(((c & 15) << 12) | ((c1 & 63) << 6) | (c2 & 63));
                i += 3;
            }
        }
        return string;
    };

    var _hexEncode = function(input) {
        var output = '', i;

        for(i = 0; i < input.length; i++) {
            output += input.charCodeAt(i).toString(16);
        }

        return output;
    };

    var _hexDecode = function(input) {
        var output = '', i;

        if(input.length % 2 > 0) {
            input = '0' + input;
        }

        for(i = 0; i < input.length; i = i + 2) {
            output += String.fromCharCode(parseInt(input.charAt(i) + input.charAt(i + 1), 16));
        }
        return output;
    };

    var encode = function (input) {
        var output = "", chr1, chr2, chr3, enc1, enc2, enc3, enc4, i = 0;

        input = _utf8_encode(input);

        while (i < input.length) {

            chr1 = input.charCodeAt(i++);
            chr2 = input.charCodeAt(i++);
            chr3 = input.charCodeAt(i++);

            enc1 = chr1 >> 2;
            enc2 = ((chr1 & 3) << 4) | (chr2 >> 4);
            enc3 = ((chr2 & 15) << 2) | (chr3 >> 6);
            enc4 = chr3 & 63;

            if (isNaN(chr2)) {
                enc3 = enc4 = 64;
            } else if (isNaN(chr3)) {
                enc4 = 64;
            }

            output += _keyStr.charAt(enc1);
            output += _keyStr.charAt(enc2);
            output += _keyStr.charAt(enc3);
            output += _keyStr.charAt(enc4);
        }
        return output;
    };

    var decode = function (input) {
        var output = "", chr1, chr2, chr3, enc1, enc2, enc3, enc4, i = 0;

        input = input.replace(/[^A-Za-z0-9\+\/\=]/g, "");

        while (i < input.length) {

            enc1 = _keyStr.indexOf(input.charAt(i++));
            enc2 = _keyStr.indexOf(input.charAt(i++));
            enc3 = _keyStr.indexOf(input.charAt(i++));
            enc4 = _keyStr.indexOf(input.charAt(i++));

            chr1 = (enc1 << 2) | (enc2 >> 4);
            chr2 = ((enc2 & 15) << 4) | (enc3 >> 2);
            chr3 = ((enc3 & 3) << 6) | enc4;

            output += String.fromCharCode(chr1);

            if (enc3 !== 64) {
                output += String.fromCharCode(chr2);
            }
            if (enc4 !== 64) {
                output += String.fromCharCode(chr3);
            }

        }

        return _utf8_decode(output);
    };

    var decodeToHex = function(input) {
        return _hexEncode(decode(input));
    };

    var encodeFromHex = function(input) {
        return encode(_hexDecode(input));
    };

    return {
        'encode': encode,
        'decode': decode,
        'decodeToHex': decodeToHex,
        'encodeFromHex': encodeFromHex
    };
}());

如果你使用Node.js,你可以这样做:

let a = Buffer.from('JavaScript').toString('base64');
console.log(a);

let b = Buffer.from(a, 'base64').toString();
console.log(b);

如果你需要编码一个HTML图像对象,你可以写一个简单的函数,像这样:

function getBase64Image(img) {
  var canvas = document.createElement("canvas");
  canvas.width = img.width;
  canvas.height = img.height;
  var ctx = canvas.getContext("2d");
  ctx.drawImage(img, 0, 0);
  var dataURL = canvas.toDataURL("image/png");
  // escape data:image prefix
  return dataURL.replace(/^data:image\/(png|jpg);base64,/, "");
  // or just return dataURL
  // return dataURL
}

通过id获取图像的Base64编码:

function getBase64ImageById(id){
  return getBase64Image(document.getElementById(id));
}

还有更多。

2022年弃用警告更新

我在我的vscode上看到了弃用警告

This function is only provided for compatibility with legacy web platform APIs and should never be used in new code, 
because they use strings to represent binary data and predate the introduction of typed arrays in JavaScript. 
For code running using Node.js APIs, 
converting between base64-encoded strings and binary data should be performed using Buffer.from(str, 'base64') andbuf.toString('base64').

在搜索了一些之后,我发现这个问题说它没有被弃用

https://github.com/microsoft/TypeScript/issues/45566

所以解决web JS弃用警告的方法是使用window.btoa 警告就会消失。

当我使用

btoa("☸☹☺☻☼☾☿"))

我得到:

InvalidCharacterError:要编码的字符串包含Latin1范围之外的字符。

我发现文档,Unicode字符串,提供了一个解决方案如下。

function toBinary(string) { const codeUnits = new Uint16Array(string.length); for (let i = 0; i < codeUnits.length; i++) { codeUnits[i] = string.charCodeAt(i); } return String.fromCharCode(...new Uint8Array(codeUnits.buffer)); } function fromBinary(binary) { const bytes = new Uint8Array(binary.length); for (let i = 0; i < bytes.length; i++) { bytes[i] = binary.charCodeAt(i); } return String.fromCharCode(...new Uint16Array(bytes.buffer)); } const myString = "☸☹☺☻☼☾☿" // console.log(btoa(myString)) // Error InvalidCharacterError: The string to be encoded contains characters outside of the Latin1 range. const converted = toBinary(myString) const encoded = btoa(converted) console.log(encoded) const decoded = atob(encoded) const original = fromBinary(decoded) console.log(original);