Directory.GetFiles("C:\\", "*.*", SearchOption.AllDirectories)

static void Main(string[] args)
        {
            string[] array1 = Directory.GetFiles(@"D:\");
            string[] array2 = System.IO.Directory.GetDirectories(@"D:\");
            Console.WriteLine("--- Files: ---");
            foreach (string name in array1)
            {
                Console.WriteLine(name);
            }
            foreach (string name in array2)
            {
                Console.WriteLine(name);
            }
                  Console.ReadLine();
        }

如果您只需要文件名，并且由于我不喜欢这里的大多数解决方案(特性或可读性方面)，那么这个懒惰的解决方案如何?

private void Foo()
{
  var files = GetAllFiles("pathToADirectory");
  foreach (string file in files)
  {
      // Use can use Path.GetFileName() or similar to extract just the filename if needed
      // You can break early and it won't still browse your whole disk since it's a lazy one
  }
}

/// <exception cref="T:System.IO.DirectoryNotFoundException">The specified path is invalid (for example, it is on an unmapped drive).</exception>
/// <exception cref="T:System.UnauthorizedAccessException">The caller does not have the required permission.</exception>
/// <exception cref="T:System.IO.IOException"><paramref name="path" /> is a file name.-or-A network error has occurred.</exception>
/// <exception cref="T:System.IO.PathTooLongException">The specified path, file name, or both exceed the system-defined maximum length. For example, on Windows-based platforms, paths must be less than 248 characters and file names must be less than 260 characters.</exception>
/// <exception cref="T:System.ArgumentNullException"><paramref name="path" /> is null.</exception>
/// <exception cref="T:System.ArgumentException"><paramref name="path" /> is a zero-length string, contains only white space, or contains one or more invalid characters as defined by <see cref="F:System.IO.Path.InvalidPathChars" />.</exception>
[NotNull]
public static IEnumerable<string> GetAllFiles([NotNull] string directory)
{
  foreach (string file in Directory.GetFiles(directory))
  {
    yield return file; // includes the path
  }

  foreach (string subDir in Directory.GetDirectories(directory))
  {
    foreach (string subFile in GetAllFiles(subDir))
    {
      yield return subFile;
    }
  }
}

private void GetFiles(DirectoryInfo dir, ref List<FileInfo> files)
{
    try
    {
        files.AddRange(dir.GetFiles());
        DirectoryInfo[] dirs = dir.GetDirectories();
        foreach (var d in dirs)
        {
            GetFiles(d, ref files);
        }
    }
    catch (Exception e)
    {

    }
}

我更喜欢使用DirectoryInfo，因为我可以得到FileInfo的，而不仅仅是字符串。

        string baseFolder = @"C:\temp";
        DirectoryInfo di = new DirectoryInfo(baseFolder);

        string searchPattern = "*.xml";

        ICollection<FileInfo> matchingFileInfos = di.GetFiles(searchPattern, SearchOption.AllDirectories)
            .Select(x => x)
            .ToList();

我这样做的情况下，在未来我需要未来过滤..基于FileInfo的属性。

        string baseFolder = @"C:\temp";
        DirectoryInfo di = new DirectoryInfo(baseFolder);

        string searchPattern = "*.xml";

        ICollection<FileInfo> matchingFileInfos = di.GetFiles(searchPattern, SearchOption.AllDirectories)
            .Where(x => x.LastWriteTimeUtc < DateTimeOffset.Now)
            .Select(x => x)
            .ToList();

如果需要，我也可以求助于字符串。(仍然是未来证明过滤器/where-clause子句的东西。

        string baseFolder = @"C:\temp";
        DirectoryInfo di = new DirectoryInfo(baseFolder);

        string searchPattern = "*.xml";

        ICollection<string> matchingFileNames = di.GetFiles(searchPattern, SearchOption.AllDirectories)
            .Select(x => x.FullName)
            .ToList();

请注意，如果您想通过扩展文件，“.”是一个有效的搜索模式。

一个非常简单的解决方案，返回一个文件列表。

    public static List<string> AllFilesInFolder(string folder)
    {
        var result = new List<string>();

        foreach (string f in Directory.GetFiles(folder))
        {
            result.Add(f);
        }

        foreach (string d in Directory.GetDirectories(folder))
        {
            result.AddRange(AllFilesInFolder(d));
        }

        return result;
    }